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    <title>수악중독</title>
    <link>https://mathjk.tistory.com/</link>
    <description>수학의 즐거움에 중독되다!
고등학교 수학 개념 및 문제 풀이</description>
    <language>ko</language>
    <pubDate>Tue, 10 Mar 2026 00:07:06 +0900</pubDate>
    <generator>TISTORY</generator>
    <ttl>100</ttl>
    <managingEditor>수악중독</managingEditor>
    <image>
      <title>수악중독</title>
      <url>https://tistory1.daumcdn.net/tistory/23799/attach/1bac5a872a5043a59cd49c144886add0</url>
      <link>https://mathjk.tistory.com</link>
    </image>
    <item>
      <title>극대 극소와 미분_난이도 중하 (2025년 11월 수능 9번)</title>
      <link>https://mathjk.tistory.com/6806</link>
      <description>&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;양수 $a$에 대하여 함수 $f(x)$를&amp;nbsp;&amp;nbsp;$$f(x)=x^3+3ax^2-9a^2x+4$$라 하자. 직선 $y=5$이 곡선 $y=f(x)$에 접할 때, $f(2)$의 값은?&amp;nbsp;&lt;br /&gt;&lt;br /&gt;① $11$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;② $12$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;③ $13$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;④ $14$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;⑤ $15$&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;div data-ke-type=&quot;moreLess&quot; data-text-more=&quot;풀이보기&quot; data-text-less=&quot;풀이닫기&quot;&gt;&lt;a class=&quot;btn-toggle-moreless&quot;&gt;더보기&lt;/a&gt;
&lt;div class=&quot;moreless-content&quot;&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&lt;span style=&quot;color: #ee2323;&quot;&gt;&lt;b&gt;정답 ④&lt;/b&gt;&lt;/span&gt;&lt;/p&gt;
&lt;figure class=&quot;imageblock alignCenter&quot; data-ke-mobileStyle=&quot;widthOrigin&quot; data-filename=&quot;수능 9번.jpeg&quot; data-origin-width=&quot;1668&quot; data-origin-height=&quot;1021&quot;&gt;&lt;span data-url=&quot;https://blog.kakaocdn.net/dn/bVi3oH/dJMcaaRc93B/h8s5Aky1gkZLB83kqH2Xik/img.jpg&quot; data-phocus=&quot;https://blog.kakaocdn.net/dn/bVi3oH/dJMcaaRc93B/h8s5Aky1gkZLB83kqH2Xik/img.jpg&quot;&gt;&lt;img src=&quot;https://blog.kakaocdn.net/dn/bVi3oH/dJMcaaRc93B/h8s5Aky1gkZLB83kqH2Xik/img.jpg&quot; srcset=&quot;https://img1.daumcdn.net/thumb/R1280x0/?scode=mtistory2&amp;fname=https%3A%2F%2Fblog.kakaocdn.net%2Fdn%2FbVi3oH%2FdJMcaaRc93B%2Fh8s5Aky1gkZLB83kqH2Xik%2Fimg.jpg&quot; onerror=&quot;this.onerror=null; this.src='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png'; this.srcset='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png';&quot; loading=&quot;lazy&quot; width=&quot;1668&quot; height=&quot;1021&quot; data-filename=&quot;수능 9번.jpeg&quot; data-origin-width=&quot;1668&quot; data-origin-height=&quot;1021&quot;/&gt;&lt;/span&gt;&lt;/figure&gt;
&lt;/div&gt;
&lt;/div&gt;</description>
      <category>수학2 - 문제풀이/미분</category>
      <author>수악중독</author>
      <guid isPermaLink="true">https://mathjk.tistory.com/6806</guid>
      <comments>https://mathjk.tistory.com/6806#entry6806comment</comments>
      <pubDate>Tue, 18 Nov 2025 07:25:38 +0900</pubDate>
    </item>
    <item>
      <title>지수함수의 그래프_난이도 하 (2025년 11월 수능 10번)</title>
      <link>https://mathjk.tistory.com/6805</link>
      <description>&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;상수 $a$ $(a &amp;gt; 1)$에 대하여 곡선 $y = a^x - 2$ 위의 점 중 제$1$사분면에 있는 점 $\mathrm{A}$를 지나고 $y$축에 평행한 직선이 $x$축과 만나는 점을 $\mathrm{B}$, 곡선 $y = a^x - 2$의 점근선과 만나는 점을 $\mathrm{C}$라 하자. $\overline{\mathrm{AB}} = \overline{\mathrm{BC}}$이고, 삼각형 $\mathrm{AOC}$의 넓이가 $8$일 때, $a \times \overline{\mathrm{OB}}$의 값은? (단, $\mathrm{O}$는 원점이다.)&amp;nbsp;&lt;br /&gt;&lt;br /&gt;① $2^{\frac{13}{6}}$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;② $2^{\frac{7}{3}}$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;③ $2^{\frac{5}{2}}$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;④ $2^{\frac{8}{3}}$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;⑤ $2^{\frac{17}{6}}$&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;div data-ke-type=&quot;moreLess&quot; data-text-more=&quot;풀이보기&quot; data-text-less=&quot;풀이닫기&quot;&gt;&lt;a class=&quot;btn-toggle-moreless&quot;&gt;더보기&lt;/a&gt;
&lt;div class=&quot;moreless-content&quot;&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&lt;span style=&quot;color: #ee2323;&quot;&gt;&lt;b&gt;정답 ③&lt;/b&gt;&lt;/span&gt;&lt;/p&gt;
&lt;figure class=&quot;imageblock alignCenter&quot; data-ke-mobileStyle=&quot;widthOrigin&quot; data-filename=&quot;수능 10번.jpeg&quot; data-origin-width=&quot;1668&quot; data-origin-height=&quot;978&quot;&gt;&lt;span data-url=&quot;https://blog.kakaocdn.net/dn/cQBT8O/dJMcabP6khy/c4iespMzeRZ2Hko1Tiqrl0/img.jpg&quot; data-phocus=&quot;https://blog.kakaocdn.net/dn/cQBT8O/dJMcabP6khy/c4iespMzeRZ2Hko1Tiqrl0/img.jpg&quot;&gt;&lt;img src=&quot;https://blog.kakaocdn.net/dn/cQBT8O/dJMcabP6khy/c4iespMzeRZ2Hko1Tiqrl0/img.jpg&quot; srcset=&quot;https://img1.daumcdn.net/thumb/R1280x0/?scode=mtistory2&amp;fname=https%3A%2F%2Fblog.kakaocdn.net%2Fdn%2FcQBT8O%2FdJMcabP6khy%2Fc4iespMzeRZ2Hko1Tiqrl0%2Fimg.jpg&quot; onerror=&quot;this.onerror=null; this.src='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png'; this.srcset='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png';&quot; loading=&quot;lazy&quot; width=&quot;1668&quot; height=&quot;978&quot; data-filename=&quot;수능 10번.jpeg&quot; data-origin-width=&quot;1668&quot; data-origin-height=&quot;978&quot;/&gt;&lt;/span&gt;&lt;/figure&gt;
&lt;/div&gt;
&lt;/div&gt;</description>
      <category>수학1- 문제풀이/지수함수와 로그함수</category>
      <author>수악중독</author>
      <guid isPermaLink="true">https://mathjk.tistory.com/6805</guid>
      <comments>https://mathjk.tistory.com/6805#entry6805comment</comments>
      <pubDate>Sun, 16 Nov 2025 01:08:13 +0900</pubDate>
    </item>
    <item>
      <title>속도, 거리와 적분_난이도 하 (2025년 11월 수능 11번)</title>
      <link>https://mathjk.tistory.com/6804</link>
      <description>&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;시각 $t=0$일 때 원점을 출발하여 수직선 위를 움직이는 점 $\mathrm{P}$가 있다. 실수 $k$에 대하여 시각이 $t$ $(t \ge 0)$일 때 점 $\mathrm{P}$의 속도 $v(t)$가 $$v(t) = t^2 - kt + 4$$이다. ⟨보기⟩에서 옳은 것만을 있는 대로 고른 것은?&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;div class=&quot;txc-textbox&quot; style=&quot;background-color: #fefeb8; padding: 10px; border: 1px solid #fefeb8;&quot;&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;ㄱ. $k=0$이면, 시각 $t=1$일 때 점 $\mathrm{P}$의 위치는 $\dfrac{13}{3}$이다.&amp;nbsp;&amp;nbsp;&lt;br /&gt;ㄴ. $k=3$이면, 출발한 후 점 $\mathrm{P}$의 운동 방향이 한 번 바뀐다.&amp;nbsp;&amp;nbsp;&lt;br /&gt;ㄷ. $k=5$이면, 시각 $t=0$에서 $t=2$까지 점 $\mathrm{P}$가 움직인 거리는 $3$이다.&lt;/p&gt;
&lt;/div&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&lt;br /&gt;①&amp;nbsp;ㄱ&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;②&amp;nbsp;ㄱ,&amp;nbsp;ㄴ&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;③&amp;nbsp;ㄱ,&amp;nbsp;ㄷ&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;④&amp;nbsp;ㄴ,&amp;nbsp;ㄷ&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;⑤&amp;nbsp;ㄱ,&amp;nbsp;ㄴ,&amp;nbsp;ㄷ&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;div data-ke-type=&quot;moreLess&quot; data-text-more=&quot;풀이보기&quot; data-text-less=&quot;풀이닫기&quot;&gt;&lt;a class=&quot;btn-toggle-moreless&quot;&gt;더보기&lt;/a&gt;
&lt;div class=&quot;moreless-content&quot;&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&lt;span style=&quot;color: #ee2323;&quot;&gt;&lt;b&gt;정답 ③&lt;/b&gt;&lt;/span&gt;&lt;/p&gt;
&lt;figure class=&quot;imageblock alignCenter&quot; data-ke-mobileStyle=&quot;widthOrigin&quot; data-filename=&quot;수능 11번.jpeg&quot; data-origin-width=&quot;1668&quot; data-origin-height=&quot;918&quot;&gt;&lt;span data-url=&quot;https://blog.kakaocdn.net/dn/ck88qU/dJMcaajmb9O/AHcBXcCod86CBVc8Z7Hg51/img.jpg&quot; data-phocus=&quot;https://blog.kakaocdn.net/dn/ck88qU/dJMcaajmb9O/AHcBXcCod86CBVc8Z7Hg51/img.jpg&quot;&gt;&lt;img src=&quot;https://blog.kakaocdn.net/dn/ck88qU/dJMcaajmb9O/AHcBXcCod86CBVc8Z7Hg51/img.jpg&quot; srcset=&quot;https://img1.daumcdn.net/thumb/R1280x0/?scode=mtistory2&amp;fname=https%3A%2F%2Fblog.kakaocdn.net%2Fdn%2Fck88qU%2FdJMcaajmb9O%2FAHcBXcCod86CBVc8Z7Hg51%2Fimg.jpg&quot; onerror=&quot;this.onerror=null; this.src='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png'; this.srcset='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png';&quot; loading=&quot;lazy&quot; width=&quot;1668&quot; height=&quot;918&quot; data-filename=&quot;수능 11번.jpeg&quot; data-origin-width=&quot;1668&quot; data-origin-height=&quot;918&quot;/&gt;&lt;/span&gt;&lt;/figure&gt;
&lt;/div&gt;
&lt;/div&gt;</description>
      <category>수학2 - 문제풀이/적분</category>
      <author>수악중독</author>
      <guid isPermaLink="true">https://mathjk.tistory.com/6804</guid>
      <comments>https://mathjk.tistory.com/6804#entry6804comment</comments>
      <pubDate>Sun, 16 Nov 2025 01:03:16 +0900</pubDate>
    </item>
    <item>
      <title>등비수열의 일반항_난이도 하 (2025년 11월 수능 12번)</title>
      <link>https://mathjk.tistory.com/6803</link>
      <description>&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;등비수열 $\{a_n\}$이&amp;nbsp; $$2(a_1 + a_4 + a_7) = a_4 + a_7 + a_{10} = 6$$을 만족시킬 때, $a_{10}$의 값은?&amp;nbsp;&lt;br /&gt;&lt;br /&gt;① $\dfrac{22}{7}$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;② $\dfrac{24}{7}$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;③ $\dfrac{26}{7}$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;④ $\dfrac{30}{7}$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;⑤ $\dfrac{32}{7}$&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;div data-ke-type=&quot;moreLess&quot; data-text-more=&quot;풀이보기&quot; data-text-less=&quot;풀이닫기&quot;&gt;&lt;a class=&quot;btn-toggle-moreless&quot;&gt;더보기&lt;/a&gt;
&lt;div class=&quot;moreless-content&quot;&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&lt;span style=&quot;color: #ee2323;&quot;&gt;&lt;b&gt;정답 ②&lt;/b&gt;&lt;/span&gt;&lt;/p&gt;
&lt;figure class=&quot;imageblock alignCenter&quot; data-ke-mobileStyle=&quot;widthOrigin&quot; data-filename=&quot;수능 12번.jpeg&quot; data-origin-width=&quot;1668&quot; data-origin-height=&quot;569&quot;&gt;&lt;span data-url=&quot;https://blog.kakaocdn.net/dn/tGJHW/dJMcaf52ola/YlBZuaTrw6AmVlgBb6OuZ1/img.jpg&quot; data-phocus=&quot;https://blog.kakaocdn.net/dn/tGJHW/dJMcaf52ola/YlBZuaTrw6AmVlgBb6OuZ1/img.jpg&quot;&gt;&lt;img src=&quot;https://blog.kakaocdn.net/dn/tGJHW/dJMcaf52ola/YlBZuaTrw6AmVlgBb6OuZ1/img.jpg&quot; srcset=&quot;https://img1.daumcdn.net/thumb/R1280x0/?scode=mtistory2&amp;fname=https%3A%2F%2Fblog.kakaocdn.net%2Fdn%2FtGJHW%2FdJMcaf52ola%2FYlBZuaTrw6AmVlgBb6OuZ1%2Fimg.jpg&quot; onerror=&quot;this.onerror=null; this.src='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png'; this.srcset='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png';&quot; loading=&quot;lazy&quot; width=&quot;1668&quot; height=&quot;569&quot; data-filename=&quot;수능 12번.jpeg&quot; data-origin-width=&quot;1668&quot; data-origin-height=&quot;569&quot;/&gt;&lt;/span&gt;&lt;/figure&gt;
&lt;/div&gt;
&lt;/div&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;</description>
      <category>수학1- 문제풀이/수열</category>
      <author>수악중독</author>
      <guid isPermaLink="true">https://mathjk.tistory.com/6803</guid>
      <comments>https://mathjk.tistory.com/6803#entry6803comment</comments>
      <pubDate>Sun, 16 Nov 2025 00:59:58 +0900</pubDate>
    </item>
    <item>
      <title>접선의 방정식_곡선 위의 한 점이 주어지는 경우_난이도 중하 (2025년 11월 수능 13번)</title>
      <link>https://mathjk.tistory.com/6802</link>
      <description>&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;함수 $f(x) = x^2 - 4x - 3$에 대하여 곡선 $y = f(x)$ 위의 점 $(1, \;-6)$에서의 접선을 $l$이라 하고, 함수 $g(x) = \left (x^3 - 2x \right )f(x)$에 대하여 곡선 $y=g(x)$ 위의 점 $(1, \;6)$에서의 접선을 $m$이라 하자. 두 직선 $l, \;m$과 $y$축으로 둘러싸인 도형의 넓이는?&amp;nbsp;&lt;br /&gt;&lt;br /&gt;① $21$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;② $28$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;③ $35$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;④ $42$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;⑤ $49$&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;div data-ke-type=&quot;moreLess&quot; data-text-more=&quot;풀이보기&quot; data-text-less=&quot;풀이닫기&quot;&gt;&lt;a class=&quot;btn-toggle-moreless&quot;&gt;더보기&lt;/a&gt;
&lt;div class=&quot;moreless-content&quot;&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&lt;span style=&quot;color: #ee2323;&quot;&gt;&lt;b&gt;정답 ⑤&lt;/b&gt;&lt;/span&gt;&lt;/p&gt;
&lt;figure class=&quot;imageblock alignCenter&quot; data-ke-mobileStyle=&quot;widthOrigin&quot; data-filename=&quot;수능 13번.jpeg&quot; data-origin-width=&quot;1482&quot; data-origin-height=&quot;1450&quot;&gt;&lt;span data-url=&quot;https://blog.kakaocdn.net/dn/mZsdw/dJMcagDSkgF/c8Q9kGvjUzllAOafCpXbi0/img.jpg&quot; data-phocus=&quot;https://blog.kakaocdn.net/dn/mZsdw/dJMcagDSkgF/c8Q9kGvjUzllAOafCpXbi0/img.jpg&quot;&gt;&lt;img src=&quot;https://blog.kakaocdn.net/dn/mZsdw/dJMcagDSkgF/c8Q9kGvjUzllAOafCpXbi0/img.jpg&quot; srcset=&quot;https://img1.daumcdn.net/thumb/R1280x0/?scode=mtistory2&amp;fname=https%3A%2F%2Fblog.kakaocdn.net%2Fdn%2FmZsdw%2FdJMcagDSkgF%2Fc8Q9kGvjUzllAOafCpXbi0%2Fimg.jpg&quot; onerror=&quot;this.onerror=null; this.src='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png'; this.srcset='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png';&quot; loading=&quot;lazy&quot; width=&quot;1482&quot; height=&quot;1450&quot; data-filename=&quot;수능 13번.jpeg&quot; data-origin-width=&quot;1482&quot; data-origin-height=&quot;1450&quot;/&gt;&lt;/span&gt;&lt;/figure&gt;
&lt;/div&gt;
&lt;/div&gt;</description>
      <category>수학2 - 문제풀이/미분</category>
      <author>수악중독</author>
      <guid isPermaLink="true">https://mathjk.tistory.com/6802</guid>
      <comments>https://mathjk.tistory.com/6802#entry6802comment</comments>
      <pubDate>Sun, 16 Nov 2025 00:57:39 +0900</pubDate>
    </item>
    <item>
      <title>사인법칙&amp;amp;코사인법칙_난이도 중 (2025년 11월 수능 14번)</title>
      <link>https://mathjk.tistory.com/6801</link>
      <description>&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;그림과 같이 $\overline{\mathrm{AB}}=3$, $\overline{\mathrm{BC}}=4$이고 $\angle \mathrm{B} = \dfrac{\pi}{2}$인 직각삼각형 $\mathrm{ABC}$가 있다. 선분 $\mathrm{AB}$를 $2:1$로 내분하는 점을 $\mathrm{D}$, 점 $\mathrm{A}$를 중심으로 하고 반지름의 길이가 $\overline{\mathrm{AD}}$인 원이 선분 $\mathrm{AC}$와 만나는 점을 $\mathrm{E}$, 직선 $\mathrm{AB}$가 이 원과 만나는 점 중 $\mathrm{D}$가 아닌 점을 $\mathrm{F}$라 하고, 호 $\mathrm{EF}$ 위의 점 $\mathrm{G}$를 $\overline{\mathrm{CG}} = 2\sqrt{6}$이 되도록 잡는다. 세 점 $\mathrm{C,\; E, \; G}$를 지나는 원 위의 점 $\mathrm{H}$가 $\angle \mathrm{HCG}=\angle \mathrm{BAC}$를만족시킬 때, 선분 $\overline{\mathrm{GH}}$의 길이는?&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;&lt;figure class=&quot;imageblock alignCenter&quot; data-ke-mobileStyle=&quot;widthOrigin&quot; data-filename=&quot;Screenshot 2025-11-15 at 10.50.40.png&quot; data-origin-width=&quot;1072&quot; data-origin-height=&quot;1516&quot;&gt;&lt;span data-url=&quot;https://blog.kakaocdn.net/dn/bhrfwj/dJMcacuHU25/d96kU1uiMlCIME1AMugyR0/img.png&quot; data-phocus=&quot;https://blog.kakaocdn.net/dn/bhrfwj/dJMcacuHU25/d96kU1uiMlCIME1AMugyR0/img.png&quot;&gt;&lt;img src=&quot;https://blog.kakaocdn.net/dn/bhrfwj/dJMcacuHU25/d96kU1uiMlCIME1AMugyR0/img.png&quot; srcset=&quot;https://img1.daumcdn.net/thumb/R1280x0/?scode=mtistory2&amp;fname=https%3A%2F%2Fblog.kakaocdn.net%2Fdn%2Fbhrfwj%2FdJMcacuHU25%2Fd96kU1uiMlCIME1AMugyR0%2Fimg.png&quot; onerror=&quot;this.onerror=null; this.src='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png'; this.srcset='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png';&quot; loading=&quot;lazy&quot; width=&quot;346&quot; height=&quot;489&quot; data-filename=&quot;Screenshot 2025-11-15 at 10.50.40.png&quot; data-origin-width=&quot;1072&quot; data-origin-height=&quot;1516&quot;/&gt;&lt;/span&gt;&lt;/figure&gt;
&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&lt;br /&gt;① $\dfrac{6\sqrt{15}}{8}$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;② $\dfrac{38\sqrt{10}}{25}$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;③ $\dfrac{14\sqrt{3}}{5}$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;④ $\dfrac{32\sqrt{15}}{25}$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;⑤ $\dfrac{8\sqrt{10}}{5}$&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;div data-ke-type=&quot;moreLess&quot; data-text-more=&quot;풀이보기&quot; data-text-less=&quot;풀이닫기&quot;&gt;&lt;a class=&quot;btn-toggle-moreless&quot;&gt;더보기&lt;/a&gt;
&lt;div class=&quot;moreless-content&quot;&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&lt;span style=&quot;color: #ee2323;&quot;&gt;&lt;b&gt;정답 ④&lt;/b&gt;&lt;/span&gt;&lt;/p&gt;
&lt;figure class=&quot;imageblock alignCenter&quot; data-ke-mobileStyle=&quot;widthOrigin&quot; data-filename=&quot;수능 14번.jpeg&quot; data-origin-width=&quot;1668&quot; data-origin-height=&quot;1438&quot;&gt;&lt;span data-url=&quot;https://blog.kakaocdn.net/dn/bEijY5/dJMcagjzxgh/e3f1PXvHNQnGGWGhxjjLDk/img.jpg&quot; data-phocus=&quot;https://blog.kakaocdn.net/dn/bEijY5/dJMcagjzxgh/e3f1PXvHNQnGGWGhxjjLDk/img.jpg&quot;&gt;&lt;img src=&quot;https://blog.kakaocdn.net/dn/bEijY5/dJMcagjzxgh/e3f1PXvHNQnGGWGhxjjLDk/img.jpg&quot; srcset=&quot;https://img1.daumcdn.net/thumb/R1280x0/?scode=mtistory2&amp;fname=https%3A%2F%2Fblog.kakaocdn.net%2Fdn%2FbEijY5%2FdJMcagjzxgh%2Fe3f1PXvHNQnGGWGhxjjLDk%2Fimg.jpg&quot; onerror=&quot;this.onerror=null; this.src='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png'; this.srcset='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png';&quot; loading=&quot;lazy&quot; width=&quot;1668&quot; height=&quot;1438&quot; data-filename=&quot;수능 14번.jpeg&quot; data-origin-width=&quot;1668&quot; data-origin-height=&quot;1438&quot;/&gt;&lt;/span&gt;&lt;/figure&gt;
&lt;/div&gt;
&lt;/div&gt;</description>
      <category>수학1- 문제풀이/삼각함수</category>
      <author>수악중독</author>
      <guid isPermaLink="true">https://mathjk.tistory.com/6801</guid>
      <comments>https://mathjk.tistory.com/6801#entry6801comment</comments>
      <pubDate>Sun, 16 Nov 2025 00:54:31 +0900</pubDate>
    </item>
    <item>
      <title>극대 극소와 미분_난이도 중상 (2025년 11월 수능 15번)</title>
      <link>https://mathjk.tistory.com/6800</link>
      <description>&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;함수&amp;nbsp; $f(x)$가 $$f(x)=\begin{cases} -x^2 &amp;amp; (x&amp;lt;0) \\ x^2-x &amp;amp; (x \ge 0)\end{cases}$$이고, 양수 $a$에 대하여 함수 $g(x)$를&amp;nbsp; $$g(x)=\begin{cases}ax+a &amp;amp; (x&amp;lt;-1) \\ 0 &amp;amp; (-1 \le x&amp;lt;1) \\ ax-a &amp;amp; (x \ge 1)\end{cases}$$이라 하자. 함수 $h(x) = \displaystyle \int_0^x (g(t)-f(t))\,dt$가 오직 하나의 극값을 갖도록 하는 $a$의 최댓값을 $k$라 하자. $a=k$일 때, $k+h(3)$의 값은?&lt;br /&gt;&lt;br /&gt;① $\dfrac{9}{2}$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;② $\dfrac{11}{2}$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;③ $\dfrac{13}{2}$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;④ $\dfrac{15}{2}$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;⑤ $\dfrac{17}{2}$&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;div data-ke-type=&quot;moreLess&quot; data-text-more=&quot;풀이보기&quot; data-text-less=&quot;풀이닫기&quot;&gt;&lt;a class=&quot;btn-toggle-moreless&quot;&gt;더보기&lt;/a&gt;
&lt;div class=&quot;moreless-content&quot;&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&lt;span style=&quot;color: #ee2323;&quot;&gt;&lt;b&gt;정답 ④&lt;/b&gt;&lt;/span&gt;&lt;/p&gt;
&lt;figure class=&quot;imageblock alignCenter&quot; data-ke-mobileStyle=&quot;widthOrigin&quot; data-filename=&quot;수능 15번.jpeg&quot; data-origin-width=&quot;1668&quot; data-origin-height=&quot;1901&quot;&gt;&lt;span data-url=&quot;https://blog.kakaocdn.net/dn/cTFpc8/dJMcabo1rQR/BjvNx6zDZfApjbWtK5auf0/img.jpg&quot; data-phocus=&quot;https://blog.kakaocdn.net/dn/cTFpc8/dJMcabo1rQR/BjvNx6zDZfApjbWtK5auf0/img.jpg&quot;&gt;&lt;img src=&quot;https://blog.kakaocdn.net/dn/cTFpc8/dJMcabo1rQR/BjvNx6zDZfApjbWtK5auf0/img.jpg&quot; srcset=&quot;https://img1.daumcdn.net/thumb/R1280x0/?scode=mtistory2&amp;fname=https%3A%2F%2Fblog.kakaocdn.net%2Fdn%2FcTFpc8%2FdJMcabo1rQR%2FBjvNx6zDZfApjbWtK5auf0%2Fimg.jpg&quot; onerror=&quot;this.onerror=null; this.src='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png'; this.srcset='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png';&quot; loading=&quot;lazy&quot; width=&quot;1668&quot; height=&quot;1901&quot; data-filename=&quot;수능 15번.jpeg&quot; data-origin-width=&quot;1668&quot; data-origin-height=&quot;1901&quot;/&gt;&lt;/span&gt;&lt;/figure&gt;
&lt;/div&gt;
&lt;/div&gt;</description>
      <category>수학2 - 문제풀이/미분</category>
      <author>수악중독</author>
      <guid isPermaLink="true">https://mathjk.tistory.com/6800</guid>
      <comments>https://mathjk.tistory.com/6800#entry6800comment</comments>
      <pubDate>Sat, 15 Nov 2025 00:35:47 +0900</pubDate>
    </item>
    <item>
      <title>여러 가지 수열의 합_난이도 중 (2025년 11월 수능 20번)</title>
      <link>https://mathjk.tistory.com/6799</link>
      <description>&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;수열 $\{a_n\}$ 이 다음 조건을 만족시킨다.&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;div class=&quot;txc-textbox&quot; style=&quot;background-color: #dbe8fb; padding: 10px; border: 1px solid #dbe8fb;&quot;&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;-&amp;nbsp;$a_1&amp;nbsp;=&amp;nbsp;7$&lt;br /&gt;- $2$ 이상의 자연수 $n$ 에 대하여 $$\displaystyle \sum_{k=1}^n a_k = \frac{2}{3} a_n + \frac{1}{6} n^2 - \frac{1}{6} n + 10$$이다.&lt;/p&gt;
&lt;/div&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;다음은 $\displaystyle \sum_{k=1}^{12} a_k + \sum_{k=1}^5 a_{2k+1}$ 의 값을 구하는 과정이다.&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;div class=&quot;txc-textbox&quot; style=&quot;background-color: #e7fdb5; padding: 10px; border: 1px solid #e7fdb5;&quot;&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;$2$ 이상의 자연수 $n$ 에 대하여 $\displaystyle a_{n+1} = \sum_{k=1}^{n+1} a_k - \sum_{k=1}^n a_k$ 이므로$$a_{n+1} = \frac{2}{3} (a_{n+1} - a_n) + \boxed{\text{ (가) }}$$이고, 이 식을 정리하면$$2a_n + a_{n+1} = 3 \times \boxed{\text{ (가) }} \quad \quad \cdots \cdots ㉠$$이다.$$\displaystyle \sum_{k=1}^n a_k = \frac{2}{3} a_n + \frac{1}{6} n^2 - \frac{1}{6} n + 10 \quad (n \ge 2)$$에서 양변에 $n = 2$ 를 대입하면$$a_2 = \boxed{\text{ (나) }} \quad \quad \cdots \cdots ㉡$$이다. ㉠과 ㉡에 의하여 $$\begin{aligned}\displaystyle \sum_{k=1}^{12} a_k + \sum_{k=1}^5 a_{2k+1} &amp;amp;= a_1 + a_2 + \sum_{k=1}^5 (2a_{2k+1} + a_{2k+2})&amp;nbsp;&amp;nbsp;\\[8pt] &amp;amp;=\boxed{\text{ (다) }}\end{aligned}$$ 이다.&lt;/p&gt;
&lt;/div&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;위의 (가)에 알맞은 식을 $f(n)$이라 하고, (나), (다)에 알맞은 수를 각각 $p, \;q$라 할 때, $\dfrac{p \times q}{f(12)}$ 의 값을 구하시오.&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;div data-ke-type=&quot;moreLess&quot; data-text-more=&quot;풀이보기&quot; data-text-less=&quot;풀이닫기&quot;&gt;&lt;a class=&quot;btn-toggle-moreless&quot;&gt;더보기&lt;/a&gt;
&lt;div class=&quot;moreless-content&quot;&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&lt;span style=&quot;color: #ee2323;&quot;&gt;&lt;b&gt;정답 $130$&lt;/b&gt;&lt;/span&gt;&lt;/p&gt;
&lt;figure class=&quot;imageblock alignCenter&quot; data-ke-mobileStyle=&quot;widthOrigin&quot; data-filename=&quot;수능 20번.jpeg&quot; data-origin-width=&quot;1668&quot; data-origin-height=&quot;1977&quot;&gt;&lt;span data-url=&quot;https://blog.kakaocdn.net/dn/dV189K/dJMcaiaB2WK/noQo9q8q1yJIYBPkli324k/img.jpg&quot; data-phocus=&quot;https://blog.kakaocdn.net/dn/dV189K/dJMcaiaB2WK/noQo9q8q1yJIYBPkli324k/img.jpg&quot;&gt;&lt;img src=&quot;https://blog.kakaocdn.net/dn/dV189K/dJMcaiaB2WK/noQo9q8q1yJIYBPkli324k/img.jpg&quot; srcset=&quot;https://img1.daumcdn.net/thumb/R1280x0/?scode=mtistory2&amp;fname=https%3A%2F%2Fblog.kakaocdn.net%2Fdn%2FdV189K%2FdJMcaiaB2WK%2FnoQo9q8q1yJIYBPkli324k%2Fimg.jpg&quot; onerror=&quot;this.onerror=null; this.src='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png'; this.srcset='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png';&quot; loading=&quot;lazy&quot; width=&quot;1668&quot; height=&quot;1977&quot; data-filename=&quot;수능 20번.jpeg&quot; data-origin-width=&quot;1668&quot; data-origin-height=&quot;1977&quot;/&gt;&lt;/span&gt;&lt;/figure&gt;
&lt;/div&gt;
&lt;/div&gt;</description>
      <category>수학1- 문제풀이/수열</category>
      <author>수악중독</author>
      <guid isPermaLink="true">https://mathjk.tistory.com/6799</guid>
      <comments>https://mathjk.tistory.com/6799#entry6799comment</comments>
      <pubDate>Sat, 15 Nov 2025 00:26:04 +0900</pubDate>
    </item>
    <item>
      <title>0/0꼴의 극한&amp;amp;좌극한과 우극한&amp;amp;삼차함수 그래프 개형_난이도 상 (2025년 11월 수능 21번)</title>
      <link>https://mathjk.tistory.com/6798</link>
      <description>&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;최고차항의 계수가 양수인 삼차함수 $f(x)$와 실수 $t$에 대하여 함수 $$g(x)=\begin{cases} -f(x) &amp;amp; (x&amp;lt;t) \\ f(x) &amp;amp; (x \ge t) \end{cases}$$는 실수 전체의 집합에서 연속이고 다음 조건을 만족시킨다.&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;div class=&quot;txc-textbox&quot; style=&quot;background-color: #dbe8fb; padding: 10px; border: 1px solid #dbe8fb;&quot;&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;(가) 모든 실수 $a$에 대하여 $\lim \limits_{x \to a} \dfrac{g(x)}{x(x-2)}$의 값이 존재한다.&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;(나) $\lim \limits_{x \to m+} \dfrac{g(x)}{x(x-2)}$의 값이 음수가 되도록 하는 자연수 $m$의 집합은 $\left \{g(-1), \; -\dfrac{7}{2}g(1) \right \}$이다.&lt;/p&gt;
&lt;/div&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;$g(-5)$의 값을 구하시오., (단, $g(-1) \ne -\dfrac{7}{2}g(1)$)&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;div data-ke-type=&quot;moreLess&quot; data-text-more=&quot;풀이보기&quot; data-text-less=&quot;풀이닫기&quot;&gt;&lt;a class=&quot;btn-toggle-moreless&quot;&gt;더보기&lt;/a&gt;
&lt;div class=&quot;moreless-content&quot;&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&lt;span style=&quot;color: #ee2323;&quot;&gt;&lt;b&gt;정답 $65$&lt;/b&gt;&lt;/span&gt;&lt;/p&gt;
&lt;figure class=&quot;imageblock alignCenter&quot; data-ke-mobileStyle=&quot;widthOrigin&quot; data-filename=&quot;수능 21번.jpeg&quot; data-origin-width=&quot;1668&quot; data-origin-height=&quot;1853&quot;&gt;&lt;span data-url=&quot;https://blog.kakaocdn.net/dn/5HAD6/dJMcagqkDTp/A64gYYE2kpoHS9SOgd2OOk/img.jpg&quot; data-phocus=&quot;https://blog.kakaocdn.net/dn/5HAD6/dJMcagqkDTp/A64gYYE2kpoHS9SOgd2OOk/img.jpg&quot;&gt;&lt;img src=&quot;https://blog.kakaocdn.net/dn/5HAD6/dJMcagqkDTp/A64gYYE2kpoHS9SOgd2OOk/img.jpg&quot; srcset=&quot;https://img1.daumcdn.net/thumb/R1280x0/?scode=mtistory2&amp;fname=https%3A%2F%2Fblog.kakaocdn.net%2Fdn%2F5HAD6%2FdJMcagqkDTp%2FA64gYYE2kpoHS9SOgd2OOk%2Fimg.jpg&quot; onerror=&quot;this.onerror=null; this.src='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png'; this.srcset='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png';&quot; loading=&quot;lazy&quot; width=&quot;1668&quot; height=&quot;1853&quot; data-filename=&quot;수능 21번.jpeg&quot; data-origin-width=&quot;1668&quot; data-origin-height=&quot;1853&quot;/&gt;&lt;/span&gt;&lt;/figure&gt;
&lt;/div&gt;
&lt;/div&gt;</description>
      <category>수학2 - 문제풀이/함수의 극한과 연속</category>
      <author>수악중독</author>
      <guid isPermaLink="true">https://mathjk.tistory.com/6798</guid>
      <comments>https://mathjk.tistory.com/6798#entry6798comment</comments>
      <pubDate>Sat, 15 Nov 2025 00:15:37 +0900</pubDate>
    </item>
    <item>
      <title>지수함수와 로그함수의 그래프&amp;amp;역함수 관계_난이도 상 (2025녀 11월 수능 22번)</title>
      <link>https://mathjk.tistory.com/6797</link>
      <description>&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;곡선 $y=\log_{16}(8x+2)$ 위의 점 $\mathrm{A}(a, \; b)$와 곡선 $y=4^{x-1}-\dfrac{1}{2}$ 위의 점 $\mathrm{B}$가 제$1$사분면에 있다. 점 $\mathrm{A}$를 직선 $y=x$에 대하여 대칭이동한 점이 직선 $\mathrm{OB}$ 위에 있고 선분 $\mathrm{AB}$의 중점의 좌표가 $\left (\dfrac{77}{8}, \; \dfrac{133}{8} \right )$일 때, $a \times b = \dfrac{q}{p}$이다. $p+q$의 값을 구하시오. (단, $\mathrm{O}$는 원점이고, $p$ 와 $q$는 서로소인 자연수이다.)&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;div data-ke-type=&quot;moreLess&quot; data-text-more=&quot;풀이보기&quot; data-text-less=&quot;풀이닫기&quot;&gt;&lt;a class=&quot;btn-toggle-moreless&quot;&gt;더보기&lt;/a&gt;
&lt;div class=&quot;moreless-content&quot;&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&lt;span style=&quot;color: #ee2323;&quot;&gt;&lt;b&gt;정답 $457$&lt;/b&gt;&lt;/span&gt;&lt;/p&gt;
&lt;figure class=&quot;imageblock alignCenter&quot; data-ke-mobileStyle=&quot;widthOrigin&quot; data-filename=&quot;수능 22번.jpeg&quot; data-origin-width=&quot;1668&quot; data-origin-height=&quot;1545&quot;&gt;&lt;span data-url=&quot;https://blog.kakaocdn.net/dn/zv2Xq/dJMcag4Waf9/1ZHYnV9G8lzWZawkdbtRR0/img.jpg&quot; data-phocus=&quot;https://blog.kakaocdn.net/dn/zv2Xq/dJMcag4Waf9/1ZHYnV9G8lzWZawkdbtRR0/img.jpg&quot;&gt;&lt;img src=&quot;https://blog.kakaocdn.net/dn/zv2Xq/dJMcag4Waf9/1ZHYnV9G8lzWZawkdbtRR0/img.jpg&quot; srcset=&quot;https://img1.daumcdn.net/thumb/R1280x0/?scode=mtistory2&amp;fname=https%3A%2F%2Fblog.kakaocdn.net%2Fdn%2Fzv2Xq%2FdJMcag4Waf9%2F1ZHYnV9G8lzWZawkdbtRR0%2Fimg.jpg&quot; onerror=&quot;this.onerror=null; this.src='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png'; this.srcset='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png';&quot; loading=&quot;lazy&quot; width=&quot;1668&quot; height=&quot;1545&quot; data-filename=&quot;수능 22번.jpeg&quot; data-origin-width=&quot;1668&quot; data-origin-height=&quot;1545&quot;/&gt;&lt;/span&gt;&lt;/figure&gt;
&lt;/div&gt;
&lt;/div&gt;</description>
      <category>수학1- 문제풀이/지수함수와 로그함수</category>
      <author>수악중독</author>
      <guid isPermaLink="true">https://mathjk.tistory.com/6797</guid>
      <comments>https://mathjk.tistory.com/6797#entry6797comment</comments>
      <pubDate>Sat, 15 Nov 2025 00:10:34 +0900</pubDate>
    </item>
    <item>
      <title>조건부확률_난이도 중상 (2025년 11월 수능 확통 28번)</title>
      <link>https://mathjk.tistory.com/6796</link>
      <description>&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;$16$개의 공과 $1$부터 $6$까지의 자연수가 하나씩 적혀 있는 여섯 개의 빈 상자가 있다.&amp;nbsp;&amp;nbsp;한&amp;nbsp;개의&amp;nbsp;주사위를&amp;nbsp;사용하여&amp;nbsp;다음&amp;nbsp;시행을&amp;nbsp;한다.&amp;nbsp;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;div class=&quot;txc-textbox&quot; style=&quot;background-color: #dbe8fb; padding: 10px; border: 1px solid #dbe8fb;&quot;&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;주사위를&amp;nbsp;한&amp;nbsp;번&amp;nbsp;던져&amp;nbsp;나온&amp;nbsp;눈의&amp;nbsp;수가&amp;nbsp;$\mathrm{k}$일&amp;nbsp;때,&amp;nbsp;&amp;nbsp;&lt;br /&gt;$\mathrm{k}$가&amp;nbsp;홀수이면&amp;nbsp;$1,&amp;nbsp;3,&amp;nbsp;5$가&amp;nbsp;적힌&amp;nbsp;상자에&amp;nbsp;공을&amp;nbsp;각각&amp;nbsp;$1$개씩&amp;nbsp;넣고,&amp;nbsp;&amp;nbsp;&lt;br /&gt;$\mathrm{k}$가&amp;nbsp;짝수이면&amp;nbsp;$\mathrm{k}$의&amp;nbsp;약수가&amp;nbsp;적힌&amp;nbsp;상자에&amp;nbsp;공을&amp;nbsp;각각&amp;nbsp;$1$개씩&amp;nbsp;넣는다.&amp;nbsp;&amp;nbsp;&lt;/p&gt;
&lt;/div&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;이 시행을 $4$번 반복한 후 여섯 개의 상자에 들어 있는 모든 공의 개수의 합이 홀수일 때,&amp;nbsp; $3$이 적힌 상자에 들어 있는 공의 개수가 $2$가 적힌 상자에 들어 있는 공의 개수보다 $1$개 더 많을 확률은?&lt;br /&gt;&lt;br /&gt;① $\dfrac{1}{8}$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;② $\dfrac{3}{16}$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;③ $\dfrac{1}{4}$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;④ $\dfrac{5}{16}$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;⑤ $\dfrac{3}{7}$&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;&lt;figure class=&quot;imageblock alignCenter&quot; data-ke-mobileStyle=&quot;widthOrigin&quot; data-filename=&quot;Screenshot 2025-11-14 at 09.23.39.png&quot; data-origin-width=&quot;1934&quot; data-origin-height=&quot;420&quot;&gt;&lt;span data-url=&quot;https://blog.kakaocdn.net/dn/YbidL/dJMcagw6cgj/iZkstVFNqxsyruFkvsXaZ0/img.png&quot; data-phocus=&quot;https://blog.kakaocdn.net/dn/YbidL/dJMcagw6cgj/iZkstVFNqxsyruFkvsXaZ0/img.png&quot;&gt;&lt;img src=&quot;https://blog.kakaocdn.net/dn/YbidL/dJMcagw6cgj/iZkstVFNqxsyruFkvsXaZ0/img.png&quot; srcset=&quot;https://img1.daumcdn.net/thumb/R1280x0/?scode=mtistory2&amp;fname=https%3A%2F%2Fblog.kakaocdn.net%2Fdn%2FYbidL%2FdJMcagw6cgj%2FiZkstVFNqxsyruFkvsXaZ0%2Fimg.png&quot; onerror=&quot;this.onerror=null; this.src='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png'; this.srcset='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png';&quot; loading=&quot;lazy&quot; width=&quot;616&quot; height=&quot;134&quot; data-filename=&quot;Screenshot 2025-11-14 at 09.23.39.png&quot; data-origin-width=&quot;1934&quot; data-origin-height=&quot;420&quot;/&gt;&lt;/span&gt;&lt;/figure&gt;
&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;div data-ke-type=&quot;moreLess&quot; data-text-more=&quot;풀이보기&quot; data-text-less=&quot;풀이닫기&quot;&gt;&lt;a class=&quot;btn-toggle-moreless&quot;&gt;더보기&lt;/a&gt;
&lt;div class=&quot;moreless-content&quot;&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&lt;span style=&quot;color: #ee2323;&quot;&gt;&lt;b&gt;정답 ②&lt;/b&gt;&lt;/span&gt;&lt;/p&gt;
&lt;figure class=&quot;imageblock alignCenter&quot; data-ke-mobileStyle=&quot;widthOrigin&quot; data-filename=&quot;수능 확통 28번.jpeg&quot; data-origin-width=&quot;1668&quot; data-origin-height=&quot;2058&quot;&gt;&lt;span data-url=&quot;https://blog.kakaocdn.net/dn/oK1WK/dJMcacIeFtn/oJvLDmARRFqXH5dyLpclAk/img.jpg&quot; data-phocus=&quot;https://blog.kakaocdn.net/dn/oK1WK/dJMcacIeFtn/oJvLDmARRFqXH5dyLpclAk/img.jpg&quot;&gt;&lt;img src=&quot;https://blog.kakaocdn.net/dn/oK1WK/dJMcacIeFtn/oJvLDmARRFqXH5dyLpclAk/img.jpg&quot; srcset=&quot;https://img1.daumcdn.net/thumb/R1280x0/?scode=mtistory2&amp;fname=https%3A%2F%2Fblog.kakaocdn.net%2Fdn%2FoK1WK%2FdJMcacIeFtn%2FoJvLDmARRFqXH5dyLpclAk%2Fimg.jpg&quot; onerror=&quot;this.onerror=null; this.src='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png'; this.srcset='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png';&quot; loading=&quot;lazy&quot; width=&quot;1668&quot; height=&quot;2058&quot; data-filename=&quot;수능 확통 28번.jpeg&quot; data-origin-width=&quot;1668&quot; data-origin-height=&quot;2058&quot;/&gt;&lt;/span&gt;&lt;/figure&gt;
&lt;/div&gt;
&lt;/div&gt;</description>
      <category>확률과 통계 - 문제풀이/확률</category>
      <author>수악중독</author>
      <guid isPermaLink="true">https://mathjk.tistory.com/6796</guid>
      <comments>https://mathjk.tistory.com/6796#entry6796comment</comments>
      <pubDate>Sat, 15 Nov 2025 00:06:43 +0900</pubDate>
    </item>
    <item>
      <title>이항분포의 정규분로의 근사_난이도 중상 (2025년 11월 수능 확통 29번)</title>
      <link>https://mathjk.tistory.com/6795</link>
      <description>&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;$6$&amp;nbsp;이하의&amp;nbsp;자연수&amp;nbsp;$a$에&amp;nbsp;대하여&amp;nbsp;한&amp;nbsp;개의&amp;nbsp;주사위와&amp;nbsp;한&amp;nbsp;개의&amp;nbsp;동전을&amp;nbsp;사용하여&amp;nbsp;다음&amp;nbsp;시행을&amp;nbsp;한다.&amp;nbsp;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;div class=&quot;txc-textbox&quot; style=&quot;background-color: #dbe8fb; padding: 10px; border: 1px solid #dbe8fb;&quot;&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;주사위를 한 번 던져 나온 눈의 수가 $a$보다 작거나 같으면 동전을&amp;nbsp;$8$번&amp;nbsp;던져&amp;nbsp;앞면이&amp;nbsp;나온&amp;nbsp;횟수를&amp;nbsp;기록하고,&amp;nbsp;&amp;nbsp;&lt;br /&gt;나온 눈의 수가 $a$보다 크면 동전을&amp;nbsp;$3$번&amp;nbsp;던져&amp;nbsp;앞면이&amp;nbsp;나온&amp;nbsp;횟수를&amp;nbsp;기록한다.&amp;nbsp;&amp;nbsp;&lt;/p&gt;
&lt;/div&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;이 시행을 $19200$번 반복하여 기록한 수가 $6$인 횟수를 확률변수 $X$라 하자.&amp;nbsp;&amp;nbsp;&lt;br /&gt;$\mathrm{E}(X) = 4800$일 때, $\mathrm{P}(X \le 4800 + 30a)$의 값을 아래 표준정규분포표를 이용하여 구한 값이 $k$이다.&amp;nbsp;&amp;nbsp;&lt;br /&gt;$1000&amp;nbsp;\times&amp;nbsp;k$의&amp;nbsp;값을&amp;nbsp;구하시오.&lt;/p&gt;
&lt;p&gt;&lt;figure class=&quot;imageblock alignCenter&quot; data-ke-mobileStyle=&quot;widthOrigin&quot; data-filename=&quot;Screenshot 2025-11-14 at 09.20.02.png&quot; data-origin-width=&quot;708&quot; data-origin-height=&quot;790&quot;&gt;&lt;span data-url=&quot;https://blog.kakaocdn.net/dn/bILPcj/dJMcahbHKRk/16zkpU5IfRKsNKuQxkthZ0/img.png&quot; data-phocus=&quot;https://blog.kakaocdn.net/dn/bILPcj/dJMcahbHKRk/16zkpU5IfRKsNKuQxkthZ0/img.png&quot;&gt;&lt;img src=&quot;https://blog.kakaocdn.net/dn/bILPcj/dJMcahbHKRk/16zkpU5IfRKsNKuQxkthZ0/img.png&quot; srcset=&quot;https://img1.daumcdn.net/thumb/R1280x0/?scode=mtistory2&amp;fname=https%3A%2F%2Fblog.kakaocdn.net%2Fdn%2FbILPcj%2FdJMcahbHKRk%2F16zkpU5IfRKsNKuQxkthZ0%2Fimg.png&quot; onerror=&quot;this.onerror=null; this.src='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png'; this.srcset='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png';&quot; loading=&quot;lazy&quot; width=&quot;224&quot; height=&quot;250&quot; data-filename=&quot;Screenshot 2025-11-14 at 09.20.02.png&quot; data-origin-width=&quot;708&quot; data-origin-height=&quot;790&quot;/&gt;&lt;/span&gt;&lt;/figure&gt;
&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;div data-ke-type=&quot;moreLess&quot; data-text-more=&quot;풀이보기&quot; data-text-less=&quot;풀이닫기&quot;&gt;&lt;a class=&quot;btn-toggle-moreless&quot;&gt;더보기&lt;/a&gt;
&lt;div class=&quot;moreless-content&quot;&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&lt;span style=&quot;color: #ee2323;&quot;&gt;&lt;b&gt;정답 $977$&lt;/b&gt;&lt;/span&gt;&lt;/p&gt;
&lt;figure class=&quot;imageblock alignCenter&quot; data-ke-mobileStyle=&quot;widthOrigin&quot; data-filename=&quot;수능 확통 29번.jpeg&quot; data-origin-width=&quot;1668&quot; data-origin-height=&quot;1532&quot;&gt;&lt;span data-url=&quot;https://blog.kakaocdn.net/dn/eWuyVG/dJMcagRoVeP/N2aLDLTC0jhA2aGZRzJol1/img.jpg&quot; data-phocus=&quot;https://blog.kakaocdn.net/dn/eWuyVG/dJMcagRoVeP/N2aLDLTC0jhA2aGZRzJol1/img.jpg&quot;&gt;&lt;img src=&quot;https://blog.kakaocdn.net/dn/eWuyVG/dJMcagRoVeP/N2aLDLTC0jhA2aGZRzJol1/img.jpg&quot; srcset=&quot;https://img1.daumcdn.net/thumb/R1280x0/?scode=mtistory2&amp;fname=https%3A%2F%2Fblog.kakaocdn.net%2Fdn%2FeWuyVG%2FdJMcagRoVeP%2FN2aLDLTC0jhA2aGZRzJol1%2Fimg.jpg&quot; onerror=&quot;this.onerror=null; this.src='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png'; this.srcset='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png';&quot; loading=&quot;lazy&quot; width=&quot;1668&quot; height=&quot;1532&quot; data-filename=&quot;수능 확통 29번.jpeg&quot; data-origin-width=&quot;1668&quot; data-origin-height=&quot;1532&quot;/&gt;&lt;/span&gt;&lt;/figure&gt;
&lt;/div&gt;
&lt;/div&gt;</description>
      <category>확률과 통계 - 문제풀이/통계</category>
      <author>수악중독</author>
      <guid isPermaLink="true">https://mathjk.tistory.com/6795</guid>
      <comments>https://mathjk.tistory.com/6795#entry6795comment</comments>
      <pubDate>Fri, 14 Nov 2025 23:21:18 +0900</pubDate>
    </item>
    <item>
      <title>중복조합_난이도 상 (2025년 11월 수능 확통 30번)</title>
      <link>https://mathjk.tistory.com/6794</link>
      <description>&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;비어 있는 주머니 $10$개가 일렬로 놓여 있고, 공 $8$개가 있다.&amp;nbsp;&amp;nbsp;각 주머니에 들어 있는 공의 개수가 $2$ 이하가 되도록 공을 주머니에 남김없이 나누어 넣을 때, 다음 조건을 만족시키는 경우의 수를 구하시오. (단, 공끼리는 서로 구별하지 않는다.)&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;div class=&quot;txc-textbox&quot; style=&quot;background-color: #dbe8fb; padding: 10px; border: 1px solid #dbe8fb;&quot;&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;(가)&amp;nbsp;들어&amp;nbsp;있는&amp;nbsp;공의&amp;nbsp;개수가&amp;nbsp;$1$인&amp;nbsp;주머니는&amp;nbsp;$3$개&amp;nbsp;또는&amp;nbsp;$9$개이다.&amp;nbsp;&amp;nbsp;&lt;br /&gt;(나)&amp;nbsp;들어&amp;nbsp;있는&amp;nbsp;공의&amp;nbsp;개수가&amp;nbsp;$2$인&amp;nbsp;주머니와&amp;nbsp;이웃한&amp;nbsp;주머니에는&amp;nbsp;공이&amp;nbsp;들어&amp;nbsp;있지&amp;nbsp;않다.&lt;/p&gt;
&lt;/div&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;div data-ke-type=&quot;moreLess&quot; data-text-more=&quot;풀이보기&quot; data-text-less=&quot;풀이닫기&quot;&gt;&lt;a class=&quot;btn-toggle-moreless&quot;&gt;더보기&lt;/a&gt;
&lt;div class=&quot;moreless-content&quot;&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&lt;span style=&quot;color: #ee2323;&quot;&gt;&lt;b&gt;정답 $262$&lt;/b&gt;&lt;/span&gt;&lt;/p&gt;
&lt;figure class=&quot;imageblock alignCenter&quot; data-ke-mobileStyle=&quot;widthOrigin&quot; data-filename=&quot;수능 확통 30번jpeg.jpeg&quot; data-origin-width=&quot;1442&quot; data-origin-height=&quot;1740&quot;&gt;&lt;span data-url=&quot;https://blog.kakaocdn.net/dn/cenq0l/dJMcag4V9hn/D9IlLbW79dFe9psrQjjG5K/img.jpg&quot; data-phocus=&quot;https://blog.kakaocdn.net/dn/cenq0l/dJMcag4V9hn/D9IlLbW79dFe9psrQjjG5K/img.jpg&quot;&gt;&lt;img src=&quot;https://blog.kakaocdn.net/dn/cenq0l/dJMcag4V9hn/D9IlLbW79dFe9psrQjjG5K/img.jpg&quot; srcset=&quot;https://img1.daumcdn.net/thumb/R1280x0/?scode=mtistory2&amp;fname=https%3A%2F%2Fblog.kakaocdn.net%2Fdn%2Fcenq0l%2FdJMcag4V9hn%2FD9IlLbW79dFe9psrQjjG5K%2Fimg.jpg&quot; onerror=&quot;this.onerror=null; this.src='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png'; this.srcset='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png';&quot; loading=&quot;lazy&quot; width=&quot;1442&quot; height=&quot;1740&quot; data-filename=&quot;수능 확통 30번jpeg.jpeg&quot; data-origin-width=&quot;1442&quot; data-origin-height=&quot;1740&quot;/&gt;&lt;/span&gt;&lt;/figure&gt;
&lt;/div&gt;
&lt;/div&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&lt;br /&gt;&lt;br /&gt;&lt;/p&gt;</description>
      <category>확률과 통계 - 문제풀이/경우의 수</category>
      <author>수악중독</author>
      <guid isPermaLink="true">https://mathjk.tistory.com/6794</guid>
      <comments>https://mathjk.tistory.com/6794#entry6794comment</comments>
      <pubDate>Fri, 14 Nov 2025 23:18:17 +0900</pubDate>
    </item>
    <item>
      <title>정사영의 넓이_난이도 중 (2025년 11월 수능 기하 28번)</title>
      <link>https://mathjk.tistory.com/6793</link>
      <description>&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;그림과 같이 $\overline{\mathrm{AB}}=\overline{\mathrm{CD}}=4$, $\overline{\mathrm{BC}} = \overline{\mathrm{BD}} = 2\sqrt{5}$인 사면체 $\mathrm{ABCD}$가 있고, 점 $\mathrm{A}$에서 직선 $\mathrm{CD}$에 내린 수선의 발 $\mathrm{H}$에 대하여 두 평면 $\mathrm{ABH}$와 $\mathrm{BCD}$는 서로 수직이고 $\overline{\mathrm{AH}}=4$이다. 삼각형 $\mathrm{ABH}$의 무게중심을 $\mathrm{G}$라 하고, 점 $\mathrm{G}$를 중심으로 하고 평면 $\mathrm{ACD}$에 접하는 구를 $S$라 하자. $\angle \mathrm{APG} = \dfrac{\pi}{2}$인 구 $S$ 위의 모든 점 $\mathrm{P}$가 나타내는 도형을 $T$라 할 때, 도형 $T$의 평면 $\mathrm{ABC}$ 위로의 정사영의 넓이는?&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;&lt;figure class=&quot;imageblock alignCenter&quot; data-ke-mobileStyle=&quot;widthOrigin&quot; data-filename=&quot;Screenshot 2025-11-14 at 09.14.10.png&quot; data-origin-width=&quot;1414&quot; data-origin-height=&quot;1408&quot;&gt;&lt;span data-url=&quot;https://blog.kakaocdn.net/dn/Lrx6X/dJMcahJxJVZ/PGbLn3RUGkU0eaYnc55Suk/img.png&quot; data-phocus=&quot;https://blog.kakaocdn.net/dn/Lrx6X/dJMcahJxJVZ/PGbLn3RUGkU0eaYnc55Suk/img.png&quot;&gt;&lt;img src=&quot;https://blog.kakaocdn.net/dn/Lrx6X/dJMcahJxJVZ/PGbLn3RUGkU0eaYnc55Suk/img.png&quot; srcset=&quot;https://img1.daumcdn.net/thumb/R1280x0/?scode=mtistory2&amp;fname=https%3A%2F%2Fblog.kakaocdn.net%2Fdn%2FLrx6X%2FdJMcahJxJVZ%2FPGbLn3RUGkU0eaYnc55Suk%2Fimg.png&quot; onerror=&quot;this.onerror=null; this.src='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png'; this.srcset='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png';&quot; loading=&quot;lazy&quot; width=&quot;374&quot; height=&quot;372&quot; data-filename=&quot;Screenshot 2025-11-14 at 09.14.10.png&quot; data-origin-width=&quot;1414&quot; data-origin-height=&quot;1408&quot;/&gt;&lt;/span&gt;&lt;/figure&gt;
&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;br /&gt;① $\dfrac{\pi}{7}$&amp;nbsp; &amp;nbsp; &amp;nbsp; &amp;nbsp; &amp;nbsp; &amp;nbsp;② $\dfrac{\pi}{6}$&amp;nbsp; &amp;nbsp; &amp;nbsp; &amp;nbsp; &amp;nbsp; &amp;nbsp;③ $\dfrac{\pi}{5}$&amp;nbsp; &amp;nbsp; &amp;nbsp; &amp;nbsp; &amp;nbsp; &amp;nbsp;④ $\dfrac{\pi}{4}$&amp;nbsp; &amp;nbsp; &amp;nbsp; &amp;nbsp; &amp;nbsp; &amp;nbsp;⑤ $\dfrac{\pi}{3}$&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;div data-ke-type=&quot;moreLess&quot; data-text-more=&quot;풀이보기&quot; data-text-less=&quot;풀이닫기&quot;&gt;&lt;a class=&quot;btn-toggle-moreless&quot;&gt;더보기&lt;/a&gt;
&lt;div class=&quot;moreless-content&quot;&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&lt;span style=&quot;color: #ee2323;&quot;&gt;&lt;b&gt;정답 ④&lt;/b&gt;&lt;/span&gt;&lt;/p&gt;
&lt;figure class=&quot;imageblock alignCenter&quot; data-ke-mobileStyle=&quot;widthOrigin&quot; data-filename=&quot;수능 기하28번.jpeg&quot; data-origin-width=&quot;1668&quot; data-origin-height=&quot;1775&quot;&gt;&lt;span data-url=&quot;https://blog.kakaocdn.net/dn/cMVVvu/dJMb99LvC3d/W4HpAfVsh10sQTM75EcouK/img.jpg&quot; data-phocus=&quot;https://blog.kakaocdn.net/dn/cMVVvu/dJMb99LvC3d/W4HpAfVsh10sQTM75EcouK/img.jpg&quot;&gt;&lt;img src=&quot;https://blog.kakaocdn.net/dn/cMVVvu/dJMb99LvC3d/W4HpAfVsh10sQTM75EcouK/img.jpg&quot; srcset=&quot;https://img1.daumcdn.net/thumb/R1280x0/?scode=mtistory2&amp;fname=https%3A%2F%2Fblog.kakaocdn.net%2Fdn%2FcMVVvu%2FdJMb99LvC3d%2FW4HpAfVsh10sQTM75EcouK%2Fimg.jpg&quot; onerror=&quot;this.onerror=null; this.src='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png'; this.srcset='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png';&quot; loading=&quot;lazy&quot; width=&quot;1668&quot; height=&quot;1775&quot; data-filename=&quot;수능 기하28번.jpeg&quot; data-origin-width=&quot;1668&quot; data-origin-height=&quot;1775&quot;/&gt;&lt;/span&gt;&lt;/figure&gt;
&lt;/div&gt;
&lt;/div&gt;</description>
      <category>기하 - 문제풀이/공간도형과 공간좌표</category>
      <author>수악중독</author>
      <guid isPermaLink="true">https://mathjk.tistory.com/6793</guid>
      <comments>https://mathjk.tistory.com/6793#entry6793comment</comments>
      <pubDate>Fri, 14 Nov 2025 23:15:56 +0900</pubDate>
    </item>
    <item>
      <title>포물선과 타원의 정의&amp;amp;방정식_난이도 중 (2025년 11월 수능 기하 29번)</title>
      <link>https://mathjk.tistory.com/6792</link>
      <description>&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;그림과 같이 초점이 $\mathrm{F}(p, 0)$ ($p &amp;gt; 0$)이고 준선이 $x = -p$인 포물선 위의 점 중 제$1$사분면에 있는 점 $\mathrm{A}$에서 포물선의 준선에 내린 수선의 발을 $\mathrm{H}$라 하고, 두 초점이 $x$축 위에 있고 세 점 $\mathrm{F}$, $\mathrm{A}$, $\mathrm{H}$를 지나는 타원의 $x$좌표가 양수인 초점을 $\mathrm{B}$라 하자. 삼각형 $\mathrm{AHB}$의 둘레의 길이가 $p + 27$, 넓이가 $2p + 12$일 때, 선분 $\mathrm{HF}$의 길이를 $k$라 하자. $k^{2}$의 값을 구하시오.&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;&lt;figure class=&quot;imageblock alignCenter&quot; data-ke-mobileStyle=&quot;widthOrigin&quot; data-filename=&quot;Screenshot 2025-11-13 at 12.59.21.png&quot; data-origin-width=&quot;1230&quot; data-origin-height=&quot;896&quot;&gt;&lt;span data-url=&quot;https://blog.kakaocdn.net/dn/P1Qbn/dJMcabbtRtB/RfiFxHTJNmswk3HEnwS90K/img.png&quot; data-phocus=&quot;https://blog.kakaocdn.net/dn/P1Qbn/dJMcabbtRtB/RfiFxHTJNmswk3HEnwS90K/img.png&quot;&gt;&lt;img src=&quot;https://blog.kakaocdn.net/dn/P1Qbn/dJMcabbtRtB/RfiFxHTJNmswk3HEnwS90K/img.png&quot; srcset=&quot;https://img1.daumcdn.net/thumb/R1280x0/?scode=mtistory2&amp;fname=https%3A%2F%2Fblog.kakaocdn.net%2Fdn%2FP1Qbn%2FdJMcabbtRtB%2FRfiFxHTJNmswk3HEnwS90K%2Fimg.png&quot; onerror=&quot;this.onerror=null; this.src='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png'; this.srcset='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png';&quot; loading=&quot;lazy&quot; width=&quot;463&quot; height=&quot;337&quot; data-filename=&quot;Screenshot 2025-11-13 at 12.59.21.png&quot; data-origin-width=&quot;1230&quot; data-origin-height=&quot;896&quot;/&gt;&lt;/span&gt;&lt;/figure&gt;
&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;div data-ke-type=&quot;moreLess&quot; data-text-more=&quot;풀이보기&quot; data-text-less=&quot;풀이닫기&quot;&gt;&lt;a class=&quot;btn-toggle-moreless&quot;&gt;더보기&lt;/a&gt;
&lt;div class=&quot;moreless-content&quot;&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&lt;span style=&quot;color: #ee2323;&quot;&gt;&lt;b&gt;정답 $360$&lt;/b&gt;&lt;/span&gt;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;figure class=&quot;imageblock alignCenter&quot; data-ke-mobileStyle=&quot;widthOrigin&quot; data-filename=&quot;2025 문제풀이 part 2.jpeg&quot; data-origin-width=&quot;1668&quot; data-origin-height=&quot;1341&quot;&gt;&lt;span data-url=&quot;https://blog.kakaocdn.net/dn/clq0mS/dJMb99LvdRr/V45IOOL1O92c6lrpG4vZJ0/img.jpg&quot; data-phocus=&quot;https://blog.kakaocdn.net/dn/clq0mS/dJMb99LvdRr/V45IOOL1O92c6lrpG4vZJ0/img.jpg&quot;&gt;&lt;img src=&quot;https://blog.kakaocdn.net/dn/clq0mS/dJMb99LvdRr/V45IOOL1O92c6lrpG4vZJ0/img.jpg&quot; srcset=&quot;https://img1.daumcdn.net/thumb/R1280x0/?scode=mtistory2&amp;fname=https%3A%2F%2Fblog.kakaocdn.net%2Fdn%2Fclq0mS%2FdJMb99LvdRr%2FV45IOOL1O92c6lrpG4vZJ0%2Fimg.jpg&quot; onerror=&quot;this.onerror=null; this.src='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png'; this.srcset='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png';&quot; loading=&quot;lazy&quot; width=&quot;1668&quot; height=&quot;1341&quot; data-filename=&quot;2025 문제풀이 part 2.jpeg&quot; data-origin-width=&quot;1668&quot; data-origin-height=&quot;1341&quot;/&gt;&lt;/span&gt;&lt;/figure&gt;
&lt;/div&gt;
&lt;/div&gt;</description>
      <category>기하 - 문제풀이/이차곡선</category>
      <author>수악중독</author>
      <guid isPermaLink="true">https://mathjk.tistory.com/6792</guid>
      <comments>https://mathjk.tistory.com/6792#entry6792comment</comments>
      <pubDate>Fri, 14 Nov 2025 03:00:36 +0900</pubDate>
    </item>
    <item>
      <title>벡터 내적의 기하학적 의미_난이도 상 (2025년 11월 수능 기하 30번)</title>
      <link>https://mathjk.tistory.com/6791</link>
      <description>&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;좌표평면에서 길이가 $10\sqrt{2}$인 선분 $\mathrm{AB}$를 지름으로 하는 원 위의 두 점 $\mathrm{P}$, $\mathrm{Q}$가 $$\left ( \overrightarrow{\mathrm{PA}}+ \overrightarrow{\mathrm{PB}} \right ) \cdot \left ( \overrightarrow{\mathrm{PQ}}+ \overrightarrow{\mathrm{PB}} \right )=2 \left | \overrightarrow{\mathrm{PQ}} \right | ^2$$을 만족시킨다. $\left| \overrightarrow{\mathrm{PB}} \right| = 14$일 때, $\left| \overrightarrow{\mathrm{PA}} \cdot \overrightarrow{\mathrm{QB}} \right| = \dfrac{q}{p}$이다. $p + q$의 값을 구하시오. (단, $\left| \overrightarrow{\mathrm{QB}} \right| &amp;gt; 0$이고, $p$와 $q$는 서로소인 자연수이다.)&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;div data-ke-type=&quot;moreLess&quot; data-text-more=&quot;풀이보기&quot; data-text-less=&quot;풀이닫기&quot;&gt;&lt;a class=&quot;btn-toggle-moreless&quot;&gt;더보기&lt;/a&gt;
&lt;div class=&quot;moreless-content&quot;&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&lt;span style=&quot;color: #ee2323;&quot;&gt;&lt;b&gt;정답 $211$&lt;/b&gt;&lt;/span&gt;&lt;/p&gt;
&lt;figure class=&quot;imageblock alignCenter&quot; data-ke-mobileStyle=&quot;widthOrigin&quot; data-filename=&quot;2025 문제풀이 part 2.jpeg&quot; data-origin-width=&quot;1556&quot; data-origin-height=&quot;1964&quot;&gt;&lt;span data-url=&quot;https://blog.kakaocdn.net/dn/nNwUN/dJMcaf51sTb/oxhJBpS7NkkOQP19v5x190/img.jpg&quot; data-phocus=&quot;https://blog.kakaocdn.net/dn/nNwUN/dJMcaf51sTb/oxhJBpS7NkkOQP19v5x190/img.jpg&quot;&gt;&lt;img src=&quot;https://blog.kakaocdn.net/dn/nNwUN/dJMcaf51sTb/oxhJBpS7NkkOQP19v5x190/img.jpg&quot; srcset=&quot;https://img1.daumcdn.net/thumb/R1280x0/?scode=mtistory2&amp;fname=https%3A%2F%2Fblog.kakaocdn.net%2Fdn%2FnNwUN%2FdJMcaf51sTb%2FoxhJBpS7NkkOQP19v5x190%2Fimg.jpg&quot; onerror=&quot;this.onerror=null; this.src='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png'; this.srcset='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png';&quot; loading=&quot;lazy&quot; width=&quot;1556&quot; height=&quot;1964&quot; data-filename=&quot;2025 문제풀이 part 2.jpeg&quot; data-origin-width=&quot;1556&quot; data-origin-height=&quot;1964&quot;/&gt;&lt;/span&gt;&lt;/figure&gt;
&lt;/div&gt;
&lt;/div&gt;</description>
      <category>기하 - 문제풀이/평면벡터</category>
      <author>수악중독</author>
      <guid isPermaLink="true">https://mathjk.tistory.com/6791</guid>
      <comments>https://mathjk.tistory.com/6791#entry6791comment</comments>
      <pubDate>Fri, 14 Nov 2025 01:41:30 +0900</pubDate>
    </item>
    <item>
      <title>역함수의 적분&amp;amp;그래프의 개형&amp;amp;접선의 방정식_난이도 중상 (2025년 11월 수능 28번)</title>
      <link>https://mathjk.tistory.com/6790</link>
      <description>&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;함수 $$f(x)=\dfrac{1}{2}x^2 &amp;minus; x + \ln⁡(1+x)$$와 양수 $t$에 대하여 점 $(s, \;f(s))$ ($s &amp;gt; 0$)에서 $y$축에 내린 수선의 발과 곡선 $y=f(x)$ 위의 점 $(s, \;f(s))$에서의 접선이 $y$축과 만나는 점 사이의 거리가 $t$가 되도록 하는 $s$의 값을 $g(t)$라 하자. $\displaystyle \int_{\frac{1}{2}}^{\frac{27}{4}} g(t) dt$의 값은?&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;br /&gt;① $\dfrac{161}{12} + \ln 3$&amp;nbsp; &amp;nbsp; &amp;nbsp; &amp;nbsp; &amp;nbsp; ② $\dfrac{40}{3} + \ln 3$&amp;nbsp; &amp;nbsp; &amp;nbsp; &amp;nbsp; &amp;nbsp; &amp;nbsp;③ $\dfrac{53}{4} + \ln 2$&amp;nbsp; &amp;nbsp; &amp;nbsp; &amp;nbsp; &amp;nbsp; &amp;nbsp;④ $\dfrac{79}{6} + \ln 2$&amp;nbsp; &amp;nbsp; &amp;nbsp; &amp;nbsp; &amp;nbsp; &amp;nbsp;⑤ $\dfrac{157}{12} + \ln 2$&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;div data-ke-type=&quot;moreLess&quot; data-text-more=&quot;풀이보기&quot; data-text-less=&quot;풀이닫기&quot;&gt;&lt;a class=&quot;btn-toggle-moreless&quot;&gt;더보기&lt;/a&gt;
&lt;div class=&quot;moreless-content&quot;&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&lt;span style=&quot;color: #ee2323;&quot;&gt;&lt;b&gt;정답 ⑤&lt;/b&gt;&lt;/span&gt;&lt;/p&gt;
&lt;figure class=&quot;imageblock alignCenter&quot; data-ke-mobileStyle=&quot;widthOrigin&quot; data-filename=&quot;2025 문제풀이 part 2.jpeg&quot; data-origin-width=&quot;1668&quot; data-origin-height=&quot;1898&quot;&gt;&lt;span data-url=&quot;https://blog.kakaocdn.net/dn/bklD7H/dJMcahJxgqC/F8Ya0DgGDHSKhEsM5yRk3k/img.jpg&quot; data-phocus=&quot;https://blog.kakaocdn.net/dn/bklD7H/dJMcahJxgqC/F8Ya0DgGDHSKhEsM5yRk3k/img.jpg&quot;&gt;&lt;img src=&quot;https://blog.kakaocdn.net/dn/bklD7H/dJMcahJxgqC/F8Ya0DgGDHSKhEsM5yRk3k/img.jpg&quot; srcset=&quot;https://img1.daumcdn.net/thumb/R1280x0/?scode=mtistory2&amp;fname=https%3A%2F%2Fblog.kakaocdn.net%2Fdn%2FbklD7H%2FdJMcahJxgqC%2FF8Ya0DgGDHSKhEsM5yRk3k%2Fimg.jpg&quot; onerror=&quot;this.onerror=null; this.src='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png'; this.srcset='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png';&quot; loading=&quot;lazy&quot; width=&quot;1668&quot; height=&quot;1898&quot; data-filename=&quot;2025 문제풀이 part 2.jpeg&quot; data-origin-width=&quot;1668&quot; data-origin-height=&quot;1898&quot;/&gt;&lt;/span&gt;&lt;/figure&gt;
&lt;/div&gt;
&lt;/div&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;</description>
      <category>미적분 - 문제풀이/적분법</category>
      <author>수악중독</author>
      <guid isPermaLink="true">https://mathjk.tistory.com/6790</guid>
      <comments>https://mathjk.tistory.com/6790#entry6790comment</comments>
      <pubDate>Thu, 13 Nov 2025 23:33:16 +0900</pubDate>
    </item>
    <item>
      <title>급수 &amp;amp; 등비급수_난이도 중 (2025년 11월 수능 미적분 29번)</title>
      <link>https://mathjk.tistory.com/6789</link>
      <description>&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;첫째항과&amp;nbsp;공차가&amp;nbsp;같은&amp;nbsp;등차수열&amp;nbsp;${a_{n}}$과&amp;nbsp;등비수열&amp;nbsp;${b_{n}}$이&amp;nbsp;다음&amp;nbsp;조건을&amp;nbsp;만족시킨다.&amp;nbsp;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;div class=&quot;txc-textbox&quot; style=&quot;background-color: #dbe8fb; padding: 10px; border: 1px solid #dbe8fb;&quot;&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;어떤 자연수 $k$에 대하여&amp;nbsp;&amp;nbsp;$$b_{k+i}=\dfrac{1}{a_i}&amp;minus;1 \quad (i=1, \;2, \;3)$$ 이다.&amp;nbsp;&amp;nbsp;&lt;/p&gt;
&lt;/div&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;부등식 $$0&amp;lt; \sum \limits_{n=1}^\infty \left (b_n -\dfrac{1}{a_n a_{n+1}} \right ) &amp;lt; 30$$이 성립할 때, $a_{2} \times \displaystyle \sum_{n=1}^{\infty} b_{2n} = \dfrac{q}{p}$이다. $p+q$의 값을 구하시오. (단, $a_{1} \ne 0$이고, $p$와 $q$는 서로소인 자연수이다.)&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;div data-ke-type=&quot;moreLess&quot; data-text-more=&quot;풀이보기&quot; data-text-less=&quot;풀이닫기&quot;&gt;&lt;a class=&quot;btn-toggle-moreless&quot;&gt;더보기&lt;/a&gt;
&lt;div class=&quot;moreless-content&quot;&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&lt;span style=&quot;color: #ee2323;&quot;&gt;&lt;b&gt;정답 $97$&lt;/b&gt;&lt;/span&gt;&lt;/p&gt;
&lt;figure class=&quot;imageblock alignCenter&quot; data-ke-mobileStyle=&quot;widthOrigin&quot; data-filename=&quot;2025 문제풀이 part 2.jpeg&quot; data-origin-width=&quot;1513&quot; data-origin-height=&quot;1931&quot;&gt;&lt;span data-url=&quot;https://blog.kakaocdn.net/dn/bem2f0/dJMcaaDDP82/wkkByKDUpx6ev0KAA2MxX0/img.jpg&quot; data-phocus=&quot;https://blog.kakaocdn.net/dn/bem2f0/dJMcaaDDP82/wkkByKDUpx6ev0KAA2MxX0/img.jpg&quot;&gt;&lt;img src=&quot;https://blog.kakaocdn.net/dn/bem2f0/dJMcaaDDP82/wkkByKDUpx6ev0KAA2MxX0/img.jpg&quot; srcset=&quot;https://img1.daumcdn.net/thumb/R1280x0/?scode=mtistory2&amp;fname=https%3A%2F%2Fblog.kakaocdn.net%2Fdn%2Fbem2f0%2FdJMcaaDDP82%2FwkkByKDUpx6ev0KAA2MxX0%2Fimg.jpg&quot; onerror=&quot;this.onerror=null; this.src='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png'; this.srcset='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png';&quot; loading=&quot;lazy&quot; width=&quot;1513&quot; height=&quot;1931&quot; data-filename=&quot;2025 문제풀이 part 2.jpeg&quot; data-origin-width=&quot;1513&quot; data-origin-height=&quot;1931&quot;/&gt;&lt;/span&gt;&lt;/figure&gt;
&lt;/div&gt;
&lt;/div&gt;</description>
      <category>미적분 - 문제풀이/수열의 극한</category>
      <author>수악중독</author>
      <guid isPermaLink="true">https://mathjk.tistory.com/6789</guid>
      <comments>https://mathjk.tistory.com/6789#entry6789comment</comments>
      <pubDate>Thu, 13 Nov 2025 22:56:47 +0900</pubDate>
    </item>
    <item>
      <title>여러 가지 함수의 미분법 &amp;amp; 함수의 연속과 불연속 &amp;amp; 역함수_난이도 상 (2025년 11월 수능 미적분 30번)</title>
      <link>https://mathjk.tistory.com/6788</link>
      <description>&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;실수&amp;nbsp;전체의&amp;nbsp;집합에서&amp;nbsp;증가하는&amp;nbsp;연속함수&amp;nbsp;$f(x)$의&amp;nbsp;역함수&amp;nbsp;$f^{-1}(x)$가&amp;nbsp;다음&amp;nbsp;조건을&amp;nbsp;만족시킨다.&amp;nbsp;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;div class=&quot;txc-textbox&quot; style=&quot;background-color: #dbe8fb; padding: 10px; border: 1px solid #dbe8fb;&quot;&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;(가)&amp;nbsp;$|x|&amp;nbsp;\le&amp;nbsp;1$일&amp;nbsp;때,&amp;nbsp;$4&amp;nbsp;\times&amp;nbsp;\left(&amp;nbsp;f^{-1}(x)&amp;nbsp;\right)^{2}&amp;nbsp;=&amp;nbsp;x^{2}&amp;nbsp;(x^{2}&amp;nbsp;-&amp;nbsp;5)^{3}$이다.&amp;nbsp;&amp;nbsp;&lt;br /&gt;(나)&amp;nbsp;$|x|&amp;nbsp;&amp;gt;&amp;nbsp;1$일&amp;nbsp;때,&amp;nbsp;$\left|&amp;nbsp;f^{-1}(x)&amp;nbsp;\right|&amp;nbsp;=&amp;nbsp;e^{|x|-1}&amp;nbsp;+&amp;nbsp;1$이다.&amp;nbsp;&amp;nbsp;&lt;/p&gt;
&lt;/div&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;실수 $m$에 대하여 기울기가 $m$이고 점 $(1, 0)$을 지나는 직선이 곡선 $y = f(x)$와 만나는 점의 개수를 $g(m)$이라 하자. 함수 $g(m)$이 $m = a$, $m = b$ ($a &amp;lt; b$)에서 불연속일 때, $g(a) \times \left ( \lim \limits_{m \to a+} g(m) \right ) + g(b) \times \left (\dfrac{\ln b}{b} \right )^2$의&amp;nbsp;값을&amp;nbsp;구하시오.&amp;nbsp;(단,&amp;nbsp;$\displaystyle\lim_{x&amp;nbsp;\to&amp;nbsp;\infty}&amp;nbsp;\dfrac{\ln&amp;nbsp;x}{x}&amp;nbsp;=&amp;nbsp;0$)&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;div data-ke-type=&quot;moreLess&quot; data-text-more=&quot;풀이보기&quot; data-text-less=&quot;풀이닫기&quot;&gt;&lt;a class=&quot;btn-toggle-moreless&quot;&gt;더보기&lt;/a&gt;
&lt;div class=&quot;moreless-content&quot;&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&lt;span style=&quot;color: #ee2323;&quot;&gt;&lt;b&gt;정답 $11$&lt;/b&gt;&lt;/span&gt;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;figure class=&quot;imageblock alignCenter&quot; data-ke-mobileStyle=&quot;widthOrigin&quot; data-filename=&quot;Screenshot 2025-11-13 at 08.26.49.png&quot; data-origin-width=&quot;1498&quot; data-origin-height=&quot;1852&quot;&gt;&lt;span data-url=&quot;https://blog.kakaocdn.net/dn/dOvZQM/dJMcacg9GrK/JHiWgAxSztPXhuzkYWT2u0/img.png&quot; data-phocus=&quot;https://blog.kakaocdn.net/dn/dOvZQM/dJMcacg9GrK/JHiWgAxSztPXhuzkYWT2u0/img.png&quot;&gt;&lt;img src=&quot;https://blog.kakaocdn.net/dn/dOvZQM/dJMcacg9GrK/JHiWgAxSztPXhuzkYWT2u0/img.png&quot; srcset=&quot;https://img1.daumcdn.net/thumb/R1280x0/?scode=mtistory2&amp;fname=https%3A%2F%2Fblog.kakaocdn.net%2Fdn%2FdOvZQM%2FdJMcacg9GrK%2FJHiWgAxSztPXhuzkYWT2u0%2Fimg.png&quot; onerror=&quot;this.onerror=null; this.src='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png'; this.srcset='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png';&quot; loading=&quot;lazy&quot; width=&quot;1498&quot; height=&quot;1852&quot; data-filename=&quot;Screenshot 2025-11-13 at 08.26.49.png&quot; data-origin-width=&quot;1498&quot; data-origin-height=&quot;1852&quot;/&gt;&lt;/span&gt;&lt;/figure&gt;
&lt;figure class=&quot;imageblock alignCenter&quot; data-ke-mobileStyle=&quot;widthOrigin&quot; data-filename=&quot;Screenshot 2025-11-13 at 08.27.11.png&quot; data-origin-width=&quot;1488&quot; data-origin-height=&quot;798&quot;&gt;&lt;span data-url=&quot;https://blog.kakaocdn.net/dn/0JU1p/dJMcabo0VJ7/FsR0phxeWrRWA30BijLdY0/img.png&quot; data-phocus=&quot;https://blog.kakaocdn.net/dn/0JU1p/dJMcabo0VJ7/FsR0phxeWrRWA30BijLdY0/img.png&quot;&gt;&lt;img src=&quot;https://blog.kakaocdn.net/dn/0JU1p/dJMcabo0VJ7/FsR0phxeWrRWA30BijLdY0/img.png&quot; srcset=&quot;https://img1.daumcdn.net/thumb/R1280x0/?scode=mtistory2&amp;fname=https%3A%2F%2Fblog.kakaocdn.net%2Fdn%2F0JU1p%2FdJMcabo0VJ7%2FFsR0phxeWrRWA30BijLdY0%2Fimg.png&quot; onerror=&quot;this.onerror=null; this.src='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png'; this.srcset='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png';&quot; loading=&quot;lazy&quot; width=&quot;1488&quot; height=&quot;798&quot; data-filename=&quot;Screenshot 2025-11-13 at 08.27.11.png&quot; data-origin-width=&quot;1488&quot; data-origin-height=&quot;798&quot;/&gt;&lt;/span&gt;&lt;/figure&gt;
&lt;/div&gt;
&lt;/div&gt;</description>
      <category>미적분 - 문제풀이/미분법</category>
      <author>수악중독</author>
      <guid isPermaLink="true">https://mathjk.tistory.com/6788</guid>
      <comments>https://mathjk.tistory.com/6788#entry6788comment</comments>
      <pubDate>Thu, 13 Nov 2025 22:27:33 +0900</pubDate>
    </item>
    <item>
      <title>기하 3. 벡터</title>
      <link>https://mathjk.tistory.com/6787</link>
      <description>&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;hr contenteditable=&quot;false&quot; data-ke-type=&quot;horizontalRule&quot; data-ke-style=&quot;style7&quot; /&gt;
&lt;h2 style=&quot;text-align: center;&quot; data-ke-size=&quot;size26&quot;&gt;&lt;span style=&quot;color: #ee2323;&quot;&gt;&lt;b&gt;개념정리&lt;/b&gt;&lt;/span&gt;&lt;/h2&gt;
&lt;hr contenteditable=&quot;false&quot; data-ke-type=&quot;horizontalRule&quot; data-ke-style=&quot;style7&quot; /&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;h2 data-ke-size=&quot;size26&quot;&gt;&lt;b&gt;1. 벡터&lt;/b&gt;&lt;/h2&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;&lt;iframe src=&quot;https://www.youtube.com/embed/2h7dU_i71Fc?si=1Jdhd6LJiROlrz6R&quot; width=&quot;560&quot; height=&quot;315&quot; frameborder=&quot;&quot; allowfullscreen=&quot;true&quot;&gt;&lt;/iframe&gt;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;h2 data-ke-size=&quot;size26&quot;&gt;&lt;b&gt;2. 서로 같은 벡터&lt;/b&gt;&lt;/h2&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;&lt;iframe src=&quot;https://www.youtube.com/embed/M6on221SbRY?si=WABnTqlNGqkt9Te9&quot; width=&quot;560&quot; height=&quot;315&quot; frameborder=&quot;&quot; allowfullscreen=&quot;true&quot;&gt;&lt;/iframe&gt;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;h2 data-ke-size=&quot;size26&quot;&gt;&lt;b&gt;3. 벡터의 덧셈&lt;/b&gt;&lt;/h2&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;&lt;iframe src=&quot;https://www.youtube.com/embed/KccNgwyyqV4?si=4-nagJZDqk5UYQFS&quot; width=&quot;560&quot; height=&quot;315&quot; frameborder=&quot;&quot; allowfullscreen=&quot;true&quot;&gt;&lt;/iframe&gt;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;h2 data-ke-size=&quot;size26&quot;&gt;&lt;b&gt;4. 벡터의 덧셈에 대한 연산법칙&lt;/b&gt;&lt;/h2&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;&lt;iframe src=&quot;https://www.youtube.com/embed/E-o4r9QcDZs?si=81---c9y-fHy2SGd&quot; width=&quot;560&quot; height=&quot;315&quot; frameborder=&quot;&quot; allowfullscreen=&quot;true&quot;&gt;&lt;/iframe&gt;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;h2 data-ke-size=&quot;size26&quot;&gt;&lt;b&gt;5. 벡터의 뺄셈&lt;/b&gt;&lt;/h2&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;&lt;iframe src=&quot;https://www.youtube.com/embed/EOvVpZ-1_f0?si=7yWCutKcKf_GrzKE&quot; width=&quot;560&quot; height=&quot;315&quot; frameborder=&quot;&quot; allowfullscreen=&quot;true&quot;&gt;&lt;/iframe&gt;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;h2 data-ke-size=&quot;size26&quot;&gt;&lt;b&gt;6. 벡터의 실수배&lt;/b&gt;&lt;/h2&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;&lt;iframe src=&quot;https://www.youtube.com/embed/IYrW_A7oS1A?si=MyOP9T9tMW_LRn60&quot; width=&quot;560&quot; height=&quot;315&quot; frameborder=&quot;&quot; allowfullscreen=&quot;true&quot;&gt;&lt;/iframe&gt;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;h2 data-ke-size=&quot;size26&quot;&gt;&lt;b&gt;7. 벡터의 실수배에 대한 연산법칙&lt;/b&gt;&lt;/h2&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;&lt;iframe src=&quot;https://www.youtube.com/embed/p7vowZId_A4?si=lD2B5lbAaHS4r8SO&quot; width=&quot;560&quot; height=&quot;315&quot; frameborder=&quot;&quot; allowfullscreen=&quot;true&quot;&gt;&lt;/iframe&gt;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;h2 data-ke-size=&quot;size26&quot;&gt;&lt;b&gt;8. 벡터의 평행&lt;/b&gt;&lt;/h2&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;&lt;iframe src=&quot;https://www.youtube.com/embed/qPLtj_HuosE?si=Tj6aEUVC3g-mLDJR&quot; width=&quot;560&quot; height=&quot;315&quot; frameborder=&quot;&quot; allowfullscreen=&quot;true&quot;&gt;&lt;/iframe&gt;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;h2 data-ke-size=&quot;size26&quot;&gt;&lt;b&gt;9. 위치벡터&lt;/b&gt;&lt;/h2&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;&lt;iframe src=&quot;https://www.youtube.com/embed/Kf8noaQCCN8?si=cstoWjBKF-t0gKqw&quot; width=&quot;560&quot; height=&quot;315&quot; frameborder=&quot;&quot; allowfullscreen=&quot;true&quot;&gt;&lt;/iframe&gt;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;h2 data-ke-size=&quot;size26&quot;&gt;&lt;b&gt;10. 평면벡터의 성분&lt;/b&gt;&lt;/h2&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;&lt;iframe src=&quot;https://www.youtube.com/embed/Aa0VPnINW9Y?si=WofoyGtV5gs0ugHA&quot; width=&quot;560&quot; height=&quot;315&quot; frameborder=&quot;&quot; allowfullscreen=&quot;true&quot;&gt;&lt;/iframe&gt;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;h2 data-ke-size=&quot;size26&quot;&gt;&lt;b&gt;11. 공간벡터의 성분&lt;/b&gt;&lt;/h2&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;&lt;iframe src=&quot;https://www.youtube.com/embed/83BP3t7CksU?si=6ZC39QGn-c3IUEUH&quot; width=&quot;560&quot; height=&quot;315&quot; frameborder=&quot;&quot; allowfullscreen=&quot;true&quot;&gt;&lt;/iframe&gt;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;h2 data-ke-size=&quot;size26&quot;&gt;&lt;b&gt;12. 벡터의 성분에 의한 연산&lt;/b&gt;&lt;/h2&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;&lt;iframe src=&quot;https://www.youtube.com/embed/Q61OM7APjUU?si=zP8xEUArwvVedE71&quot; width=&quot;560&quot; height=&quot;315&quot; frameborder=&quot;&quot; allowfullscreen=&quot;true&quot;&gt;&lt;/iframe&gt;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;h2 data-ke-size=&quot;size26&quot;&gt;&lt;b&gt;13. 벡터의 내적&lt;/b&gt;&lt;/h2&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;&lt;iframe src=&quot;https://www.youtube.com/embed/tQhylhd4D4A?si=1f9sedrtRtvulmBk&quot; width=&quot;560&quot; height=&quot;315&quot; frameborder=&quot;&quot; allowfullscreen=&quot;true&quot;&gt;&lt;/iframe&gt;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;h2 data-ke-size=&quot;size26&quot;&gt;&lt;b&gt;14. 성분으로 나타낸 벡터의 내적&lt;/b&gt;&lt;/h2&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;&lt;iframe src=&quot;https://www.youtube.com/embed/J7j98smjKZI?si=9gq8DiaA7ejgR6nR&quot; width=&quot;560&quot; height=&quot;315&quot; frameborder=&quot;&quot; allowfullscreen=&quot;true&quot;&gt;&lt;/iframe&gt;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;h2 data-ke-size=&quot;size26&quot;&gt;&lt;b&gt;15. 벡터의 내적의 성질&lt;/b&gt;&lt;/h2&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;&lt;iframe src=&quot;https://www.youtube.com/embed/Xk8aqUlNveU?si=vBj48qosx6-Wr3bp&quot; width=&quot;560&quot; height=&quot;315&quot; frameborder=&quot;&quot; allowfullscreen=&quot;true&quot;&gt;&lt;/iframe&gt;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;h2 data-ke-size=&quot;size26&quot;&gt;&lt;b&gt;16. 두 벡터가 이루는 각의 크기&lt;/b&gt;&lt;/h2&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;&lt;iframe src=&quot;https://www.youtube.com/embed/wDXZE7wPoxU?si=BZBKQui41Di2exiZ&quot; width=&quot;560&quot; height=&quot;315&quot; frameborder=&quot;&quot; allowfullscreen=&quot;true&quot;&gt;&lt;/iframe&gt;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;h2 data-ke-size=&quot;size26&quot;&gt;&lt;b&gt;17. 벡터의 수직조건과 평행조건&lt;/b&gt;&lt;/h2&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;&lt;iframe src=&quot;https://www.youtube.com/embed/FJHS2gnC8qc?si=q-UNxuEHee0XLuX5&quot; width=&quot;560&quot; height=&quot;315&quot; frameborder=&quot;&quot; allowfullscreen=&quot;true&quot;&gt;&lt;/iframe&gt;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;h2 data-ke-size=&quot;size26&quot;&gt;&lt;b&gt;18. 좌표평면에서 한 점과 방향벡터가 주어진 직선의 방정식&lt;/b&gt;&lt;/h2&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;&lt;iframe src=&quot;https://www.youtube.com/embed/BQ04M65Yo-U?si=7vePQL0h9E9n66SI&quot; width=&quot;560&quot; height=&quot;315&quot; frameborder=&quot;&quot; allowfullscreen=&quot;true&quot;&gt;&lt;/iframe&gt;&lt;/p&gt;
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&lt;h2 data-ke-size=&quot;size26&quot;&gt;&lt;b&gt;19. 좌표공간에서 한 점과 방향벡터가 주어진 직선의 방정식&lt;/b&gt;&lt;/h2&gt;
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&lt;h2 data-ke-size=&quot;size26&quot;&gt;&lt;b&gt;20. 두 점을 지나는 직선의 방정식&lt;/b&gt;&lt;/h2&gt;
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&lt;h2 data-ke-size=&quot;size26&quot;&gt;&lt;b&gt;21. 두 직선이 이루는 각의 크기&lt;/b&gt;&lt;/h2&gt;
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&lt;h2 data-ke-size=&quot;size26&quot;&gt;&lt;b&gt;22. 법선벡터를 이용한 직선의 방정식&lt;/b&gt;&lt;/h2&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;&lt;iframe src=&quot;https://www.youtube.com/embed/jcNVScauB1E?si=B0p6Fk0WZY3B7SqQ&quot; width=&quot;560&quot; height=&quot;315&quot; frameborder=&quot;&quot; allowfullscreen=&quot;true&quot;&gt;&lt;/iframe&gt;&lt;/p&gt;
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&lt;h2 data-ke-size=&quot;size26&quot;&gt;&lt;b&gt;23. 평면의 방정식&lt;/b&gt;&lt;/h2&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;&lt;iframe src=&quot;https://www.youtube.com/embed/R16Ah88WwfI?si=kQcJTImX9E7wve_a&quot; width=&quot;560&quot; height=&quot;315&quot; frameborder=&quot;&quot; allowfullscreen=&quot;true&quot;&gt;&lt;/iframe&gt;&lt;/p&gt;
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&lt;h2 data-ke-size=&quot;size26&quot;&gt;&lt;b&gt;24. 일차방정식 $ax+by+cz+d=0$과 평면&lt;/b&gt;&lt;/h2&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
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&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
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&lt;h2 data-ke-size=&quot;size26&quot;&gt;&lt;b&gt;25. 평면과 평면의 교선 &amp;amp; 직선과 평면의 교점&lt;/b&gt;&lt;/h2&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;&lt;iframe src=&quot;https://www.youtube.com/embed/tpwycbWhXq4?si=I_CV0BKmRIfPugWf&quot; width=&quot;560&quot; height=&quot;315&quot; frameborder=&quot;&quot; allowfullscreen=&quot;true&quot;&gt;&lt;/iframe&gt;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
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&lt;h2 data-ke-size=&quot;size26&quot;&gt;&lt;b&gt;26. 두 평면이 이루는 각의 크기&lt;/b&gt;&lt;/h2&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;&lt;iframe src=&quot;https://www.youtube.com/embed/p4MYEOpM6W0?si=4md9pbprqJYmcZM7&quot; width=&quot;560&quot; height=&quot;315&quot; frameborder=&quot;&quot; allowfullscreen=&quot;true&quot;&gt;&lt;/iframe&gt;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;h2 data-ke-size=&quot;size26&quot;&gt;&lt;b&gt;27. 두 평면의 수직 조건과 평행 조건&lt;/b&gt;&lt;/h2&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;&lt;iframe src=&quot;https://www.youtube.com/embed/FUgBkZj17eg?si=pOTtfQNh2fvjKvX7&quot; width=&quot;560&quot; height=&quot;315&quot; frameborder=&quot;&quot; allowfullscreen=&quot;true&quot;&gt;&lt;/iframe&gt;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;h2 data-ke-size=&quot;size26&quot;&gt;&lt;b&gt;28. 평면과 직선이 이루는 각의 크기&lt;/b&gt;&lt;/h2&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;&lt;iframe src=&quot;https://www.youtube.com/embed/N7EyArlc0Ck?si=JiPlZr5FLUu6AZ6z&quot; width=&quot;560&quot; height=&quot;315&quot; frameborder=&quot;&quot; allowfullscreen=&quot;true&quot;&gt;&lt;/iframe&gt;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;h2 data-ke-size=&quot;size26&quot;&gt;&lt;b&gt;29. 좌표공간에서 점과 평면 사이의 거리&lt;/b&gt;&lt;/h2&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;iframe src=&quot;https://www.youtube.com/embed/hAIUcHWLowk?si=wuzBte32X5xk0NYz&quot; width=&quot;560&quot; height=&quot;315&quot; allow=&quot;accelerometer; autoplay; clipboard-write; encrypted-media; gyroscope; picture-in-picture; web-share&quot; frameborder=&quot;&quot; allowfullscreen=&quot;true&quot;&gt;&lt;/iframe&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
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&lt;h2 data-ke-size=&quot;size26&quot;&gt;&lt;b&gt;30. 벡터를 이용한 구의 방정식&lt;/b&gt;&lt;/h2&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
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&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
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&lt;h2 data-ke-size=&quot;size26&quot;&gt;&lt;b&gt;31. 두 점을 지름의 양 끝 점으로 하는 구의 방정식&lt;/b&gt;&lt;/h2&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
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&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;</description>
      <category>(新 교육과정) 기하 - 개념 및 유형</category>
      <author>수악중독</author>
      <guid isPermaLink="true">https://mathjk.tistory.com/6787</guid>
      <comments>https://mathjk.tistory.com/6787#entry6787comment</comments>
      <pubDate>Sat, 8 Nov 2025 21:25:14 +0900</pubDate>
    </item>
    <item>
      <title>기하 2. 공간도형과 공간좌표</title>
      <link>https://mathjk.tistory.com/6786</link>
      <description>&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;hr contenteditable=&quot;false&quot; data-ke-type=&quot;horizontalRule&quot; data-ke-style=&quot;style7&quot; /&gt;
&lt;h2 style=&quot;text-align: center;&quot; data-ke-size=&quot;size26&quot;&gt;&lt;span style=&quot;color: #ee2323;&quot;&gt;&lt;b&gt;개념정리&lt;/b&gt;&lt;/span&gt;&lt;/h2&gt;
&lt;hr contenteditable=&quot;false&quot; data-ke-type=&quot;horizontalRule&quot; data-ke-style=&quot;style7&quot; /&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;h2 data-ke-size=&quot;size26&quot;&gt;&lt;b&gt;1. 평면의 결정 조건&lt;/b&gt;&lt;/h2&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;&lt;iframe src=&quot;https://www.youtube.com/embed/QFHtQseuQzU?si=d2RbhyXT8BqiEK-B&quot; width=&quot;560&quot; height=&quot;315&quot; frameborder=&quot;&quot; allowfullscreen=&quot;true&quot;&gt;&lt;/iframe&gt;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;h2 data-ke-size=&quot;size26&quot;&gt;&lt;b&gt;2. 공간에서 두 직선의 위치 관계&lt;/b&gt;&lt;/h2&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;&lt;iframe src=&quot;https://www.youtube.com/embed/GTAKTQof_3E?si=jqnwY0e3HuDJyh32&quot; width=&quot;560&quot; height=&quot;315&quot; frameborder=&quot;&quot; allowfullscreen=&quot;true&quot;&gt;&lt;/iframe&gt;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;h2 data-ke-size=&quot;size26&quot;&gt;&lt;b&gt;3. 직선과 평면의 위치 관계&lt;/b&gt;&lt;/h2&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;&lt;iframe src=&quot;https://www.youtube.com/embed/3rFF3fod_f8?si=u0aWgR1uyMZvrkE6&quot; width=&quot;560&quot; height=&quot;315&quot; frameborder=&quot;&quot; allowfullscreen=&quot;true&quot;&gt;&lt;/iframe&gt;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;h2 data-ke-size=&quot;size26&quot;&gt;&lt;b&gt;4. 평면과 평면의 위치 관계&lt;/b&gt;&lt;/h2&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;&lt;iframe src=&quot;https://www.youtube.com/embed/kasz-xd3GC8?si=9yppdsVxPfpL5CfL&quot; width=&quot;560&quot; height=&quot;315&quot; frameborder=&quot;&quot; allowfullscreen=&quot;true&quot;&gt;&lt;/iframe&gt;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;h2 data-ke-size=&quot;size26&quot;&gt;&lt;b&gt;5. 직선과 평면의 평행에 대한 성질&lt;/b&gt;&lt;/h2&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;&lt;iframe src=&quot;https://www.youtube.com/embed/YPadSZ_ftKQ?si=diGnoIBucoHuT5BZ&quot; width=&quot;560&quot; height=&quot;315&quot; frameborder=&quot;&quot; allowfullscreen=&quot;true&quot;&gt;&lt;/iframe&gt;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;h2 data-ke-size=&quot;size26&quot;&gt;&lt;b&gt;6. 두 직선이 이루는 각&lt;/b&gt;&lt;/h2&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;&lt;iframe src=&quot;https://www.youtube.com/embed/QmmGhTg0O4Y?si=VuhTa0GQ3b41M1zH&quot; width=&quot;560&quot; height=&quot;315&quot; frameborder=&quot;&quot; allowfullscreen=&quot;true&quot;&gt;&lt;/iframe&gt;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;h2 data-ke-size=&quot;size26&quot;&gt;&lt;b&gt;7. 직선과 평면의 수직&lt;/b&gt;&lt;/h2&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;&lt;iframe src=&quot;https://www.youtube.com/embed/ENCoVeqjjKc?si=W2iABCCr-48ImRz9&quot; width=&quot;560&quot; height=&quot;315&quot; frameborder=&quot;&quot; allowfullscreen=&quot;true&quot;&gt;&lt;/iframe&gt;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;h2 data-ke-size=&quot;size26&quot;&gt;&lt;b&gt;8. 삼수선의 정리&lt;/b&gt;&lt;/h2&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;&lt;iframe src=&quot;https://www.youtube.com/embed/oDpVD39KZTw?si=Iw_ZalF0KhupmQWm&quot; width=&quot;560&quot; height=&quot;315&quot; frameborder=&quot;&quot; allowfullscreen=&quot;true&quot;&gt;&lt;/iframe&gt;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;h2 data-ke-size=&quot;size26&quot;&gt;&lt;b&gt;9. 이면각&lt;/b&gt;&lt;/h2&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;&lt;iframe src=&quot;https://www.youtube.com/embed/zxxArwsqFh8?si=WXxfkmZ_MLM1Y1MF&quot; width=&quot;560&quot; height=&quot;315&quot; frameborder=&quot;&quot; allowfullscreen=&quot;true&quot;&gt;&lt;/iframe&gt;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;h2 data-ke-size=&quot;size26&quot;&gt;&lt;b&gt;10. 정사영&lt;/b&gt;&lt;/h2&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;&lt;iframe src=&quot;https://www.youtube.com/embed/1vX6CAkHx2s?si=SeQcqavOvvn1QTtO&quot; width=&quot;560&quot; height=&quot;315&quot; frameborder=&quot;&quot; allowfullscreen=&quot;true&quot;&gt;&lt;/iframe&gt;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;h2 data-ke-size=&quot;size26&quot;&gt;&lt;b&gt;11. 직선과 평면이 이루는 각&lt;/b&gt;&lt;/h2&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
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&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;h2 data-ke-size=&quot;size26&quot;&gt;&lt;b&gt;12. 정사영의 길이&lt;/b&gt;&lt;/h2&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;&lt;iframe src=&quot;https://www.youtube.com/embed/jx-XIoZkNfI?si=mSM6hqNhq8K8drl0&quot; width=&quot;560&quot; height=&quot;315&quot; frameborder=&quot;&quot; allowfullscreen=&quot;true&quot;&gt;&lt;/iframe&gt;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;h2 data-ke-size=&quot;size26&quot;&gt;&lt;b&gt;13. 정사영의 넓이&lt;/b&gt;&lt;/h2&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;&lt;iframe src=&quot;https://www.youtube.com/embed/1x-Z4sP1Wcg?si=HNQ5qIeI1YcvvoKQ&quot; width=&quot;560&quot; height=&quot;315&quot; frameborder=&quot;&quot; allowfullscreen=&quot;true&quot;&gt;&lt;/iframe&gt;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
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&lt;h2 data-ke-size=&quot;size26&quot;&gt;&lt;b&gt;14. 공간에서의 점의 좌표&lt;/b&gt;&lt;/h2&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
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&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
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&lt;h2 data-ke-size=&quot;size26&quot;&gt;&lt;b&gt;15. 좌표공간에서 두 점 사이의 거리&lt;/b&gt;&lt;/h2&gt;
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&lt;h2 data-ke-size=&quot;size26&quot;&gt;&lt;b&gt;16. 좌표공간에서 선분의 내분점&lt;/b&gt;&lt;/h2&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;iframe src=&quot;https://www.youtube.com/embed/DVn5IZpYabM?si=TFNlx7d2K8un8DWc&quot; width=&quot;560&quot; height=&quot;315&quot; allow=&quot;accelerometer; autoplay; clipboard-write; encrypted-media; gyroscope; picture-in-picture; web-share&quot; frameborder=&quot;&quot; allowfullscreen=&quot;true&quot;&gt;&lt;/iframe&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;h2 data-ke-size=&quot;size26&quot;&gt;&lt;b&gt;17. 구의 방정식&lt;/b&gt;&lt;/h2&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;iframe src=&quot;https://www.youtube.com/embed/3HfGUNDuYxo?si=2eKbJDoUj9yZJsvr&quot; width=&quot;560&quot; height=&quot;315&quot; allow=&quot;accelerometer; autoplay; clipboard-write; encrypted-media; gyroscope; picture-in-picture; web-share&quot; frameborder=&quot;&quot; allowfullscreen=&quot;true&quot;&gt;&lt;/iframe&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;</description>
      <category>(新 교육과정) 기하 - 개념 및 유형</category>
      <author>수악중독</author>
      <guid isPermaLink="true">https://mathjk.tistory.com/6786</guid>
      <comments>https://mathjk.tistory.com/6786#entry6786comment</comments>
      <pubDate>Sun, 2 Nov 2025 08:34:43 +0900</pubDate>
    </item>
    <item>
      <title>기하 1. 이차곡선</title>
      <link>https://mathjk.tistory.com/6785</link>
      <description>&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;hr contenteditable=&quot;false&quot; data-ke-type=&quot;horizontalRule&quot; data-ke-style=&quot;style7&quot; /&gt;
&lt;h2 style=&quot;text-align: center;&quot; data-ke-size=&quot;size26&quot;&gt;&lt;span style=&quot;color: #ee2323;&quot;&gt;&lt;b&gt;개념정리&lt;/b&gt;&lt;/span&gt;&lt;/h2&gt;
&lt;hr contenteditable=&quot;false&quot; data-ke-type=&quot;horizontalRule&quot; data-ke-style=&quot;style7&quot; /&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;h2 data-ke-size=&quot;size26&quot;&gt;&lt;b&gt;1. 포물선의 정의&lt;/b&gt;&lt;/h2&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;&lt;iframe src=&quot;https://www.youtube.com/embed/7cynhZXGGM4?si=AUytJstBtWMC6NwH&quot; width=&quot;560&quot; height=&quot;315&quot; frameborder=&quot;&quot; allowfullscreen=&quot;true&quot;&gt;&lt;/iframe&gt;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;h2 data-ke-size=&quot;size26&quot;&gt;&lt;b&gt;2. 포물선의 방정식&lt;/b&gt;&lt;/h2&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;&lt;iframe src=&quot;https://www.youtube.com/embed/6wETQ_BC7b0?si=IkPA4VImRLcn2vCN&quot; width=&quot;560&quot; height=&quot;315&quot; frameborder=&quot;&quot; allowfullscreen=&quot;true&quot;&gt;&lt;/iframe&gt;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;h2 data-ke-size=&quot;size26&quot;&gt;&lt;b&gt;3. 포물선의 평행이동&lt;/b&gt;&lt;/h2&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;&lt;iframe src=&quot;https://www.youtube.com/embed/okquo3bSsa8?si=xQIXQkEoEhR0OzIU&quot; width=&quot;560&quot; height=&quot;315&quot; frameborder=&quot;&quot; allowfullscreen=&quot;true&quot;&gt;&lt;/iframe&gt;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;h2 data-ke-size=&quot;size26&quot;&gt;&lt;b&gt;4. 포물선과 직선의 위치 관계&lt;/b&gt;&lt;/h2&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;&lt;iframe src=&quot;https://www.youtube.com/embed/GNgvRzCn-Dc?si=VX6-FS1cMwnXkg71&quot; width=&quot;560&quot; height=&quot;315&quot; frameborder=&quot;&quot; allowfullscreen=&quot;true&quot;&gt;&lt;/iframe&gt;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;h2 data-ke-size=&quot;size26&quot;&gt;&lt;b&gt;5. 포물선의 접선&lt;/b&gt;&lt;/h2&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;&lt;iframe src=&quot;https://www.youtube.com/embed/Yf9Rh6CBdXo?si=8t7RcCtAsEOQhU4H&quot; width=&quot;560&quot; height=&quot;315&quot; frameborder=&quot;&quot; allowfullscreen=&quot;true&quot;&gt;&lt;/iframe&gt;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;h2 data-ke-size=&quot;size26&quot;&gt;&lt;b&gt;6. 타원의 정의&lt;/b&gt;&lt;/h2&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;&lt;iframe src=&quot;https://www.youtube.com/embed/KjRFwZZ1NEU?si=tchXeB7wj6WBTHLL&quot; width=&quot;560&quot; height=&quot;315&quot; frameborder=&quot;&quot; allowfullscreen=&quot;true&quot;&gt;&lt;/iframe&gt;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;h2 data-ke-size=&quot;size26&quot;&gt;&lt;b&gt;7. 타원의 방정식&lt;/b&gt;&lt;/h2&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;&lt;iframe src=&quot;https://www.youtube.com/embed/ZoRsUDeXQDU?si=IAnAq-i7GYLlLGu7&quot; width=&quot;560&quot; height=&quot;315&quot; frameborder=&quot;&quot; allowfullscreen=&quot;true&quot;&gt;&lt;/iframe&gt;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;h2 data-ke-size=&quot;size26&quot;&gt;&lt;b&gt;8. 타원의 평행이동&lt;/b&gt;&lt;/h2&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;&lt;iframe src=&quot;https://www.youtube.com/embed/XvOQ1v8utyg?si=mgEyZYagDb55VQJB&quot; width=&quot;560&quot; height=&quot;315&quot; frameborder=&quot;&quot; allowfullscreen=&quot;true&quot;&gt;&lt;/iframe&gt;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;h2 data-ke-size=&quot;size26&quot;&gt;&lt;b&gt;9. 타원과 직선의 위치 관계&lt;/b&gt;&lt;/h2&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;&lt;iframe src=&quot;https://www.youtube.com/embed/4iFRbwvpU7A?si=G2DxfOxJ9QgRN6yu&quot; width=&quot;560&quot; height=&quot;315&quot; frameborder=&quot;&quot; allowfullscreen=&quot;true&quot;&gt;&lt;/iframe&gt;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;h2 data-ke-size=&quot;size26&quot;&gt;&lt;b&gt;10. 타원의 접선&lt;/b&gt;&lt;/h2&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;&lt;iframe src=&quot;https://www.youtube.com/embed/iXehfF9goXA?si=aaPqyHE6KLEjXAVe&quot; width=&quot;560&quot; height=&quot;315&quot; frameborder=&quot;&quot; allowfullscreen=&quot;true&quot;&gt;&lt;/iframe&gt;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;h2 data-ke-size=&quot;size26&quot;&gt;&lt;b&gt;11. 쌍곡선의 정의&lt;/b&gt;&lt;/h2&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;&lt;iframe src=&quot;https://www.youtube.com/embed/HTU-RTnecsQ?si=LdMM2TTRClUv_E_d&quot; width=&quot;560&quot; height=&quot;315&quot; frameborder=&quot;&quot; allowfullscreen=&quot;true&quot;&gt;&lt;/iframe&gt;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;h2 data-ke-size=&quot;size26&quot;&gt;&lt;b&gt;12. 쌍곡선의 방정식&lt;/b&gt;&lt;/h2&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;&lt;iframe src=&quot;https://www.youtube.com/embed/2qDf1b5X4V8?si=_C8lle8HpkRYKq6S&quot; width=&quot;560&quot; height=&quot;315&quot; frameborder=&quot;&quot; allowfullscreen=&quot;true&quot;&gt;&lt;/iframe&gt;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;h2 data-ke-size=&quot;size26&quot;&gt;&lt;b&gt;13. 쌍곡선의 점근선&lt;/b&gt;&lt;/h2&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;&lt;iframe src=&quot;https://www.youtube.com/embed/C1O5VuT_bFQ?si=kobebij4muL4a99g&quot; width=&quot;560&quot; height=&quot;315&quot; frameborder=&quot;&quot; allowfullscreen=&quot;true&quot;&gt;&lt;/iframe&gt;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;h2 data-ke-size=&quot;size26&quot;&gt;&lt;b&gt;14. 쌍곡선의 평행이동&lt;/b&gt;&lt;/h2&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;iframe src=&quot;https://www.youtube.com/embed/urtIpgC69NU?si=se9FdI1uU3knsgNx&quot; width=&quot;560&quot; height=&quot;315&quot; allow=&quot;accelerometer; autoplay; clipboard-write; encrypted-media; gyroscope; picture-in-picture; web-share&quot; frameborder=&quot;&quot; allowfullscreen=&quot;true&quot;&gt;&lt;/iframe&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;h2 data-ke-size=&quot;size26&quot;&gt;&lt;b&gt;15. 쌍곡선과 직선의 위치 관계&lt;/b&gt;&lt;/h2&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;iframe src=&quot;https://www.youtube.com/embed/WA5BjzcbiTk?si=r8neLF8GmYlNChJF&quot; width=&quot;560&quot; height=&quot;315&quot; allow=&quot;accelerometer; autoplay; clipboard-write; encrypted-media; gyroscope; picture-in-picture; web-share&quot; frameborder=&quot;&quot; allowfullscreen=&quot;true&quot;&gt;&lt;/iframe&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;h2 data-ke-size=&quot;size26&quot;&gt;&lt;b&gt;16. 싸옥선의 접선&lt;/b&gt;&lt;/h2&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;iframe src=&quot;https://www.youtube.com/embed/vN1gbhwW9Mg?si=o5bo1fm0krnWFpAa&quot; width=&quot;560&quot; height=&quot;315&quot; allow=&quot;accelerometer; autoplay; clipboard-write; encrypted-media; gyroscope; picture-in-picture; web-share&quot; frameborder=&quot;&quot; allowfullscreen=&quot;true&quot;&gt;&lt;/iframe&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;h2 data-ke-size=&quot;size26&quot;&gt;&lt;b&gt;17. 이차곡선&lt;/b&gt;&lt;/h2&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;iframe src=&quot;https://www.youtube.com/embed/vN1gbhwW9Mg?si=o5bo1fm0krnWFpAa&quot; width=&quot;560&quot; height=&quot;315&quot; allow=&quot;accelerometer; autoplay; clipboard-write; encrypted-media; gyroscope; picture-in-picture; web-share&quot; frameborder=&quot;&quot; allowfullscreen=&quot;true&quot;&gt;&lt;/iframe&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;</description>
      <category>(新 교육과정) 기하 - 개념 및 유형</category>
      <author>수악중독</author>
      <guid isPermaLink="true">https://mathjk.tistory.com/6785</guid>
      <comments>https://mathjk.tistory.com/6785#entry6785comment</comments>
      <pubDate>Tue, 28 Oct 2025 07:32:28 +0900</pubDate>
    </item>
    <item>
      <title>대칭이동과 선분의 길이의 합의 최솟값_난이도 중하 (2025년 10월 고1 14번)</title>
      <link>https://mathjk.tistory.com/6784</link>
      <description>&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;좌표평면 위에 두 점 $\mathrm{A}(-3,\; 2)$, $\mathrm{B}(2, \;6)$이 있다. $\overline{\mathrm{PQ}}=1$인 $x$축 위의 두 점 $\mathrm{P, \;Q}$에 대하여 $\overline{\mathrm{AP}} + \overline{\mathrm{QB}}$의 최솟값은?&amp;nbsp;&amp;nbsp;&lt;br /&gt;(단, 점 $\mathrm{P}$의 $x$좌표는 점 $\mathrm{Q}$의 $x$좌표보다 작다.)&lt;br /&gt;&lt;br /&gt;① $2\sqrt{17}$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;② $6\sqrt{2}$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;③ $2\sqrt{19}$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;④ $4\sqrt{5}$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;⑤ $2\sqrt{21}$&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;div data-ke-type=&quot;moreLess&quot; data-text-more=&quot;풀이보기&quot; data-text-less=&quot;풀이닫기&quot;&gt;&lt;a class=&quot;btn-toggle-moreless&quot;&gt;더보기&lt;/a&gt;
&lt;div class=&quot;moreless-content&quot;&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&lt;span style=&quot;color: #ee2323;&quot;&gt;&lt;b&gt;정답 ④&lt;/b&gt;&lt;/span&gt;&lt;/p&gt;
&lt;figure class=&quot;imageblock alignCenter&quot; data-ke-mobileStyle=&quot;widthOrigin&quot; data-filename=&quot;고1-14번.png&quot; data-origin-width=&quot;2480&quot; data-origin-height=&quot;1492&quot;&gt;&lt;span data-url=&quot;https://blog.kakaocdn.net/dn/bep2kU/dJMb80OC0HW/6yc4qiTwCZe01CzLkXhUsk/img.png&quot; data-phocus=&quot;https://blog.kakaocdn.net/dn/bep2kU/dJMb80OC0HW/6yc4qiTwCZe01CzLkXhUsk/img.png&quot;&gt;&lt;img src=&quot;https://blog.kakaocdn.net/dn/bep2kU/dJMb80OC0HW/6yc4qiTwCZe01CzLkXhUsk/img.png&quot; srcset=&quot;https://img1.daumcdn.net/thumb/R1280x0/?scode=mtistory2&amp;fname=https%3A%2F%2Fblog.kakaocdn.net%2Fdn%2Fbep2kU%2FdJMb80OC0HW%2F6yc4qiTwCZe01CzLkXhUsk%2Fimg.png&quot; onerror=&quot;this.onerror=null; this.src='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png'; this.srcset='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png';&quot; loading=&quot;lazy&quot; width=&quot;2480&quot; height=&quot;1492&quot; data-filename=&quot;고1-14번.png&quot; data-origin-width=&quot;2480&quot; data-origin-height=&quot;1492&quot;/&gt;&lt;/span&gt;&lt;/figure&gt;
&lt;/div&gt;
&lt;/div&gt;</description>
      <category>(新 교육과정) 공통수학 - 문제풀이/도형의 방정식</category>
      <author>수악중독</author>
      <guid isPermaLink="true">https://mathjk.tistory.com/6784</guid>
      <comments>https://mathjk.tistory.com/6784#entry6784comment</comments>
      <pubDate>Fri, 24 Oct 2025 06:27:58 +0900</pubDate>
    </item>
    <item>
      <title>행렬의 곱셈_난이도 중하 (2025년 10월 고1 15번)</title>
      <link>https://mathjk.tistory.com/6783</link>
      <description>&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;세 이차정사각행렬&amp;nbsp; $A=\begin{pmatrix}0 &amp;amp; 0 \\6 &amp;amp; 0\end{pmatrix}$, $B$, $C$가&amp;nbsp;다음&amp;nbsp;조건을&amp;nbsp;만족시킨다.&amp;nbsp;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;div class=&quot;txc-textbox&quot; style=&quot;background-color: #dbe8fb; padding: 10px; border: 1px solid #dbe8fb;&quot;&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;(가)&amp;nbsp;$AB&amp;nbsp;=&amp;nbsp;CA&amp;nbsp;=&amp;nbsp;O$&amp;nbsp;&amp;nbsp;&lt;br /&gt;(나) 행렬 $B$의 모든 성분의 합이 $3$이고, 행렬 $C$의 $(1,\;1)$ 성분과 $(2,\;1)$ 성분이 같다.&amp;nbsp;&amp;nbsp;&lt;/p&gt;
&lt;/div&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;$BC = A$일 때, 행렬 $C$의 모든 성분의 합은? (단, $O$는 영행렬이다.)&amp;nbsp;&lt;br /&gt;&lt;br /&gt;①&amp;nbsp;$3$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;②&amp;nbsp;$4$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;③&amp;nbsp;$5$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;④&amp;nbsp;$6$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;⑤&amp;nbsp;$7$&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;div data-ke-type=&quot;moreLess&quot; data-text-more=&quot;풀이보기&quot; data-text-less=&quot;풀이닫기&quot;&gt;&lt;a class=&quot;btn-toggle-moreless&quot;&gt;더보기&lt;/a&gt;
&lt;div class=&quot;moreless-content&quot;&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&lt;span style=&quot;color: #ee2323;&quot;&gt;&lt;b&gt;정답 ②&amp;nbsp;&lt;/b&gt;&lt;/span&gt;&lt;/p&gt;
&lt;figure class=&quot;imageblock alignCenter&quot; data-ke-mobileStyle=&quot;widthOrigin&quot; data-filename=&quot;고1-15번.png&quot; data-origin-width=&quot;2480&quot; data-origin-height=&quot;719&quot;&gt;&lt;span data-url=&quot;https://blog.kakaocdn.net/dn/w1AZy/dJMb9WrUaFE/yjwwYdKAiQnxAvDhYw51g0/img.png&quot; data-phocus=&quot;https://blog.kakaocdn.net/dn/w1AZy/dJMb9WrUaFE/yjwwYdKAiQnxAvDhYw51g0/img.png&quot;&gt;&lt;img src=&quot;https://blog.kakaocdn.net/dn/w1AZy/dJMb9WrUaFE/yjwwYdKAiQnxAvDhYw51g0/img.png&quot; srcset=&quot;https://img1.daumcdn.net/thumb/R1280x0/?scode=mtistory2&amp;fname=https%3A%2F%2Fblog.kakaocdn.net%2Fdn%2Fw1AZy%2FdJMb9WrUaFE%2FyjwwYdKAiQnxAvDhYw51g0%2Fimg.png&quot; onerror=&quot;this.onerror=null; this.src='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png'; this.srcset='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png';&quot; loading=&quot;lazy&quot; width=&quot;2480&quot; height=&quot;719&quot; data-filename=&quot;고1-15번.png&quot; data-origin-width=&quot;2480&quot; data-origin-height=&quot;719&quot;/&gt;&lt;/span&gt;&lt;/figure&gt;
&lt;/div&gt;
&lt;/div&gt;</description>
      <category>(新 교육과정) 공통수학 - 문제풀이/행렬</category>
      <author>수악중독</author>
      <guid isPermaLink="true">https://mathjk.tistory.com/6783</guid>
      <comments>https://mathjk.tistory.com/6783#entry6783comment</comments>
      <pubDate>Fri, 24 Oct 2025 06:21:24 +0900</pubDate>
    </item>
    <item>
      <title>순열과 조합_이웃하면 안되는 경우_난이도 중 (2025년 10월 고1 16번)</title>
      <link>https://mathjk.tistory.com/6782</link>
      <description>&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;$1$학년 학생 $3$명, $2$학년 학생 $2$명, $3$학년 학생 $1$명이 있다.&amp;nbsp;&amp;nbsp;이 $6$명의 학생 중에서 $5$명의 학생을 선택하고 이 $5$명의 학생이 모두 한 번씩 발표하도록 순서를 정하려고 할 때, $1$학년 학생끼리는 연속해서 발표하지 않도록 순서를 정하는 경우의 수는?&amp;nbsp;&amp;nbsp;(단, 발표는 한 명씩 한다.)&lt;br /&gt;&lt;br /&gt;① $228$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;② $234$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;③ $240$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;④ $246$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;⑤ $252$&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;div data-ke-type=&quot;moreLess&quot; data-text-more=&quot;풀이보기&quot; data-text-less=&quot;풀이닫기&quot;&gt;&lt;a class=&quot;btn-toggle-moreless&quot;&gt;더보기&lt;/a&gt;
&lt;div class=&quot;moreless-content&quot;&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&lt;span style=&quot;color: #ee2323;&quot;&gt;&lt;b&gt;정답 ⑤&lt;/b&gt;&lt;/span&gt;&lt;/p&gt;
&lt;figure class=&quot;imageblock alignCenter&quot; data-ke-mobileStyle=&quot;widthOrigin&quot; data-filename=&quot;고1-16번.png&quot; data-origin-width=&quot;2472&quot; data-origin-height=&quot;1361&quot;&gt;&lt;span data-url=&quot;https://blog.kakaocdn.net/dn/nta0e/dJMb9cuK0aR/EnJzDmwzibKWMMKHe5z9d0/img.png&quot; data-phocus=&quot;https://blog.kakaocdn.net/dn/nta0e/dJMb9cuK0aR/EnJzDmwzibKWMMKHe5z9d0/img.png&quot;&gt;&lt;img src=&quot;https://blog.kakaocdn.net/dn/nta0e/dJMb9cuK0aR/EnJzDmwzibKWMMKHe5z9d0/img.png&quot; srcset=&quot;https://img1.daumcdn.net/thumb/R1280x0/?scode=mtistory2&amp;fname=https%3A%2F%2Fblog.kakaocdn.net%2Fdn%2Fnta0e%2FdJMb9cuK0aR%2FEnJzDmwzibKWMMKHe5z9d0%2Fimg.png&quot; onerror=&quot;this.onerror=null; this.src='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png'; this.srcset='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png';&quot; loading=&quot;lazy&quot; width=&quot;2472&quot; height=&quot;1361&quot; data-filename=&quot;고1-16번.png&quot; data-origin-width=&quot;2472&quot; data-origin-height=&quot;1361&quot;/&gt;&lt;/span&gt;&lt;/figure&gt;
&lt;/div&gt;
&lt;/div&gt;</description>
      <category>(新 교육과정) 공통수학 - 문제풀이/경우의 수</category>
      <author>수악중독</author>
      <guid isPermaLink="true">https://mathjk.tistory.com/6782</guid>
      <comments>https://mathjk.tistory.com/6782#entry6782comment</comments>
      <pubDate>Fri, 24 Oct 2025 06:16:54 +0900</pubDate>
    </item>
    <item>
      <title>이차함수의 최대와 최소_난이도 중 (2025년 10월 고1 17번)</title>
      <link>https://mathjk.tistory.com/6781</link>
      <description>&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;양수 $a$에 대하여 $0 \le x \le a$에서 이차함수&amp;nbsp;$f(x)&amp;nbsp;=&amp;nbsp;-2x^2&amp;nbsp;+&amp;nbsp;16x&amp;nbsp;-&amp;nbsp;7$의&amp;nbsp;최댓값과&amp;nbsp;최솟값의&amp;nbsp;합이&amp;nbsp;$0$이&amp;nbsp;되도록&amp;nbsp;하는&amp;nbsp;&amp;nbsp;&lt;br /&gt;모든 $a$의 값의 합은?&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&lt;br /&gt;① $\dfrac{17}{2}$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;② $9$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;③ $\dfrac{19}{2}$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;④ $10$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;⑤ $\dfrac{21}{2}$&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;div data-ke-type=&quot;moreLess&quot; data-text-more=&quot;풀이보기&quot; data-text-less=&quot;풀이닫기&quot;&gt;&lt;a class=&quot;btn-toggle-moreless&quot;&gt;더보기&lt;/a&gt;
&lt;div class=&quot;moreless-content&quot;&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&lt;span style=&quot;color: #ee2323;&quot;&gt;&lt;b&gt;정답 ④&lt;/b&gt;&lt;/span&gt;&lt;/p&gt;
&lt;figure class=&quot;imageblock alignCenter&quot; data-ke-mobileStyle=&quot;widthOrigin&quot; data-filename=&quot;고1-17번.png&quot; data-origin-width=&quot;2471&quot; data-origin-height=&quot;1654&quot;&gt;&lt;span data-url=&quot;https://blog.kakaocdn.net/dn/biBD8O/dJMb81msV3M/HEfCDXqvnbRqntVhcIDI4k/img.png&quot; data-phocus=&quot;https://blog.kakaocdn.net/dn/biBD8O/dJMb81msV3M/HEfCDXqvnbRqntVhcIDI4k/img.png&quot;&gt;&lt;img src=&quot;https://blog.kakaocdn.net/dn/biBD8O/dJMb81msV3M/HEfCDXqvnbRqntVhcIDI4k/img.png&quot; srcset=&quot;https://img1.daumcdn.net/thumb/R1280x0/?scode=mtistory2&amp;fname=https%3A%2F%2Fblog.kakaocdn.net%2Fdn%2FbiBD8O%2FdJMb81msV3M%2FHEfCDXqvnbRqntVhcIDI4k%2Fimg.png&quot; onerror=&quot;this.onerror=null; this.src='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png'; this.srcset='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png';&quot; loading=&quot;lazy&quot; width=&quot;2471&quot; height=&quot;1654&quot; data-filename=&quot;고1-17번.png&quot; data-origin-width=&quot;2471&quot; data-origin-height=&quot;1654&quot;/&gt;&lt;/span&gt;&lt;/figure&gt;
&lt;/div&gt;
&lt;/div&gt;</description>
      <category>(新 교육과정) 공통수학 - 문제풀이/방정식과 부등식</category>
      <author>수악중독</author>
      <guid isPermaLink="true">https://mathjk.tistory.com/6781</guid>
      <comments>https://mathjk.tistory.com/6781#entry6781comment</comments>
      <pubDate>Fri, 24 Oct 2025 06:12:52 +0900</pubDate>
    </item>
    <item>
      <title>이차방정식의 판별식&amp;amp;고차식의 인수분해_난이도 중 (2025년 10월 고1 18번)</title>
      <link>https://mathjk.tistory.com/6780</link>
      <description>&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;$x$에 대한 다항식&amp;nbsp;&amp;nbsp;$x^3 + (2a+3)x^2 + (3a+5)x + a + 3$이 $(x+b)(x+c)^2$로 인수분해되도록 하는 세 실수 $a, \;b, \;c$에 대하여, $a+b+c$의 최댓값을 $M$, 최솟값을 $m$이라 할 때, $M+m$의 값은?&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&lt;br /&gt;① $5$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;② $6$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;③ $7$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;④ $8$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;⑤ $9$&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;div data-ke-type=&quot;moreLess&quot; data-text-more=&quot;풀이보기&quot; data-text-less=&quot;풀이닫기&quot;&gt;&lt;a class=&quot;btn-toggle-moreless&quot;&gt;더보기&lt;/a&gt;
&lt;div class=&quot;moreless-content&quot;&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&lt;span style=&quot;color: #ee2323;&quot;&gt;&lt;b&gt;정답 ②&lt;/b&gt;&lt;/span&gt;&lt;/p&gt;
&lt;figure class=&quot;imageblock alignCenter&quot; data-ke-mobileStyle=&quot;widthOrigin&quot; data-filename=&quot;고1-18번.png&quot; data-origin-width=&quot;2473&quot; data-origin-height=&quot;2272&quot;&gt;&lt;span data-url=&quot;https://blog.kakaocdn.net/dn/kSWWB/dJMb9YJ1INJ/5pqiSzdMrMIqWSPXI0Io4k/img.png&quot; data-phocus=&quot;https://blog.kakaocdn.net/dn/kSWWB/dJMb9YJ1INJ/5pqiSzdMrMIqWSPXI0Io4k/img.png&quot;&gt;&lt;img src=&quot;https://blog.kakaocdn.net/dn/kSWWB/dJMb9YJ1INJ/5pqiSzdMrMIqWSPXI0Io4k/img.png&quot; srcset=&quot;https://img1.daumcdn.net/thumb/R1280x0/?scode=mtistory2&amp;fname=https%3A%2F%2Fblog.kakaocdn.net%2Fdn%2FkSWWB%2FdJMb9YJ1INJ%2F5pqiSzdMrMIqWSPXI0Io4k%2Fimg.png&quot; onerror=&quot;this.onerror=null; this.src='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png'; this.srcset='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png';&quot; loading=&quot;lazy&quot; width=&quot;2473&quot; height=&quot;2272&quot; data-filename=&quot;고1-18번.png&quot; data-origin-width=&quot;2473&quot; data-origin-height=&quot;2272&quot;/&gt;&lt;/span&gt;&lt;/figure&gt;
&lt;/div&gt;
&lt;/div&gt;</description>
      <category>(新 교육과정) 공통수학 - 문제풀이/방정식과 부등식</category>
      <author>수악중독</author>
      <guid isPermaLink="true">https://mathjk.tistory.com/6780</guid>
      <comments>https://mathjk.tistory.com/6780#entry6780comment</comments>
      <pubDate>Fri, 24 Oct 2025 06:11:01 +0900</pubDate>
    </item>
    <item>
      <title>나머지 정리_난이도 중 (2025년 10월 고1 19번)</title>
      <link>https://mathjk.tistory.com/6779</link>
      <description>&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;최고차항의 계수가 $1$인 삼차다항식 $f(x)$와 모든 항의 계수가 실수인 두 다항식 $P(x), \;Q(x)$가 다음 조건을 만족시킨다.&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;div class=&quot;txc-textbox&quot; style=&quot;background-color: #dbe8fb; padding: 10px; border: 1px solid #dbe8fb;&quot;&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;(가)&amp;nbsp;$f(x)$를&amp;nbsp;$P(x)$로&amp;nbsp;나누었을&amp;nbsp;때의&amp;nbsp;몫은&amp;nbsp;$Q(x)$이고,&amp;nbsp;나머지는&amp;nbsp;$P(x)&amp;nbsp;+&amp;nbsp;\{Q(x)\}^2$이다.&amp;nbsp;&amp;nbsp;&lt;br /&gt;(나)&amp;nbsp;$f(x)$를&amp;nbsp;$Q(x)$로&amp;nbsp;나누었을&amp;nbsp;때의&amp;nbsp;몫은&amp;nbsp;$P(x)$이고,&amp;nbsp;나머지는&amp;nbsp;$P(x)&amp;nbsp;+&amp;nbsp;\{Q(x)\}^2$이다.&amp;nbsp;&amp;nbsp;&lt;/p&gt;
&lt;/div&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&lt;br /&gt;$P(0) = -2$, $Q(0) = 1$일 때, $f(2)$의 값은?&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&lt;br /&gt;① $-3$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;② $-2$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;③ $-1$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;④ $0$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;⑤ $1$&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;div data-ke-type=&quot;moreLess&quot; data-text-more=&quot;풀이보기&quot; data-text-less=&quot;풀이닫기&quot;&gt;&lt;a class=&quot;btn-toggle-moreless&quot;&gt;더보기&lt;/a&gt;
&lt;div class=&quot;moreless-content&quot;&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&lt;span style=&quot;color: #ee2323;&quot;&gt;&lt;b&gt;정답 ⑤&lt;/b&gt;&lt;/span&gt;&lt;/p&gt;
&lt;figure class=&quot;imageblock alignCenter&quot; data-ke-mobileStyle=&quot;widthOrigin&quot; data-filename=&quot;고1-19번.png&quot; data-origin-width=&quot;1700&quot; data-origin-height=&quot;773&quot;&gt;&lt;span data-url=&quot;https://blog.kakaocdn.net/dn/cR797z/dJMb9i2Og47/s5kcPoupwXsyI6PqrPJw6K/img.png&quot; data-phocus=&quot;https://blog.kakaocdn.net/dn/cR797z/dJMb9i2Og47/s5kcPoupwXsyI6PqrPJw6K/img.png&quot;&gt;&lt;img src=&quot;https://blog.kakaocdn.net/dn/cR797z/dJMb9i2Og47/s5kcPoupwXsyI6PqrPJw6K/img.png&quot; srcset=&quot;https://img1.daumcdn.net/thumb/R1280x0/?scode=mtistory2&amp;fname=https%3A%2F%2Fblog.kakaocdn.net%2Fdn%2FcR797z%2FdJMb9i2Og47%2Fs5kcPoupwXsyI6PqrPJw6K%2Fimg.png&quot; onerror=&quot;this.onerror=null; this.src='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png'; this.srcset='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png';&quot; loading=&quot;lazy&quot; width=&quot;1700&quot; height=&quot;773&quot; data-filename=&quot;고1-19번.png&quot; data-origin-width=&quot;1700&quot; data-origin-height=&quot;773&quot;/&gt;&lt;/span&gt;&lt;/figure&gt;
&lt;/div&gt;
&lt;/div&gt;</description>
      <category>(新 교육과정) 공통수학 - 문제풀이/다항식</category>
      <author>수악중독</author>
      <guid isPermaLink="true">https://mathjk.tistory.com/6779</guid>
      <comments>https://mathjk.tistory.com/6779#entry6779comment</comments>
      <pubDate>Thu, 23 Oct 2025 10:32:12 +0900</pubDate>
    </item>
    <item>
      <title>내분점&amp;amp;두 점 사이의 거리&amp;amp; 직선의 방정식_난이도 중 (2025년 10월 고1 20번)</title>
      <link>https://mathjk.tistory.com/6778</link>
      <description>&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;$0$이 아닌 실수 $a$에 대하여 좌표평면 위의 서로 다른 세 점&amp;nbsp;&amp;nbsp;$\mathrm{A}(2a,\; 0)$, $\mathrm{B}$, $\mathrm{C}$가 다음 조건을 만족시킨다.&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;div class=&quot;txc-textbox&quot; style=&quot;background-color: #dbe8fb; padding: 10px; border: 1px solid #dbe8fb;&quot;&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;◦ 삼각형 $\mathrm{ABC}$의 무게중심의 좌표는 $(0, \;2)$이다.&amp;nbsp;&amp;nbsp;&lt;br /&gt;◦ $\overline{\mathrm{AB}} = \overline{\mathrm{AC}}$&amp;nbsp;&amp;nbsp;&lt;/p&gt;
&lt;/div&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;다음은 $\overline{\mathrm{BC}} = 2\sqrt{a^2 + 1}$일 때, 점 $\mathrm{B}$의 $x$좌표와 $y$좌표의 합을 구하는 과정이다.&amp;nbsp;&amp;nbsp;&lt;br /&gt;(단, 점 $\mathrm{B}$의 $x$좌표는 점 $\mathrm{C}$의 $x$좌표보다 크다.)&amp;nbsp; &amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;div class=&quot;txc-textbox&quot; style=&quot;background-color: #e7fdb5; padding: 10px; border: 1px solid #e7fdb5;&quot;&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;선분 $\mathrm{BC}$의 중점을 $\mathrm{M}(b, \; c)$, 삼각형 $\mathrm{ABC}$의 무게중심을 $\mathrm{G}$라고 하면 $\mathrm{G}(0, \;2)$는 선분 $\mathrm{AM}$을 $2:1$로 내분하는 점이므로 $b = -a$, $c = \boxed{\text{ (가) }}$이다.&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;$\overline{\mathrm{AB}} = \overline{\mathrm{AC}}$이고 직선 $\mathrm{AM}$의 기울기가 $-\dfrac{1}{a}$이므로 직선 $\mathrm{BC}$의 방정식은 $$y = \boxed{\text{ (나) }} \times \{x -(- a)\} + \boxed{\text{ (가) }}$$ 이다.&amp;nbsp;&amp;nbsp;&lt;br /&gt;점 $\mathrm{B}$의 $x$좌표를 $k$라 하면 점 $\mathrm{B}$의 $y$좌표는 $\boxed{\text{ (나) }} \times (k + a) + \boxed{\text{ (가) }}$이다.&amp;nbsp;&amp;nbsp;&lt;br /&gt;$\overline{\mathrm{BM}} = \dfrac{1}{2}\overline{\mathrm{BC}}$이고 점 $\mathrm{B}$의 $x$좌표가 점 $\mathrm{C}$의 $x$좌표보다 크므로 $k = \boxed{\text{ (다) }}$이다.&amp;nbsp;&amp;nbsp;&lt;br /&gt;따라서 점 $\mathrm{B}$의 $x$좌표와 $y$좌표의 합은 $\boxed{\text{ (라) }}$이다.&amp;nbsp;&amp;nbsp;&lt;/p&gt;
&lt;/div&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;위의 (가), (라)에 알맞은 수를 각각 $p, \;q$라 하고, (나), (다)에 알맞은 식을 각각 $f(a), \;g(a)$라 할 때, $f(p) \times g(q)$의 값은?&amp;nbsp;&lt;br /&gt;&lt;br /&gt;① $-10$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;② $-\dfrac{19}{2}$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;③ $-9$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;④ $-\dfrac{17}{2}$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;⑤ $-8$&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;div data-ke-type=&quot;moreLess&quot; data-text-more=&quot;풀이보기&quot; data-text-less=&quot;풀이닫기&quot;&gt;&lt;a class=&quot;btn-toggle-moreless&quot;&gt;더보기&lt;/a&gt;
&lt;div class=&quot;moreless-content&quot;&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&lt;span style=&quot;color: #ee2323;&quot;&gt;&lt;b&gt;정답 &lt;span style=&quot;color: #ee2323; text-align: start;&quot;&gt;③&amp;nbsp;&lt;/span&gt;&lt;/b&gt;&lt;/span&gt;&lt;/p&gt;
&lt;figure class=&quot;imageblock alignCenter&quot; data-ke-mobileStyle=&quot;widthOrigin&quot; data-filename=&quot;고1-20번.png&quot; data-origin-width=&quot;2475&quot; data-origin-height=&quot;2199&quot;&gt;&lt;span data-url=&quot;https://blog.kakaocdn.net/dn/PYkQM/dJMb8WZK8dC/9f5sXDw4k9pI2Navl1ArF0/img.png&quot; data-phocus=&quot;https://blog.kakaocdn.net/dn/PYkQM/dJMb8WZK8dC/9f5sXDw4k9pI2Navl1ArF0/img.png&quot;&gt;&lt;img src=&quot;https://blog.kakaocdn.net/dn/PYkQM/dJMb8WZK8dC/9f5sXDw4k9pI2Navl1ArF0/img.png&quot; srcset=&quot;https://img1.daumcdn.net/thumb/R1280x0/?scode=mtistory2&amp;fname=https%3A%2F%2Fblog.kakaocdn.net%2Fdn%2FPYkQM%2FdJMb8WZK8dC%2F9f5sXDw4k9pI2Navl1ArF0%2Fimg.png&quot; onerror=&quot;this.onerror=null; this.src='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png'; this.srcset='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png';&quot; loading=&quot;lazy&quot; width=&quot;2475&quot; height=&quot;2199&quot; data-filename=&quot;고1-20번.png&quot; data-origin-width=&quot;2475&quot; data-origin-height=&quot;2199&quot;/&gt;&lt;/span&gt;&lt;/figure&gt;
&lt;/div&gt;
&lt;/div&gt;</description>
      <category>(新 교육과정) 공통수학 - 문제풀이/도형의 방정식</category>
      <author>수악중독</author>
      <guid isPermaLink="true">https://mathjk.tistory.com/6778</guid>
      <comments>https://mathjk.tistory.com/6778#entry6778comment</comments>
      <pubDate>Thu, 23 Oct 2025 10:29:33 +0900</pubDate>
    </item>
    <item>
      <title>점과 도형의 대칭이동 &amp;amp; 점과 직선 사이의 거리_난이도 중상 (2025년 10월 고1 21번)</title>
      <link>https://mathjk.tistory.com/6777</link>
      <description>&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;좌표평면 위의 제$1$사분면에 있는 점 $\mathrm{A}$를 중심으로 하고 원점 $\mathrm{O}$를 지나는 원 $C_1$이 있다. 원 $C_1$을 원점 $\mathrm{O}$에 대하여 대칭이동한&amp;nbsp;원을&amp;nbsp;$C_2$라&amp;nbsp;할&amp;nbsp;때,&amp;nbsp;두&amp;nbsp;원&amp;nbsp;$C_1$,&amp;nbsp;$C_2$가&amp;nbsp;다음&amp;nbsp;조건을&amp;nbsp;만족시킨다.&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;div class=&quot;txc-textbox&quot; style=&quot;background-color: #dbe8fb; padding: 10px; border: 1px solid #dbe8fb;&quot;&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;삼각형 $\mathrm{OPQ}$의 외접원의 중심이 선분 $\mathrm{PQ}$ 위에 있도록 하는 원 $C_1$ 위의 점 $\mathrm{P}$와 원 $C_2$ 위의 점 $\mathrm{Q}$에 대하여 $\overline{\mathrm{PQ}}=6$이다.&amp;nbsp;&amp;nbsp;&lt;/p&gt;
&lt;/div&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&lt;br /&gt;원 $C_2$가 $x$축과 만나는 점 중 $\mathrm{O}$가 아닌 점을 $\mathrm{B}$라 할 때, 원 $C_2$ 위의 점 $\mathrm{B}$에서의 접선을 $l$이라 하자. 직선 $l$의 기울기가 $\dfrac{1}{2}$일 때, 점 $\mathrm{A}$와 직선 $l$ 사이의 거리는?&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&lt;br /&gt;① $\dfrac{3}{5}$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;② $\dfrac{2}{3}$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;③ $\dfrac{11}{15}$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;④ $\dfrac{4}{5}$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;⑤ $\dfrac{13}{15}$&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;&lt;figure class=&quot;imageblock alignCenter&quot; data-ke-mobileStyle=&quot;widthOrigin&quot; data-filename=&quot;Screenshot 2025-10-22 at 21.15.33.png&quot; data-origin-width=&quot;1222&quot; data-origin-height=&quot;1486&quot;&gt;&lt;span data-url=&quot;https://blog.kakaocdn.net/dn/zaIK0/dJMb84cp0YP/t3GbD7KRIasx1ONK8EmuQ1/img.png&quot; data-phocus=&quot;https://blog.kakaocdn.net/dn/zaIK0/dJMb84cp0YP/t3GbD7KRIasx1ONK8EmuQ1/img.png&quot;&gt;&lt;img src=&quot;https://blog.kakaocdn.net/dn/zaIK0/dJMb84cp0YP/t3GbD7KRIasx1ONK8EmuQ1/img.png&quot; srcset=&quot;https://img1.daumcdn.net/thumb/R1280x0/?scode=mtistory2&amp;fname=https%3A%2F%2Fblog.kakaocdn.net%2Fdn%2FzaIK0%2FdJMb84cp0YP%2Ft3GbD7KRIasx1ONK8EmuQ1%2Fimg.png&quot; onerror=&quot;this.onerror=null; this.src='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png'; this.srcset='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png';&quot; loading=&quot;lazy&quot; width=&quot;409&quot; height=&quot;497&quot; data-filename=&quot;Screenshot 2025-10-22 at 21.15.33.png&quot; data-origin-width=&quot;1222&quot; data-origin-height=&quot;1486&quot;/&gt;&lt;/span&gt;&lt;/figure&gt;
&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;div data-ke-type=&quot;moreLess&quot; data-text-more=&quot;풀이보기&quot; data-text-less=&quot;풀이닫기&quot;&gt;&lt;a class=&quot;btn-toggle-moreless&quot;&gt;더보기&lt;/a&gt;
&lt;div class=&quot;moreless-content&quot;&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&lt;span style=&quot;color: #ee2323;&quot;&gt;&lt;b&gt;정답 ①&lt;/b&gt;&lt;/span&gt;&lt;/p&gt;
&lt;figure class=&quot;imageblock alignCenter&quot; data-ke-mobileStyle=&quot;widthOrigin&quot; data-filename=&quot;고1-21번.png&quot; data-origin-width=&quot;2480&quot; data-origin-height=&quot;2345&quot;&gt;&lt;span data-url=&quot;https://blog.kakaocdn.net/dn/ckWkBy/dJMb81UiN6k/jW2kJ71u6gLvPtIdGbkKt0/img.png&quot; data-phocus=&quot;https://blog.kakaocdn.net/dn/ckWkBy/dJMb81UiN6k/jW2kJ71u6gLvPtIdGbkKt0/img.png&quot;&gt;&lt;img src=&quot;https://blog.kakaocdn.net/dn/ckWkBy/dJMb81UiN6k/jW2kJ71u6gLvPtIdGbkKt0/img.png&quot; srcset=&quot;https://img1.daumcdn.net/thumb/R1280x0/?scode=mtistory2&amp;fname=https%3A%2F%2Fblog.kakaocdn.net%2Fdn%2FckWkBy%2FdJMb81UiN6k%2FjW2kJ71u6gLvPtIdGbkKt0%2Fimg.png&quot; onerror=&quot;this.onerror=null; this.src='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png'; this.srcset='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png';&quot; loading=&quot;lazy&quot; width=&quot;2480&quot; height=&quot;2345&quot; data-filename=&quot;고1-21번.png&quot; data-origin-width=&quot;2480&quot; data-origin-height=&quot;2345&quot;/&gt;&lt;/span&gt;&lt;/figure&gt;
&lt;/div&gt;
&lt;/div&gt;</description>
      <category>(新 교육과정) 공통수학 - 문제풀이/도형의 방정식</category>
      <author>수악중독</author>
      <guid isPermaLink="true">https://mathjk.tistory.com/6777</guid>
      <comments>https://mathjk.tistory.com/6777#entry6777comment</comments>
      <pubDate>Thu, 23 Oct 2025 10:17:26 +0900</pubDate>
    </item>
    <item>
      <title>이차방정식의 판별식&amp;amp;복이차방정식_난이도 중하 (2025년 10월 고1 26번)</title>
      <link>https://mathjk.tistory.com/6776</link>
      <description>&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;$x$에 대한 사차방정식 $\left (2x^2 + kx \right )^2 + 10\left (2x^2 + kx \right ) + 16 = 0$의&amp;nbsp;서로&amp;nbsp;다른&amp;nbsp;실근의&amp;nbsp;개수가&amp;nbsp;$2$가&amp;nbsp;되도록&amp;nbsp;하는&amp;nbsp;모든&amp;nbsp;자연수&amp;nbsp;$k$의&amp;nbsp;값의&amp;nbsp;합을&amp;nbsp;구하시오.&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;div data-ke-type=&quot;moreLess&quot; data-text-more=&quot;풀이보기&quot; data-text-less=&quot;풀이닫기&quot;&gt;&lt;a class=&quot;btn-toggle-moreless&quot;&gt;더보기&lt;/a&gt;
&lt;div class=&quot;moreless-content&quot;&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&lt;span style=&quot;color: #ee2323;&quot;&gt;&lt;b&gt;정답 $18$&lt;/b&gt;&lt;/span&gt;&lt;/p&gt;
&lt;figure class=&quot;imageblock alignCenter&quot; data-ke-mobileStyle=&quot;widthOrigin&quot; data-filename=&quot;고1-26번.png&quot; data-origin-width=&quot;2480&quot; data-origin-height=&quot;1141&quot;&gt;&lt;span data-url=&quot;https://blog.kakaocdn.net/dn/upgS6/dJMb9OgpSiY/dcTwEpDrckFevVz5CNqyyk/img.png&quot; data-phocus=&quot;https://blog.kakaocdn.net/dn/upgS6/dJMb9OgpSiY/dcTwEpDrckFevVz5CNqyyk/img.png&quot;&gt;&lt;img src=&quot;https://blog.kakaocdn.net/dn/upgS6/dJMb9OgpSiY/dcTwEpDrckFevVz5CNqyyk/img.png&quot; srcset=&quot;https://img1.daumcdn.net/thumb/R1280x0/?scode=mtistory2&amp;fname=https%3A%2F%2Fblog.kakaocdn.net%2Fdn%2FupgS6%2FdJMb9OgpSiY%2FdcTwEpDrckFevVz5CNqyyk%2Fimg.png&quot; onerror=&quot;this.onerror=null; this.src='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png'; this.srcset='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png';&quot; loading=&quot;lazy&quot; width=&quot;2480&quot; height=&quot;1141&quot; data-filename=&quot;고1-26번.png&quot; data-origin-width=&quot;2480&quot; data-origin-height=&quot;1141&quot;/&gt;&lt;/span&gt;&lt;/figure&gt;
&lt;/div&gt;
&lt;/div&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;</description>
      <category>(新 교육과정) 공통수학 - 문제풀이/방정식과 부등식</category>
      <author>수악중독</author>
      <guid isPermaLink="true">https://mathjk.tistory.com/6776</guid>
      <comments>https://mathjk.tistory.com/6776#entry6776comment</comments>
      <pubDate>Thu, 23 Oct 2025 10:10:58 +0900</pubDate>
    </item>
    <item>
      <title>이차방정식의 판별식과 근과 계수와의 관계_난이도 중 (2025년 10월 고1 27번)</title>
      <link>https://mathjk.tistory.com/6775</link>
      <description>&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;상수 $k$에 대하여 $\mathrm{x}$에 대한 이차방정식&amp;nbsp; $x^2 + kx - \dfrac{1}{2}k^2 + 3k = 0$이 서로 다른 두 실근 $\alpha, \; \beta$를 갖는다. $\alpha^2 - k\beta = 12$일 때, $\alpha^2 + \beta^2$의 값을 구하시오.&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;div data-ke-type=&quot;moreLess&quot; data-text-more=&quot;풀이보기&quot; data-text-less=&quot;풀이닫기&quot;&gt;&lt;a class=&quot;btn-toggle-moreless&quot;&gt;더보기&lt;/a&gt;
&lt;div class=&quot;moreless-content&quot;&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&lt;span style=&quot;color: #ee2323;&quot;&gt;&lt;b&gt;정답 $20$&lt;/b&gt;&lt;/span&gt;&lt;/p&gt;
&lt;figure class=&quot;imageblock alignCenter&quot; data-ke-mobileStyle=&quot;widthOrigin&quot; data-filename=&quot;고1-27번.png&quot; data-origin-width=&quot;2480&quot; data-origin-height=&quot;1673&quot;&gt;&lt;span data-url=&quot;https://blog.kakaocdn.net/dn/bobEvw/dJMb9NIzVrQ/XO3HY5S4cUUuO3dBDXUOn0/img.png&quot; data-phocus=&quot;https://blog.kakaocdn.net/dn/bobEvw/dJMb9NIzVrQ/XO3HY5S4cUUuO3dBDXUOn0/img.png&quot;&gt;&lt;img src=&quot;https://blog.kakaocdn.net/dn/bobEvw/dJMb9NIzVrQ/XO3HY5S4cUUuO3dBDXUOn0/img.png&quot; srcset=&quot;https://img1.daumcdn.net/thumb/R1280x0/?scode=mtistory2&amp;fname=https%3A%2F%2Fblog.kakaocdn.net%2Fdn%2FbobEvw%2FdJMb9NIzVrQ%2FXO3HY5S4cUUuO3dBDXUOn0%2Fimg.png&quot; onerror=&quot;this.onerror=null; this.src='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png'; this.srcset='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png';&quot; loading=&quot;lazy&quot; width=&quot;2480&quot; height=&quot;1673&quot; data-filename=&quot;고1-27번.png&quot; data-origin-width=&quot;2480&quot; data-origin-height=&quot;1673&quot;/&gt;&lt;/span&gt;&lt;/figure&gt;
&lt;/div&gt;
&lt;/div&gt;</description>
      <category>(新 교육과정) 공통수학 - 문제풀이/방정식과 부등식</category>
      <author>수악중독</author>
      <guid isPermaLink="true">https://mathjk.tistory.com/6775</guid>
      <comments>https://mathjk.tistory.com/6775#entry6775comment</comments>
      <pubDate>Thu, 23 Oct 2025 10:08:36 +0900</pubDate>
    </item>
    <item>
      <title>원과 직선의 위치 관계_직선이 원에 접할 조건_난이도 중 (2025년 10월 고1 28번)</title>
      <link>https://mathjk.tistory.com/6774</link>
      <description>&lt;p data-ke-size=&quot;size16&quot;&gt;`&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;원 $O$가 $x$축과 두 점 $\mathrm{A,\; B}$에서 만나고, $y$축과 두 점 $\mathrm{C, \; D}$에서 만난다. 네 점 $\mathrm{A, \;B, \; C, \; D}$와 원 $O$가 다음 조건을 만족시킬 때, 사각형 $\mathrm{ACBD}$의 넓이를 구하시오. (단, 점 $\mathrm{A}$의 $x$좌표는 점 $\mathrm{B}$의 $x$좌표보다 작고, 점 $\mathrm{C}$의 $y$좌표는 점 $\mathrm{D}$의 $y$좌표보다 작다.)&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;div class=&quot;txc-textbox&quot; style=&quot;background-color: #dbe8fb; padding: 10px; border: 1px solid #dbe8fb;&quot;&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;(가) 선분 $\mathrm{AB}$를 $1:4$로 내분하는 점은 선분 $\mathrm{CD}$의 중점이다.&amp;nbsp;&amp;nbsp;&lt;br /&gt;(나) 원 $O$가 직선 $4x - 3y + 13 = 0$에 접한다.&lt;/p&gt;
&lt;/div&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;div data-ke-type=&quot;moreLess&quot; data-text-more=&quot;풀이보기&quot; data-text-less=&quot;풀이닫기&quot;&gt;&lt;a class=&quot;btn-toggle-moreless&quot;&gt;더보기&lt;/a&gt;
&lt;div class=&quot;moreless-content&quot;&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&lt;span style=&quot;color: #ee2323;&quot;&gt;&lt;b&gt;정답 $40$&lt;/b&gt;&lt;/span&gt;&lt;/p&gt;
&lt;figure class=&quot;imageblock alignCenter&quot; data-ke-mobileStyle=&quot;widthOrigin&quot; data-filename=&quot;고1-28번.png&quot; data-origin-width=&quot;2480&quot; data-origin-height=&quot;1661&quot;&gt;&lt;span data-url=&quot;https://blog.kakaocdn.net/dn/biAf2R/dJMb83EzQOX/3MM0OVS9WuMQKhv6c0pIGk/img.png&quot; data-phocus=&quot;https://blog.kakaocdn.net/dn/biAf2R/dJMb83EzQOX/3MM0OVS9WuMQKhv6c0pIGk/img.png&quot;&gt;&lt;img src=&quot;https://blog.kakaocdn.net/dn/biAf2R/dJMb83EzQOX/3MM0OVS9WuMQKhv6c0pIGk/img.png&quot; srcset=&quot;https://img1.daumcdn.net/thumb/R1280x0/?scode=mtistory2&amp;fname=https%3A%2F%2Fblog.kakaocdn.net%2Fdn%2FbiAf2R%2FdJMb83EzQOX%2F3MM0OVS9WuMQKhv6c0pIGk%2Fimg.png&quot; onerror=&quot;this.onerror=null; this.src='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png'; this.srcset='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png';&quot; loading=&quot;lazy&quot; width=&quot;2480&quot; height=&quot;1661&quot; data-filename=&quot;고1-28번.png&quot; data-origin-width=&quot;2480&quot; data-origin-height=&quot;1661&quot;/&gt;&lt;/span&gt;&lt;/figure&gt;
&lt;/div&gt;
&lt;/div&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;/p&gt;</description>
      <category>(新 교육과정) 공통수학 - 문제풀이/도형의 방정식</category>
      <author>수악중독</author>
      <guid isPermaLink="true">https://mathjk.tistory.com/6774</guid>
      <comments>https://mathjk.tistory.com/6774#entry6774comment</comments>
      <pubDate>Wed, 22 Oct 2025 00:19:04 +0900</pubDate>
    </item>
    <item>
      <title>곱셈공식&amp;amp;곱셈공식의 변형_난이도 중 (2025년 10월 고1 29번)</title>
      <link>https://mathjk.tistory.com/6773</link>
      <description>&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;그림과 같이 정사각형 $\mathrm{ABCD}$를 밑면으로 하는 직육면체 $\mathrm{ABCD-EFGH}$가 있다.&amp;nbsp; 선분 $\mathrm{AD}$ 위의 점 $\mathrm{p}P$와 선분 $\mathrm{BC}$ 위의 점 $\mathrm{Q}$를 $\overline{\mathrm{AP}} = \overline{\mathrm{BQ}} = \overline{\mathrm{BF}}$가 되도록 잡고, 점 $\mathrm{P}$에서 선분 $\mathrm{EH}$에 내린 수선의 발을 $\mathrm{R}$, 점 $\mathrm{Q}$에서 선분 $\mathrm{FG}$에 내린 수선의 발을 $\mathrm{S}$라 하자. 직육면체 $\mathrm{ABCD-EFGH}$의 부피를 $V_1$, 직육면체 $\mathrm{ABQP-EFSR}$의 부피를 $V_2$라 하자. $$\left (\overline{\mathrm{AB}} +\overline{\mathrm{BF}} \right ) \times \overline{\mathrm{SD}}^2 = \dfrac{35}{4}, \quad V_1 + V_2 = \dfrac{15}{4}$$&amp;nbsp; 일 때, $\left (\overline{\mathrm{AB}} + \overline{\mathrm{BF}} \right )^3 = \dfrac{q}{p}$ 이다.&amp;nbsp;$p&amp;nbsp;+&amp;nbsp;q$의&amp;nbsp;값을&amp;nbsp;구하시오.&amp;nbsp;&amp;nbsp;&lt;br /&gt;(단, $\overline{\mathrm{AB}} &amp;gt; \overline{\mathrm{BF}}$이고, $p$와 $q$는 서로소인 자연수이다.)&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;&lt;figure class=&quot;imageblock alignCenter&quot; data-ke-mobileStyle=&quot;widthOrigin&quot; data-filename=&quot;Screenshot 2025-10-21 at 11.09.07.png&quot; data-origin-width=&quot;1556&quot; data-origin-height=&quot;962&quot;&gt;&lt;span data-url=&quot;https://blog.kakaocdn.net/dn/cqYXsZ/dJMb9V7AXZ9/ic9v1b1B8gUH6KSoQ0nKp0/img.png&quot; data-phocus=&quot;https://blog.kakaocdn.net/dn/cqYXsZ/dJMb9V7AXZ9/ic9v1b1B8gUH6KSoQ0nKp0/img.png&quot;&gt;&lt;img src=&quot;https://blog.kakaocdn.net/dn/cqYXsZ/dJMb9V7AXZ9/ic9v1b1B8gUH6KSoQ0nKp0/img.png&quot; srcset=&quot;https://img1.daumcdn.net/thumb/R1280x0/?scode=mtistory2&amp;fname=https%3A%2F%2Fblog.kakaocdn.net%2Fdn%2FcqYXsZ%2FdJMb9V7AXZ9%2Fic9v1b1B8gUH6KSoQ0nKp0%2Fimg.png&quot; onerror=&quot;this.onerror=null; this.src='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png'; this.srcset='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png';&quot; loading=&quot;lazy&quot; width=&quot;432&quot; height=&quot;267&quot; data-filename=&quot;Screenshot 2025-10-21 at 11.09.07.png&quot; data-origin-width=&quot;1556&quot; data-origin-height=&quot;962&quot;/&gt;&lt;/span&gt;&lt;/figure&gt;
&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;div data-ke-type=&quot;moreLess&quot; data-text-more=&quot;풀이보기&quot; data-text-less=&quot;풀이닫기&quot;&gt;&lt;a class=&quot;btn-toggle-moreless&quot;&gt;더보기&lt;/a&gt;
&lt;div class=&quot;moreless-content&quot;&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&lt;span style=&quot;color: #ee2323;&quot;&gt;&lt;b&gt;정답&amp;nbsp;&lt;/b&gt;&lt;/span&gt;&lt;/p&gt;
&lt;figure class=&quot;imageblock alignCenter&quot; data-ke-mobileStyle=&quot;widthOrigin&quot; data-filename=&quot;고1-29번.png&quot; data-origin-width=&quot;2480&quot; data-origin-height=&quot;1492&quot;&gt;&lt;span data-url=&quot;https://blog.kakaocdn.net/dn/LjY8Q/dJMb9MiBljy/df9wGjl8msdnXeikvPhew0/img.png&quot; data-phocus=&quot;https://blog.kakaocdn.net/dn/LjY8Q/dJMb9MiBljy/df9wGjl8msdnXeikvPhew0/img.png&quot;&gt;&lt;img src=&quot;https://blog.kakaocdn.net/dn/LjY8Q/dJMb9MiBljy/df9wGjl8msdnXeikvPhew0/img.png&quot; srcset=&quot;https://img1.daumcdn.net/thumb/R1280x0/?scode=mtistory2&amp;fname=https%3A%2F%2Fblog.kakaocdn.net%2Fdn%2FLjY8Q%2FdJMb9MiBljy%2Fdf9wGjl8msdnXeikvPhew0%2Fimg.png&quot; onerror=&quot;this.onerror=null; this.src='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png'; this.srcset='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png';&quot; loading=&quot;lazy&quot; width=&quot;2480&quot; height=&quot;1492&quot; data-filename=&quot;고1-29번.png&quot; data-origin-width=&quot;2480&quot; data-origin-height=&quot;1492&quot;/&gt;&lt;/span&gt;&lt;/figure&gt;
&lt;/div&gt;
&lt;/div&gt;</description>
      <category>(新 교육과정) 공통수학 - 문제풀이/다항식</category>
      <author>수악중독</author>
      <guid isPermaLink="true">https://mathjk.tistory.com/6773</guid>
      <comments>https://mathjk.tistory.com/6773#entry6773comment</comments>
      <pubDate>Wed, 22 Oct 2025 00:14:49 +0900</pubDate>
    </item>
    <item>
      <title>이차방정식과 이차함수의 그래프_난이도 상 (2025년 10월 고1 30번)</title>
      <link>https://mathjk.tistory.com/6772</link>
      <description>&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;두 상수 $p\; (p&amp;gt;0)$, $q$에 대하여&amp;nbsp; 이차함수&amp;nbsp;$f(x)&amp;nbsp;=&amp;nbsp;\dfrac{1}{2}(x&amp;nbsp;-&amp;nbsp;p)^2&amp;nbsp;+&amp;nbsp;q$가&amp;nbsp;있다.&amp;nbsp;&amp;nbsp;&lt;br /&gt;함수 $f(x)$와 양수 $m$에 대하여 함수 $g(x)$를&amp;nbsp; $$g(x) = -f(x - m)$$&amp;nbsp; 이라 할 때, 방정식 $f(x) = g(x)$가 서로 다른 두 실근 $\alpha, \; \beta \; (\alpha &amp;lt; \beta)$를 갖는다.&amp;nbsp; 함수 $h(x)$를&amp;nbsp;&amp;nbsp;$$h(x) =\begin{cases} f(x) &amp;amp; (x \le \alpha \text{ 또는 } x \ge \beta) \\ g(x) &amp;amp; (\alpha &amp;lt; x &amp;lt; \beta)\end{cases}$$&amp;nbsp; 라&amp;nbsp;할&amp;nbsp;때,&amp;nbsp;함수&amp;nbsp;$h(x)$는&amp;nbsp;다음&amp;nbsp;조건을&amp;nbsp;만족시킨다.&amp;nbsp;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;div class=&quot;txc-textbox&quot; style=&quot;background-color: #dbe8fb; padding: 10px; border: 1px solid #dbe8fb;&quot;&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;$\mathrm{x}$에 대한 방정식 $h(x) = t$의 서로 다른 실근의 개수가 $2$ 이상이면서&amp;nbsp; 서로 다른 모든 실근의 합이 $4p + 2m$이 되도록 하는&amp;nbsp; 모든 실수 $t$의 값의 범위는 $g(p) &amp;lt; t &amp;lt; 5$이다.&amp;nbsp;&amp;nbsp;&lt;/p&gt;
&lt;/div&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&lt;br /&gt;$f(m) + g(m) = -4$일 때, $m \times (p - q)$의 값을 구하시오.&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;div data-ke-type=&quot;moreLess&quot; data-text-more=&quot;풀이보기&quot; data-text-less=&quot;풀이닫기&quot;&gt;&lt;a class=&quot;btn-toggle-moreless&quot;&gt;더보기&lt;/a&gt;
&lt;div class=&quot;moreless-content&quot;&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&lt;span style=&quot;color: #ee2323;&quot;&gt;&lt;b&gt;정답 $16$&lt;/b&gt;&lt;/span&gt;&lt;/p&gt;
&lt;figure class=&quot;imageblock alignCenter&quot; data-ke-mobileStyle=&quot;widthOrigin&quot; data-filename=&quot;고1-30번.png&quot; data-origin-width=&quot;2480&quot; data-origin-height=&quot;2363&quot;&gt;&lt;span data-url=&quot;https://blog.kakaocdn.net/dn/R39Mb/dJMb86BiOol/15kwkxg0SxJmise7eBQKQK/img.png&quot; data-phocus=&quot;https://blog.kakaocdn.net/dn/R39Mb/dJMb86BiOol/15kwkxg0SxJmise7eBQKQK/img.png&quot;&gt;&lt;img src=&quot;https://blog.kakaocdn.net/dn/R39Mb/dJMb86BiOol/15kwkxg0SxJmise7eBQKQK/img.png&quot; srcset=&quot;https://img1.daumcdn.net/thumb/R1280x0/?scode=mtistory2&amp;fname=https%3A%2F%2Fblog.kakaocdn.net%2Fdn%2FR39Mb%2FdJMb86BiOol%2F15kwkxg0SxJmise7eBQKQK%2Fimg.png&quot; onerror=&quot;this.onerror=null; this.src='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png'; this.srcset='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png';&quot; loading=&quot;lazy&quot; width=&quot;2480&quot; height=&quot;2363&quot; data-filename=&quot;고1-30번.png&quot; data-origin-width=&quot;2480&quot; data-origin-height=&quot;2363&quot;/&gt;&lt;/span&gt;&lt;/figure&gt;
&lt;/div&gt;
&lt;/div&gt;</description>
      <category>(新 교육과정) 공통수학 - 문제풀이/방정식과 부등식</category>
      <author>수악중독</author>
      <guid isPermaLink="true">https://mathjk.tistory.com/6772</guid>
      <comments>https://mathjk.tistory.com/6772#entry6772comment</comments>
      <pubDate>Wed, 22 Oct 2025 00:08:30 +0900</pubDate>
    </item>
    <item>
      <title>수열의 합과 일반항과의 관계_난이도 중하 (2025년 10월 고2 14번)</title>
      <link>https://mathjk.tistory.com/6771</link>
      <description>&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;수열&amp;nbsp;$\lbrace&amp;nbsp;a_n&amp;nbsp;\rbrace$의&amp;nbsp;첫째항부터&amp;nbsp;제$n$항까지의&amp;nbsp;합을&amp;nbsp;$S_n$이라&amp;nbsp;하자.&amp;nbsp;&amp;nbsp;&lt;br /&gt;$S_n = \dfrac{1}{n}$ 일 때, $a_1 + \displaystyle\sum_{k=2}^{7} \dfrac{1}{(k-1) \times a_k}$ 의 값은?&amp;nbsp;&lt;br /&gt;&lt;br /&gt;① $-34$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;② $-32$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;③ $-30$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;④ $-28$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;⑤ $-26$&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;div data-ke-type=&quot;moreLess&quot; data-text-more=&quot;풀이보기&quot; data-text-less=&quot;풀이닫기&quot;&gt;&lt;a class=&quot;btn-toggle-moreless&quot;&gt;더보기&lt;/a&gt;
&lt;div class=&quot;moreless-content&quot;&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&lt;span style=&quot;color: #ee2323;&quot;&gt;&lt;b&gt;정답&amp;nbsp;&lt;/b&gt;&lt;/span&gt;&lt;/p&gt;
&lt;figure class=&quot;imageblock alignCenter&quot; data-ke-mobileStyle=&quot;widthOrigin&quot; data-filename=&quot;고2-14번.png&quot; data-origin-width=&quot;2480&quot; data-origin-height=&quot;684&quot;&gt;&lt;span data-url=&quot;https://blog.kakaocdn.net/dn/WrkXU/dJMb9hW8aEY/IkRvIUkCN7zzhExCfv8GI0/img.png&quot; data-phocus=&quot;https://blog.kakaocdn.net/dn/WrkXU/dJMb9hW8aEY/IkRvIUkCN7zzhExCfv8GI0/img.png&quot;&gt;&lt;img src=&quot;https://blog.kakaocdn.net/dn/WrkXU/dJMb9hW8aEY/IkRvIUkCN7zzhExCfv8GI0/img.png&quot; srcset=&quot;https://img1.daumcdn.net/thumb/R1280x0/?scode=mtistory2&amp;fname=https%3A%2F%2Fblog.kakaocdn.net%2Fdn%2FWrkXU%2FdJMb9hW8aEY%2FIkRvIUkCN7zzhExCfv8GI0%2Fimg.png&quot; onerror=&quot;this.onerror=null; this.src='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png'; this.srcset='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png';&quot; loading=&quot;lazy&quot; width=&quot;2480&quot; height=&quot;684&quot; data-filename=&quot;고2-14번.png&quot; data-origin-width=&quot;2480&quot; data-origin-height=&quot;684&quot;/&gt;&lt;/span&gt;&lt;/figure&gt;
&lt;/div&gt;
&lt;/div&gt;</description>
      <category>수학1- 문제풀이/수열</category>
      <author>수악중독</author>
      <guid isPermaLink="true">https://mathjk.tistory.com/6771</guid>
      <comments>https://mathjk.tistory.com/6771#entry6771comment</comments>
      <pubDate>Wed, 22 Oct 2025 00:03:55 +0900</pubDate>
    </item>
    <item>
      <title>거듭제곱근의 정의_난이도 중 (2025년 10월 고2 15번)</title>
      <link>https://mathjk.tistory.com/6770</link>
      <description>&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;$2$ 이상의 자연수 $n$에 대하여 $n-12$의 $n$제곱근 중 실수인 것의 개수를 $f(n)$이라 하자.&amp;nbsp; $f(n)&amp;nbsp;+&amp;nbsp;f(2n)&amp;nbsp;=&amp;nbsp;1$을&amp;nbsp;만족시키는&amp;nbsp;모든&amp;nbsp;$n$의&amp;nbsp;값의&amp;nbsp;합은?&lt;br /&gt;&lt;br /&gt;① $10$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;② $12$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;③ $14$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;④ $16$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;⑤ $18$&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;div data-ke-type=&quot;moreLess&quot; data-text-more=&quot;풀이보기&quot; data-text-less=&quot;풀이닫기&quot;&gt;&lt;a class=&quot;btn-toggle-moreless&quot;&gt;더보기&lt;/a&gt;
&lt;div class=&quot;moreless-content&quot;&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&lt;span style=&quot;color: #ee2323;&quot;&gt;&lt;b&gt;정답 ③&lt;/b&gt;&lt;/span&gt;&lt;/p&gt;
&lt;figure class=&quot;imageblock alignCenter&quot; data-ke-mobileStyle=&quot;widthOrigin&quot; data-filename=&quot;고2-15번.png&quot; data-origin-width=&quot;2480&quot; data-origin-height=&quot;591&quot;&gt;&lt;span data-url=&quot;https://blog.kakaocdn.net/dn/boRkvq/dJMb8ZCaXtA/qsgBaDhHSRiQeWdRJ8Edl1/img.png&quot; data-phocus=&quot;https://blog.kakaocdn.net/dn/boRkvq/dJMb8ZCaXtA/qsgBaDhHSRiQeWdRJ8Edl1/img.png&quot;&gt;&lt;img src=&quot;https://blog.kakaocdn.net/dn/boRkvq/dJMb8ZCaXtA/qsgBaDhHSRiQeWdRJ8Edl1/img.png&quot; srcset=&quot;https://img1.daumcdn.net/thumb/R1280x0/?scode=mtistory2&amp;fname=https%3A%2F%2Fblog.kakaocdn.net%2Fdn%2FboRkvq%2FdJMb8ZCaXtA%2FqsgBaDhHSRiQeWdRJ8Edl1%2Fimg.png&quot; onerror=&quot;this.onerror=null; this.src='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png'; this.srcset='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png';&quot; loading=&quot;lazy&quot; width=&quot;2480&quot; height=&quot;591&quot; data-filename=&quot;고2-15번.png&quot; data-origin-width=&quot;2480&quot; data-origin-height=&quot;591&quot;/&gt;&lt;/span&gt;&lt;/figure&gt;
&lt;/div&gt;
&lt;/div&gt;</description>
      <category>수학1- 문제풀이/지수함수와 로그함수</category>
      <author>수악중독</author>
      <guid isPermaLink="true">https://mathjk.tistory.com/6770</guid>
      <comments>https://mathjk.tistory.com/6770#entry6770comment</comments>
      <pubDate>Wed, 22 Oct 2025 00:00:57 +0900</pubDate>
    </item>
    <item>
      <title>극한_미정계수의 결정_난이도 중 (2025년 10월 고2 16번)</title>
      <link>https://mathjk.tistory.com/6769</link>
      <description>&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;최고차항의 계수가 $1$인 두 이차함수 $f(x)$, $g(x)$가 $$f(1)=0, \quad \displaystyle\lim_{x \to 1} \dfrac{f(x+3) \times g(x)}{\{f(x)\}^2} = 0$$을 만족시킬 때, $f(5) + g(5)$의 값은?&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&lt;br /&gt;① $14$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;② $16$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;③ $18$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;④ $20$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;⑤ $22$&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;div data-ke-type=&quot;moreLess&quot; data-text-more=&quot;풀이보기&quot; data-text-less=&quot;풀이닫기&quot;&gt;&lt;a class=&quot;btn-toggle-moreless&quot;&gt;더보기&lt;/a&gt;
&lt;div class=&quot;moreless-content&quot;&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&lt;span style=&quot;color: #ee2323;&quot;&gt;&lt;b&gt;정답 ④&lt;/b&gt;&lt;/span&gt;&lt;/p&gt;
&lt;figure class=&quot;imageblock alignCenter&quot; data-ke-mobileStyle=&quot;widthOrigin&quot; data-filename=&quot;고2-16번.png&quot; data-origin-width=&quot;2480&quot; data-origin-height=&quot;948&quot;&gt;&lt;span data-url=&quot;https://blog.kakaocdn.net/dn/PYY50/dJMb9j1H8na/MXOtKL9KdldkPP1MfdmpW0/img.png&quot; data-phocus=&quot;https://blog.kakaocdn.net/dn/PYY50/dJMb9j1H8na/MXOtKL9KdldkPP1MfdmpW0/img.png&quot;&gt;&lt;img src=&quot;https://blog.kakaocdn.net/dn/PYY50/dJMb9j1H8na/MXOtKL9KdldkPP1MfdmpW0/img.png&quot; srcset=&quot;https://img1.daumcdn.net/thumb/R1280x0/?scode=mtistory2&amp;fname=https%3A%2F%2Fblog.kakaocdn.net%2Fdn%2FPYY50%2FdJMb9j1H8na%2FMXOtKL9KdldkPP1MfdmpW0%2Fimg.png&quot; onerror=&quot;this.onerror=null; this.src='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png'; this.srcset='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png';&quot; loading=&quot;lazy&quot; width=&quot;2480&quot; height=&quot;948&quot; data-filename=&quot;고2-16번.png&quot; data-origin-width=&quot;2480&quot; data-origin-height=&quot;948&quot;/&gt;&lt;/span&gt;&lt;/figure&gt;
&lt;/div&gt;
&lt;/div&gt;</description>
      <category>수학2 - 문제풀이/함수의 극한과 연속</category>
      <author>수악중독</author>
      <guid isPermaLink="true">https://mathjk.tistory.com/6769</guid>
      <comments>https://mathjk.tistory.com/6769#entry6769comment</comments>
      <pubDate>Tue, 21 Oct 2025 01:26:29 +0900</pubDate>
    </item>
    <item>
      <title>등차수열의 일반항_난이도 중 (2025년 10월 고2 17번)</title>
      <link>https://mathjk.tistory.com/6768</link>
      <description>&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;첫째항이 자연수이고 공차가 $-2$인 등차수열 $\lbrace a_n \rbrace$과 자연수 $k$가&amp;nbsp; $$a_4 \times a_5 \le 0, \quad \lvert a_1 - a_k \rvert = 4 \lvert a_k \rvert$$를 만족시킬 때, $a_1 + k$의 값은?&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&lt;br /&gt;① $11$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;② $12$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;③ $13$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;④ $14$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;⑤ $15$&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;div data-ke-type=&quot;moreLess&quot; data-text-more=&quot;풀이보기&quot; data-text-less=&quot;풀이닫기&quot;&gt;&lt;a class=&quot;btn-toggle-moreless&quot;&gt;더보기&lt;/a&gt;
&lt;div class=&quot;moreless-content&quot;&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&lt;span style=&quot;color: #ee2323;&quot;&gt;&lt;b&gt;정답&amp;nbsp;&lt;/b&gt;&lt;/span&gt;&lt;/p&gt;
&lt;figure class=&quot;imageblock alignCenter&quot; data-ke-mobileStyle=&quot;widthOrigin&quot; data-filename=&quot;고2-17번.png&quot; data-origin-width=&quot;2480&quot; data-origin-height=&quot;1568&quot;&gt;&lt;span data-url=&quot;https://blog.kakaocdn.net/dn/5okgA/dJMb9hph3tY/EmHRmZsxn3LLRmmiWXI4e0/img.png&quot; data-phocus=&quot;https://blog.kakaocdn.net/dn/5okgA/dJMb9hph3tY/EmHRmZsxn3LLRmmiWXI4e0/img.png&quot;&gt;&lt;img src=&quot;https://blog.kakaocdn.net/dn/5okgA/dJMb9hph3tY/EmHRmZsxn3LLRmmiWXI4e0/img.png&quot; srcset=&quot;https://img1.daumcdn.net/thumb/R1280x0/?scode=mtistory2&amp;fname=https%3A%2F%2Fblog.kakaocdn.net%2Fdn%2F5okgA%2FdJMb9hph3tY%2FEmHRmZsxn3LLRmmiWXI4e0%2Fimg.png&quot; onerror=&quot;this.onerror=null; this.src='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png'; this.srcset='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png';&quot; loading=&quot;lazy&quot; width=&quot;2480&quot; height=&quot;1568&quot; data-filename=&quot;고2-17번.png&quot; data-origin-width=&quot;2480&quot; data-origin-height=&quot;1568&quot;/&gt;&lt;/span&gt;&lt;/figure&gt;
&lt;/div&gt;
&lt;/div&gt;</description>
      <category>수학1- 문제풀이/수열</category>
      <author>수악중독</author>
      <guid isPermaLink="true">https://mathjk.tistory.com/6768</guid>
      <comments>https://mathjk.tistory.com/6768#entry6768comment</comments>
      <pubDate>Tue, 21 Oct 2025 01:23:56 +0900</pubDate>
    </item>
    <item>
      <title>삼각함수의 그래프_난이도 중 (2025년 10월 고2 18번)</title>
      <link>https://mathjk.tistory.com/6767</link>
      <description>&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;함수 $f(x) = \sin(x+a)$가 다음 조건을 만족시키도록 하는 $3\pi$보다 작은 모든 양수 $a$의 값의 합은?&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;div class=&quot;txc-textbox&quot; style=&quot;background-color: #dbe8fb; padding: 10px; border: 1px solid #dbe8fb;&quot;&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;닫힌구간 $[0, \; \pi]$에서 함수 $f(x)$의 최댓값과 최솟값을 각각 $M,\; m$이라 할 때,&amp;nbsp; $2|M|&amp;nbsp;=&amp;nbsp;|m|$&amp;nbsp;이다.&lt;/p&gt;
&lt;/div&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;① $\dfrac{25}{6}\pi$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;② $\dfrac{13}{3}\pi$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;③ $\dfrac{9}{2}\pi$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;④ $\dfrac{14}{3}\pi$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;⑤ $\dfrac{29}{6}\pi$&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;div data-ke-type=&quot;moreLess&quot; data-text-more=&quot;풀이보기&quot; data-text-less=&quot;풀이닫기&quot;&gt;&lt;a class=&quot;btn-toggle-moreless&quot;&gt;더보기&lt;/a&gt;
&lt;div class=&quot;moreless-content&quot;&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&lt;span style=&quot;color: #ee2323;&quot;&gt;&lt;b&gt;정답 ⑤&lt;/b&gt;&lt;/span&gt;&lt;/p&gt;
&lt;figure class=&quot;imageblock alignCenter&quot; data-ke-mobileStyle=&quot;widthOrigin&quot; data-filename=&quot;고2-18번.png&quot; data-origin-width=&quot;2480&quot; data-origin-height=&quot;2112&quot;&gt;&lt;span data-url=&quot;https://blog.kakaocdn.net/dn/NbaAF/dJMb9YpIgkh/0rrCan4jaKwkv46ts8c1Ek/img.png&quot; data-phocus=&quot;https://blog.kakaocdn.net/dn/NbaAF/dJMb9YpIgkh/0rrCan4jaKwkv46ts8c1Ek/img.png&quot;&gt;&lt;img src=&quot;https://blog.kakaocdn.net/dn/NbaAF/dJMb9YpIgkh/0rrCan4jaKwkv46ts8c1Ek/img.png&quot; srcset=&quot;https://img1.daumcdn.net/thumb/R1280x0/?scode=mtistory2&amp;fname=https%3A%2F%2Fblog.kakaocdn.net%2Fdn%2FNbaAF%2FdJMb9YpIgkh%2F0rrCan4jaKwkv46ts8c1Ek%2Fimg.png&quot; onerror=&quot;this.onerror=null; this.src='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png'; this.srcset='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png';&quot; loading=&quot;lazy&quot; width=&quot;2480&quot; height=&quot;2112&quot; data-filename=&quot;고2-18번.png&quot; data-origin-width=&quot;2480&quot; data-origin-height=&quot;2112&quot;/&gt;&lt;/span&gt;&lt;/figure&gt;
&lt;/div&gt;
&lt;/div&gt;</description>
      <category>수학1- 문제풀이/삼각함수</category>
      <author>수악중독</author>
      <guid isPermaLink="true">https://mathjk.tistory.com/6767</guid>
      <comments>https://mathjk.tistory.com/6767#entry6767comment</comments>
      <pubDate>Tue, 21 Oct 2025 01:21:07 +0900</pubDate>
    </item>
    <item>
      <title>지수함수의 그래프_난이도 중 (2025년 10월 고2 19번)</title>
      <link>https://mathjk.tistory.com/6766</link>
      <description>&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;그림과 같이 기울기가 $1$인 직선 $l$이 곡선 $y = 2^x$과 서로 다른 두 점 $\mathrm{A, \;B}$에서 만나고, 곡선 $y = 2^{x-1} + 1$과 서로 다른 두 점 $\mathrm{C,\; D}$에서 만난다. 점 $\mathrm{B}$가 선분 $\mathrm{AD}$를 $3:1$로 내분할 때, 점 $\mathrm{B}$의 $x$좌표는? (단, 점 $\mathrm{B}$의 $x$좌표는 점 $\mathrm{A}$의 $x$좌표보다 크고, 점 $\mathrm{D}$의 $x$좌표는 점 $\mathrm{C}$의 $x$좌표보다 크다.)&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;&lt;figure class=&quot;imageblock alignCenter&quot; data-ke-mobileStyle=&quot;widthOrigin&quot; data-filename=&quot;Screenshot 2025-10-20 at 12.11.04.png&quot; data-origin-width=&quot;1046&quot; data-origin-height=&quot;1034&quot;&gt;&lt;span data-url=&quot;https://blog.kakaocdn.net/dn/7slkY/dJMb88lz0Kw/CM6CUM8eV8VtpBMn0qxkEK/img.png&quot; data-phocus=&quot;https://blog.kakaocdn.net/dn/7slkY/dJMb88lz0Kw/CM6CUM8eV8VtpBMn0qxkEK/img.png&quot;&gt;&lt;img src=&quot;https://blog.kakaocdn.net/dn/7slkY/dJMb88lz0Kw/CM6CUM8eV8VtpBMn0qxkEK/img.png&quot; srcset=&quot;https://img1.daumcdn.net/thumb/R1280x0/?scode=mtistory2&amp;fname=https%3A%2F%2Fblog.kakaocdn.net%2Fdn%2F7slkY%2FdJMb88lz0Kw%2FCM6CUM8eV8VtpBMn0qxkEK%2Fimg.png&quot; onerror=&quot;this.onerror=null; this.src='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png'; this.srcset='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png';&quot; loading=&quot;lazy&quot; width=&quot;426&quot; height=&quot;421&quot; data-filename=&quot;Screenshot 2025-10-20 at 12.11.04.png&quot; data-origin-width=&quot;1046&quot; data-origin-height=&quot;1034&quot;/&gt;&lt;/span&gt;&lt;/figure&gt;
&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&lt;br /&gt;① $\log_2 \dfrac{23}{7}$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;② $\log_2 \dfrac{24}{7}$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;③ $\log_2 \dfrac{25}{7}$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;④ $\log_2 \dfrac{26}{7}$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;⑤ $\log_2 \dfrac{27}{7}$&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;div data-ke-type=&quot;moreLess&quot; data-text-more=&quot;풀이보기&quot; data-text-less=&quot;풀이닫기&quot;&gt;&lt;a class=&quot;btn-toggle-moreless&quot;&gt;더보기&lt;/a&gt;
&lt;div class=&quot;moreless-content&quot;&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&lt;span style=&quot;color: #ee2323;&quot;&gt;&lt;b&gt;정답 ②&lt;/b&gt;&lt;/span&gt;&lt;/p&gt;
&lt;figure class=&quot;imageblock alignCenter&quot; data-ke-mobileStyle=&quot;widthOrigin&quot; data-filename=&quot;고2-19번.png&quot; data-origin-width=&quot;2480&quot; data-origin-height=&quot;842&quot;&gt;&lt;span data-url=&quot;https://blog.kakaocdn.net/dn/duW5Qo/dJMb9VzKZe4/Od0Uq6KbvIjFxKvTzjgJk0/img.png&quot; data-phocus=&quot;https://blog.kakaocdn.net/dn/duW5Qo/dJMb9VzKZe4/Od0Uq6KbvIjFxKvTzjgJk0/img.png&quot;&gt;&lt;img src=&quot;https://blog.kakaocdn.net/dn/duW5Qo/dJMb9VzKZe4/Od0Uq6KbvIjFxKvTzjgJk0/img.png&quot; srcset=&quot;https://img1.daumcdn.net/thumb/R1280x0/?scode=mtistory2&amp;fname=https%3A%2F%2Fblog.kakaocdn.net%2Fdn%2FduW5Qo%2FdJMb9VzKZe4%2FOd0Uq6KbvIjFxKvTzjgJk0%2Fimg.png&quot; onerror=&quot;this.onerror=null; this.src='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png'; this.srcset='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png';&quot; loading=&quot;lazy&quot; width=&quot;2480&quot; height=&quot;842&quot; data-filename=&quot;고2-19번.png&quot; data-origin-width=&quot;2480&quot; data-origin-height=&quot;842&quot;/&gt;&lt;/span&gt;&lt;/figure&gt;
&lt;/div&gt;
&lt;/div&gt;</description>
      <category>수학1- 문제풀이/지수함수와 로그함수</category>
      <author>수악중독</author>
      <guid isPermaLink="true">https://mathjk.tistory.com/6766</guid>
      <comments>https://mathjk.tistory.com/6766#entry6766comment</comments>
      <pubDate>Tue, 21 Oct 2025 01:16:19 +0900</pubDate>
    </item>
    <item>
      <title>등비수열의 일반항_난이도 중 (2025년 10월 고2 20번)</title>
      <link>https://mathjk.tistory.com/6765</link>
      <description>&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;등비수열 $\lbrace a_n \rbrace$이 다음 조건을 만족시킬 때, $a_{10}$의 값은?&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;div class=&quot;txc-textbox&quot; style=&quot;background-color: #dbe8fb; padding: 10px; border: 1px solid #dbe8fb;&quot;&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;(가) $2$ 이상의 모든 자연수 $n$에 대하여&amp;nbsp; $$a_n &amp;gt; a_1, \quad a_n = (a_4 + a_5 - 1) \times a_{n-1}$$ 이다.&amp;nbsp;&amp;nbsp;&lt;br /&gt;(나) $\displaystyle\sum_{n=1}^{3} a_n = \dfrac{6}{a_1 - a_2}$&amp;nbsp;&amp;nbsp;&lt;/p&gt;
&lt;/div&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&lt;br /&gt;① $\dfrac{1}{12}$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;② $\dfrac{1}{6}$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;③ $\dfrac{1}{4}$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;④ $\dfrac{1}{3}$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;⑤ $\dfrac{5}{12}$&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;div data-ke-type=&quot;moreLess&quot; data-text-more=&quot;풀이보기&quot; data-text-less=&quot;풀이닫기&quot;&gt;&lt;a class=&quot;btn-toggle-moreless&quot;&gt;더보기&lt;/a&gt;
&lt;div class=&quot;moreless-content&quot;&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&lt;span style=&quot;color: #ee2323;&quot;&gt;&lt;b&gt;정답 ③&lt;/b&gt;&lt;/span&gt;&lt;/p&gt;
&lt;figure class=&quot;imageblock alignCenter&quot; data-ke-mobileStyle=&quot;widthOrigin&quot; data-filename=&quot;고2-20번.png&quot; data-origin-width=&quot;2473&quot; data-origin-height=&quot;1994&quot;&gt;&lt;span data-url=&quot;https://blog.kakaocdn.net/dn/bAnNac/dJMb9hW7ZP1/84tHcxz5jfzRZ4wt2grIXk/img.png&quot; data-phocus=&quot;https://blog.kakaocdn.net/dn/bAnNac/dJMb9hW7ZP1/84tHcxz5jfzRZ4wt2grIXk/img.png&quot;&gt;&lt;img src=&quot;https://blog.kakaocdn.net/dn/bAnNac/dJMb9hW7ZP1/84tHcxz5jfzRZ4wt2grIXk/img.png&quot; srcset=&quot;https://img1.daumcdn.net/thumb/R1280x0/?scode=mtistory2&amp;fname=https%3A%2F%2Fblog.kakaocdn.net%2Fdn%2FbAnNac%2FdJMb9hW7ZP1%2F84tHcxz5jfzRZ4wt2grIXk%2Fimg.png&quot; onerror=&quot;this.onerror=null; this.src='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png'; this.srcset='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png';&quot; loading=&quot;lazy&quot; width=&quot;2473&quot; height=&quot;1994&quot; data-filename=&quot;고2-20번.png&quot; data-origin-width=&quot;2473&quot; data-origin-height=&quot;1994&quot;/&gt;&lt;/span&gt;&lt;/figure&gt;
&lt;/div&gt;
&lt;/div&gt;</description>
      <category>수학1- 문제풀이/수열</category>
      <author>수악중독</author>
      <guid isPermaLink="true">https://mathjk.tistory.com/6765</guid>
      <comments>https://mathjk.tistory.com/6765#entry6765comment</comments>
      <pubDate>Tue, 21 Oct 2025 01:07:21 +0900</pubDate>
    </item>
    <item>
      <title>지수함수의 그래프 &amp;amp; 로그부등식_난이도 중상 (2025년 10월 고2 21번)</title>
      <link>https://mathjk.tistory.com/6764</link>
      <description>&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;함수&amp;nbsp; $$f(x)=\begin{cases} -2^{x + 3} + a &amp;amp; (x&amp;lt;0) \\[3pt] 2^{ - x + 6} + a - 12 &amp;amp; (x \ge 0)\end{cases}$$이 다음 조건을 만족시키도록 하는 모든 정수 $a$의 값의 합은?&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;div class=&quot;txc-textbox&quot; style=&quot;background-color: #dbe8fb; padding: 10px; border: 1px solid #dbe8fb;&quot;&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;$x$에 대한 방정식 $f(x) \times f(x-k)=0$의 서로 다른 실근의 개수가 $3$이 되도록 하는&amp;nbsp;&amp;nbsp;$4$ 이하의 양수 $k$가 존재한다.&amp;nbsp;&amp;nbsp;&lt;/p&gt;
&lt;/div&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&lt;br /&gt;① $16$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;② $19$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;③ $22$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;④ $25$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;⑤ $28$&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;div data-ke-type=&quot;moreLess&quot; data-text-more=&quot;풀이보기&quot; data-text-less=&quot;풀이닫기&quot;&gt;&lt;a class=&quot;btn-toggle-moreless&quot;&gt;더보기&lt;/a&gt;
&lt;div class=&quot;moreless-content&quot;&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&lt;span style=&quot;color: #ee2323;&quot;&gt;&lt;b&gt;정답 ③&lt;/b&gt;&lt;/span&gt;&lt;/p&gt;
&lt;figure class=&quot;imageblock alignCenter&quot; data-ke-mobileStyle=&quot;widthOrigin&quot; data-filename=&quot;chap1-15-5.png&quot; data-origin-width=&quot;1516&quot; data-origin-height=&quot;1918&quot;&gt;&lt;span data-url=&quot;https://blog.kakaocdn.net/dn/cdMwCZ/dJMcaioB9vv/SSf5zCeq0mVnFcIYssHK6k/img.png&quot; data-phocus=&quot;https://blog.kakaocdn.net/dn/cdMwCZ/dJMcaioB9vv/SSf5zCeq0mVnFcIYssHK6k/img.png&quot;&gt;&lt;img src=&quot;https://blog.kakaocdn.net/dn/cdMwCZ/dJMcaioB9vv/SSf5zCeq0mVnFcIYssHK6k/img.png&quot; srcset=&quot;https://img1.daumcdn.net/thumb/R1280x0/?scode=mtistory2&amp;fname=https%3A%2F%2Fblog.kakaocdn.net%2Fdn%2FcdMwCZ%2FdJMcaioB9vv%2FSSf5zCeq0mVnFcIYssHK6k%2Fimg.png&quot; onerror=&quot;this.onerror=null; this.src='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png'; this.srcset='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png';&quot; loading=&quot;lazy&quot; width=&quot;1516&quot; height=&quot;1918&quot; data-filename=&quot;chap1-15-5.png&quot; data-origin-width=&quot;1516&quot; data-origin-height=&quot;1918&quot;/&gt;&lt;/span&gt;&lt;/figure&gt;
&lt;/div&gt;
&lt;/div&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;</description>
      <category>수학1- 문제풀이/지수함수와 로그함수</category>
      <author>수악중독</author>
      <guid isPermaLink="true">https://mathjk.tistory.com/6764</guid>
      <comments>https://mathjk.tistory.com/6764#entry6764comment</comments>
      <pubDate>Mon, 20 Oct 2025 00:21:10 +0900</pubDate>
    </item>
    <item>
      <title>좌극한과 우극한_난이도 중하 (2025년 10월 고2 26번)</title>
      <link>https://mathjk.tistory.com/6763</link>
      <description>&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;두 상수 $a$, $k$에 대하여 함수 $f(x) = a|\!x-2\!|$가&amp;nbsp;&amp;nbsp;$$\displaystyle \lim_{x \to k+} \dfrac{f(x)-f(k)}{x-k} - \lim_{x \to k-} \dfrac{f(x)-f(k)}{x-k} = 6$$ 을&amp;nbsp;만족시킬&amp;nbsp;때,&amp;nbsp;$f(a+k)$의&amp;nbsp;값을&amp;nbsp;구하시오.&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;div data-ke-type=&quot;moreLess&quot; data-text-more=&quot;풀이보기&quot; data-text-less=&quot;풀이닫기&quot;&gt;&lt;a class=&quot;btn-toggle-moreless&quot;&gt;더보기&lt;/a&gt;
&lt;div class=&quot;moreless-content&quot;&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&lt;span style=&quot;color: #ee2323;&quot;&gt;&lt;b&gt;정답 $9$&lt;/b&gt;&lt;/span&gt;&lt;/p&gt;
&lt;figure class=&quot;imageblock alignCenter&quot; data-ke-mobileStyle=&quot;widthOrigin&quot; data-filename=&quot;고2-26번.png&quot; data-origin-width=&quot;2480&quot; data-origin-height=&quot;1416&quot;&gt;&lt;span data-url=&quot;https://blog.kakaocdn.net/dn/TT8Kx/dJMb9V7ACBl/0JGZbXSWqw5cJIJCp5GeUk/img.png&quot; data-phocus=&quot;https://blog.kakaocdn.net/dn/TT8Kx/dJMb9V7ACBl/0JGZbXSWqw5cJIJCp5GeUk/img.png&quot;&gt;&lt;img src=&quot;https://blog.kakaocdn.net/dn/TT8Kx/dJMb9V7ACBl/0JGZbXSWqw5cJIJCp5GeUk/img.png&quot; srcset=&quot;https://img1.daumcdn.net/thumb/R1280x0/?scode=mtistory2&amp;fname=https%3A%2F%2Fblog.kakaocdn.net%2Fdn%2FTT8Kx%2FdJMb9V7ACBl%2F0JGZbXSWqw5cJIJCp5GeUk%2Fimg.png&quot; onerror=&quot;this.onerror=null; this.src='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png'; this.srcset='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png';&quot; loading=&quot;lazy&quot; width=&quot;2480&quot; height=&quot;1416&quot; data-filename=&quot;고2-26번.png&quot; data-origin-width=&quot;2480&quot; data-origin-height=&quot;1416&quot;/&gt;&lt;/span&gt;&lt;/figure&gt;
&lt;/div&gt;
&lt;/div&gt;</description>
      <category>수학2 - 문제풀이/함수의 극한과 연속</category>
      <author>수악중독</author>
      <guid isPermaLink="true">https://mathjk.tistory.com/6763</guid>
      <comments>https://mathjk.tistory.com/6763#entry6763comment</comments>
      <pubDate>Mon, 20 Oct 2025 00:17:26 +0900</pubDate>
    </item>
    <item>
      <title>사인법칙&amp;amp;코사인법칙_난이도 중 (2025년 10월 고2 27번)</title>
      <link>https://mathjk.tistory.com/6762</link>
      <description>&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;$\overline{\mathrm{AB}} = 6$인 삼각형 $\mathrm{ABC}$에 대하여 $$2\sin \mathrm{A} = \sin \mathrm{B}, \quad \cos \mathrm{C} = \dfrac{4}{5}$$ 일 때, 삼각형 $\mathrm{ABC}$의 넓이를 구하시오.&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;div data-ke-type=&quot;moreLess&quot; data-text-more=&quot;풀이보기&quot; data-text-less=&quot;풀이닫기&quot;&gt;&lt;a class=&quot;btn-toggle-moreless&quot;&gt;더보기&lt;/a&gt;
&lt;div class=&quot;moreless-content&quot;&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&lt;span style=&quot;color: #ee2323;&quot;&gt;&lt;b&gt;정답 $12$&lt;/b&gt;&lt;/span&gt;&lt;/p&gt;
&lt;figure class=&quot;imageblock alignCenter&quot; data-ke-mobileStyle=&quot;widthOrigin&quot; data-filename=&quot;고2-27번.png&quot; data-origin-width=&quot;2476&quot; data-origin-height=&quot;946&quot;&gt;&lt;span data-url=&quot;https://blog.kakaocdn.net/dn/bY50xj/dJMb9VzKNux/NP4UTuRb3flIfG8gyyPhAK/img.png&quot; data-phocus=&quot;https://blog.kakaocdn.net/dn/bY50xj/dJMb9VzKNux/NP4UTuRb3flIfG8gyyPhAK/img.png&quot;&gt;&lt;img src=&quot;https://blog.kakaocdn.net/dn/bY50xj/dJMb9VzKNux/NP4UTuRb3flIfG8gyyPhAK/img.png&quot; srcset=&quot;https://img1.daumcdn.net/thumb/R1280x0/?scode=mtistory2&amp;fname=https%3A%2F%2Fblog.kakaocdn.net%2Fdn%2FbY50xj%2FdJMb9VzKNux%2FNP4UTuRb3flIfG8gyyPhAK%2Fimg.png&quot; onerror=&quot;this.onerror=null; this.src='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png'; this.srcset='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png';&quot; loading=&quot;lazy&quot; width=&quot;2476&quot; height=&quot;946&quot; data-filename=&quot;고2-27번.png&quot; data-origin-width=&quot;2476&quot; data-origin-height=&quot;946&quot;/&gt;&lt;/span&gt;&lt;/figure&gt;
&lt;/div&gt;
&lt;/div&gt;</description>
      <category>수학1- 문제풀이/삼각함수</category>
      <author>수악중독</author>
      <guid isPermaLink="true">https://mathjk.tistory.com/6762</guid>
      <comments>https://mathjk.tistory.com/6762#entry6762comment</comments>
      <pubDate>Mon, 20 Oct 2025 00:15:13 +0900</pubDate>
    </item>
    <item>
      <title>함수의 연속과 불연속&amp;amp;사잇값 정리_난이도 중상 (2025년 10월 고2 28번)</title>
      <link>https://mathjk.tistory.com/6761</link>
      <description>&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;닫힌구간 $[0, \;2]$에서 정의된 함수 $f(x)$가 다음 조건을 만족시킬 때, $\dfrac{f(0)}{f(2)}$의 값을 구하시오.&amp;nbsp; &amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;div class=&quot;txc-textbox&quot; style=&quot;background-color: #dbe8fb; padding: 10px; border: 1px solid #dbe8fb;&quot;&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;(가)&amp;nbsp;함수&amp;nbsp;$f(x)$는&amp;nbsp;$x=1$에서만&amp;nbsp;불연속이고,&amp;nbsp;$\displaystyle\lim_{x&amp;nbsp;\to&amp;nbsp;1}&amp;nbsp;f(x)&amp;nbsp;=&amp;nbsp;3f(2)$이다.&amp;nbsp;&amp;nbsp;&lt;br /&gt;(나) $0 \le x \le 2$인 모든 실수 $x$에 대하여 $f(x) \ne 2$이고, $f(0) + f(2) = 4$이다.&lt;/p&gt;
&lt;/div&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;div data-ke-type=&quot;moreLess&quot; data-text-more=&quot;풀이보기&quot; data-text-less=&quot;풀이닫기&quot;&gt;&lt;a class=&quot;btn-toggle-moreless&quot;&gt;더보기&lt;/a&gt;
&lt;div class=&quot;moreless-content&quot;&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&lt;span style=&quot;color: #ee2323;&quot;&gt;&lt;b&gt;정답 $5$&lt;/b&gt;&lt;/span&gt;&lt;/p&gt;
&lt;figure class=&quot;imageblock alignCenter&quot; data-ke-mobileStyle=&quot;widthOrigin&quot; data-filename=&quot;고2-28번.png&quot; data-origin-width=&quot;2476&quot; data-origin-height=&quot;1089&quot;&gt;&lt;span data-url=&quot;https://blog.kakaocdn.net/dn/bEqfvk/dJMb9P0GtYk/3n6hamN4jEtGVkqlUtjhq1/img.png&quot; data-phocus=&quot;https://blog.kakaocdn.net/dn/bEqfvk/dJMb9P0GtYk/3n6hamN4jEtGVkqlUtjhq1/img.png&quot;&gt;&lt;img src=&quot;https://blog.kakaocdn.net/dn/bEqfvk/dJMb9P0GtYk/3n6hamN4jEtGVkqlUtjhq1/img.png&quot; srcset=&quot;https://img1.daumcdn.net/thumb/R1280x0/?scode=mtistory2&amp;fname=https%3A%2F%2Fblog.kakaocdn.net%2Fdn%2FbEqfvk%2FdJMb9P0GtYk%2F3n6hamN4jEtGVkqlUtjhq1%2Fimg.png&quot; onerror=&quot;this.onerror=null; this.src='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png'; this.srcset='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png';&quot; loading=&quot;lazy&quot; width=&quot;2476&quot; height=&quot;1089&quot; data-filename=&quot;고2-28번.png&quot; data-origin-width=&quot;2476&quot; data-origin-height=&quot;1089&quot;/&gt;&lt;/span&gt;&lt;/figure&gt;
&lt;/div&gt;
&lt;/div&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;</description>
      <category>수학2 - 문제풀이/함수의 극한과 연속</category>
      <author>수악중독</author>
      <guid isPermaLink="true">https://mathjk.tistory.com/6761</guid>
      <comments>https://mathjk.tistory.com/6761#entry6761comment</comments>
      <pubDate>Mon, 20 Oct 2025 00:11:51 +0900</pubDate>
    </item>
    <item>
      <title>수열의 귀납적 정의_난이도 중 (2025년 10월 고2 29번)</title>
      <link>https://mathjk.tistory.com/6760</link>
      <description>&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;다음 조건을 만족시키는 수열 $\lbrace a_n \rbrace$에 대하여&amp;nbsp;&amp;nbsp;$12(a_{14}+a_{15})$의 값을 구하시오.&amp;nbsp; &amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;div class=&quot;txc-textbox&quot; style=&quot;background-color: #dbe8fb; padding: 10px; border: 1px solid #dbe8fb;&quot;&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;(가) 모든 자연수 $n$에 대하여&amp;nbsp;&amp;nbsp;$$a_{n+1} =\begin{cases}\dfrac{1}{a_n} - 1 &amp;amp; (a_n &amp;gt; 0) \\[5pt]- a_n &amp;amp; (a_n \le 0)\end{cases}$$&amp;nbsp;&amp;nbsp;&lt;br /&gt;(나) $a_1 &amp;gt; 6$이고, $a_1 + a_5 + a_9 + a_{13} = 13$이다.&lt;/p&gt;
&lt;/div&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;div data-ke-type=&quot;moreLess&quot; data-text-more=&quot;풀이보기&quot; data-text-less=&quot;풀이닫기&quot;&gt;&lt;a class=&quot;btn-toggle-moreless&quot;&gt;더보기&lt;/a&gt;
&lt;div class=&quot;moreless-content&quot;&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&lt;span style=&quot;color: #ee2323;&quot;&gt;&lt;b&gt;정답 $28$&lt;/b&gt;&lt;/span&gt;&lt;/p&gt;
&lt;figure class=&quot;imageblock alignCenter&quot; data-ke-mobileStyle=&quot;widthOrigin&quot; data-filename=&quot;고2-29번.png&quot; data-origin-width=&quot;2477&quot; data-origin-height=&quot;1074&quot;&gt;&lt;span data-url=&quot;https://blog.kakaocdn.net/dn/c0EL1o/dJMb9LKKkna/SfNF9ZR6mN4eEOub1Pq0lK/img.png&quot; data-phocus=&quot;https://blog.kakaocdn.net/dn/c0EL1o/dJMb9LKKkna/SfNF9ZR6mN4eEOub1Pq0lK/img.png&quot;&gt;&lt;img src=&quot;https://blog.kakaocdn.net/dn/c0EL1o/dJMb9LKKkna/SfNF9ZR6mN4eEOub1Pq0lK/img.png&quot; srcset=&quot;https://img1.daumcdn.net/thumb/R1280x0/?scode=mtistory2&amp;fname=https%3A%2F%2Fblog.kakaocdn.net%2Fdn%2Fc0EL1o%2FdJMb9LKKkna%2FSfNF9ZR6mN4eEOub1Pq0lK%2Fimg.png&quot; onerror=&quot;this.onerror=null; this.src='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png'; this.srcset='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png';&quot; loading=&quot;lazy&quot; width=&quot;2477&quot; height=&quot;1074&quot; data-filename=&quot;고2-29번.png&quot; data-origin-width=&quot;2477&quot; data-origin-height=&quot;1074&quot;/&gt;&lt;/span&gt;&lt;/figure&gt;
&lt;/div&gt;
&lt;/div&gt;</description>
      <category>수학1- 문제풀이/수열</category>
      <author>수악중독</author>
      <guid isPermaLink="true">https://mathjk.tistory.com/6760</guid>
      <comments>https://mathjk.tistory.com/6760#entry6760comment</comments>
      <pubDate>Mon, 20 Oct 2025 00:08:35 +0900</pubDate>
    </item>
    <item>
      <title>함수의 연속_연속의 조건_난이도 상 (2025년 10월 고2 30번)</title>
      <link>https://mathjk.tistory.com/6759</link>
      <description>&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;세 양수 $a, \; b, \; c$에 대하여 함수 $$f(x)=\begin{cases} (x+4)(x+a) &amp;amp; (x&amp;lt;-4, \; -4&amp;lt;x&amp;lt;0) \\&amp;nbsp; b &amp;amp; (x=-4) \\ -x^2+6x+c &amp;amp; (x \ge 0)\end{cases}$$이 있다.&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;상수 $k \; (k&amp;gt;4)$와 실수 $t$에 대햐여 함수 $f(x)$에서 $x$의 값이 $t$에서 $t+k$까지 변할 때의 평균변화율을 $g(t)$라 하고, $f(t) \times g(t)$의 값을 $h(t)$라 하자.&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;두 함수 $f(x), \; h(t)$가 다음 조건을 만족시킨다.&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;div class=&quot;txc-textbox&quot; style=&quot;background-color: #dbe8fb; padding: 10px; border: 1px solid #dbe8fb;&quot;&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;(가) 함수 $h(t)$가 실수 전체의 집합에서 연속이다.&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;(나) $f(k)=b$&lt;/p&gt;
&lt;/div&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;$f(c-a-b)$의 값을 구하시오.&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;div data-ke-type=&quot;moreLess&quot; data-text-more=&quot;풀이보기&quot; data-text-less=&quot;풀이닫기&quot;&gt;&lt;a class=&quot;btn-toggle-moreless&quot;&gt;더보기&lt;/a&gt;
&lt;div class=&quot;moreless-content&quot;&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&lt;span style=&quot;color: #ee2323;&quot;&gt;&lt;b&gt;정답 $50$&lt;/b&gt;&lt;/span&gt;&lt;/p&gt;
&lt;figure class=&quot;imageblock alignCenter&quot; data-ke-mobileStyle=&quot;widthOrigin&quot; data-filename=&quot;고2-30번-1.png&quot; data-origin-width=&quot;2473&quot; data-origin-height=&quot;3278&quot;&gt;&lt;span data-url=&quot;https://blog.kakaocdn.net/dn/6R54K/dJMb84cpeNg/T7lddXTZe5uvnpQinPzhX0/img.png&quot; data-phocus=&quot;https://blog.kakaocdn.net/dn/6R54K/dJMb84cpeNg/T7lddXTZe5uvnpQinPzhX0/img.png&quot;&gt;&lt;img src=&quot;https://blog.kakaocdn.net/dn/6R54K/dJMb84cpeNg/T7lddXTZe5uvnpQinPzhX0/img.png&quot; srcset=&quot;https://img1.daumcdn.net/thumb/R1280x0/?scode=mtistory2&amp;fname=https%3A%2F%2Fblog.kakaocdn.net%2Fdn%2F6R54K%2FdJMb84cpeNg%2FT7lddXTZe5uvnpQinPzhX0%2Fimg.png&quot; onerror=&quot;this.onerror=null; this.src='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png'; this.srcset='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png';&quot; loading=&quot;lazy&quot; width=&quot;2473&quot; height=&quot;3278&quot; data-filename=&quot;고2-30번-1.png&quot; data-origin-width=&quot;2473&quot; data-origin-height=&quot;3278&quot;/&gt;&lt;/span&gt;&lt;/figure&gt;
&lt;figure class=&quot;imageblock alignCenter&quot; data-ke-mobileStyle=&quot;widthOrigin&quot; data-filename=&quot;고2-30번-2.png&quot; data-origin-width=&quot;2473&quot; data-origin-height=&quot;1795&quot;&gt;&lt;span data-url=&quot;https://blog.kakaocdn.net/dn/5ywjE/dJMb9MCSEHF/dmKHL8xM40FtouwtZkhMmK/img.png&quot; data-phocus=&quot;https://blog.kakaocdn.net/dn/5ywjE/dJMb9MCSEHF/dmKHL8xM40FtouwtZkhMmK/img.png&quot;&gt;&lt;img src=&quot;https://blog.kakaocdn.net/dn/5ywjE/dJMb9MCSEHF/dmKHL8xM40FtouwtZkhMmK/img.png&quot; srcset=&quot;https://img1.daumcdn.net/thumb/R1280x0/?scode=mtistory2&amp;fname=https%3A%2F%2Fblog.kakaocdn.net%2Fdn%2F5ywjE%2FdJMb9MCSEHF%2FdmKHL8xM40FtouwtZkhMmK%2Fimg.png&quot; onerror=&quot;this.onerror=null; this.src='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png'; this.srcset='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png';&quot; loading=&quot;lazy&quot; width=&quot;2473&quot; height=&quot;1795&quot; data-filename=&quot;고2-30번-2.png&quot; data-origin-width=&quot;2473&quot; data-origin-height=&quot;1795&quot;/&gt;&lt;/span&gt;&lt;/figure&gt;
&lt;/div&gt;
&lt;/div&gt;</description>
      <category>수학2 - 문제풀이/미분</category>
      <author>수악중독</author>
      <guid isPermaLink="true">https://mathjk.tistory.com/6759</guid>
      <comments>https://mathjk.tistory.com/6759#entry6759comment</comments>
      <pubDate>Sun, 19 Oct 2025 00:48:49 +0900</pubDate>
    </item>
    <item>
      <title>속도 가속도와 미분_난이도 하 (2025년 10월 고3 9번)</title>
      <link>https://mathjk.tistory.com/6758</link>
      <description>&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;수직선 위를 움직이는 두 점 $\mathrm{P, \; Q}$의 시각 $t \; (t \ge 0)$에서의 위치가 각각 $$x_1 = -t^3+7t^2-10t, \quad x_2=t^2+2t$$이다. 두 점 $\mathrm{P, \; Q}$의 속도가 같아지는 순간 두 점 $\mathrm{P, \; Q}$ 사이의 거리는?&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&lt;br /&gt;① $6$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;② $7$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;③ $8$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;④ $9$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;⑤ $10$&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;div data-ke-type=&quot;moreLess&quot; data-text-more=&quot;풀이보기&quot; data-text-less=&quot;풀이닫기&quot;&gt;&lt;a class=&quot;btn-toggle-moreless&quot;&gt;더보기&lt;/a&gt;
&lt;div class=&quot;moreless-content&quot;&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&lt;span style=&quot;color: #ee2323;&quot;&gt;&lt;b&gt;정답 ③&lt;/b&gt;&lt;/span&gt;&lt;/p&gt;
&lt;figure class=&quot;imageblock alignCenter&quot; data-ke-mobileStyle=&quot;widthOrigin&quot; data-filename=&quot;9번.jpeg&quot; data-origin-width=&quot;1542&quot; data-origin-height=&quot;613&quot;&gt;&lt;span data-url=&quot;https://blog.kakaocdn.net/dn/bCqvOC/dJMb9XRR1sa/6pGkBwLW4nXl7GK8BcjKH0/img.jpg&quot; data-phocus=&quot;https://blog.kakaocdn.net/dn/bCqvOC/dJMb9XRR1sa/6pGkBwLW4nXl7GK8BcjKH0/img.jpg&quot;&gt;&lt;img src=&quot;https://blog.kakaocdn.net/dn/bCqvOC/dJMb9XRR1sa/6pGkBwLW4nXl7GK8BcjKH0/img.jpg&quot; srcset=&quot;https://img1.daumcdn.net/thumb/R1280x0/?scode=mtistory2&amp;fname=https%3A%2F%2Fblog.kakaocdn.net%2Fdn%2FbCqvOC%2FdJMb9XRR1sa%2F6pGkBwLW4nXl7GK8BcjKH0%2Fimg.jpg&quot; onerror=&quot;this.onerror=null; this.src='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png'; this.srcset='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png';&quot; loading=&quot;lazy&quot; width=&quot;1542&quot; height=&quot;613&quot; data-filename=&quot;9번.jpeg&quot; data-origin-width=&quot;1542&quot; data-origin-height=&quot;613&quot;/&gt;&lt;/span&gt;&lt;/figure&gt;
&lt;/div&gt;
&lt;/div&gt;</description>
      <category>수학2 - 문제풀이/미분</category>
      <author>수악중독</author>
      <guid isPermaLink="true">https://mathjk.tistory.com/6758</guid>
      <comments>https://mathjk.tistory.com/6758#entry6758comment</comments>
      <pubDate>Sun, 19 Oct 2025 00:43:32 +0900</pubDate>
    </item>
    <item>
      <title>삼각함수의 그래프_난이도 중하 (2025년 10월 고3 10번)</title>
      <link>https://mathjk.tistory.com/6757</link>
      <description>&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;두 양수 $a, b$에 대하여 닫힌구간 $[0, \; 2a]$에서 정의된 함수 $$f(x) = 3\sin{\dfrac{\pi x}{a}} + b$$의 그래프가 $x$축과 오직 한 점 $(2,\; 0)$에서 만날 때, $a + b$의 값은?&amp;nbsp;&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;br /&gt;① $\dfrac{25}{6}$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;② $\dfrac{13}{3}$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;③ $\dfrac{9}{2}$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;④ $\dfrac{14}{3}$&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;⑤ $\dfrac{29}{6}$&lt;/p&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;
&lt;div data-ke-type=&quot;moreLess&quot; data-text-more=&quot;풀이보기&quot; data-text-less=&quot;풀이닫기&quot;&gt;&lt;a class=&quot;btn-toggle-moreless&quot;&gt;더보기&lt;/a&gt;
&lt;div class=&quot;moreless-content&quot;&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&lt;span style=&quot;color: #ee2323;&quot;&gt;&lt;b&gt;정답 ②&lt;/b&gt;&lt;/span&gt;&lt;/p&gt;
&lt;figure class=&quot;imageblock alignCenter&quot; data-ke-mobileStyle=&quot;widthOrigin&quot; data-filename=&quot;10번.jpeg&quot; data-origin-width=&quot;1545&quot; data-origin-height=&quot;577&quot;&gt;&lt;span data-url=&quot;https://blog.kakaocdn.net/dn/KYxYr/dJMb9O1LZYz/KOjobrAwUN9fDiwJ2W9mQ1/img.jpg&quot; data-phocus=&quot;https://blog.kakaocdn.net/dn/KYxYr/dJMb9O1LZYz/KOjobrAwUN9fDiwJ2W9mQ1/img.jpg&quot;&gt;&lt;img src=&quot;https://blog.kakaocdn.net/dn/KYxYr/dJMb9O1LZYz/KOjobrAwUN9fDiwJ2W9mQ1/img.jpg&quot; srcset=&quot;https://img1.daumcdn.net/thumb/R1280x0/?scode=mtistory2&amp;fname=https%3A%2F%2Fblog.kakaocdn.net%2Fdn%2FKYxYr%2FdJMb9O1LZYz%2FKOjobrAwUN9fDiwJ2W9mQ1%2Fimg.jpg&quot; onerror=&quot;this.onerror=null; this.src='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png'; this.srcset='//t1.daumcdn.net/tistory_admin/static/images/no-image-v1.png';&quot; loading=&quot;lazy&quot; width=&quot;1545&quot; height=&quot;577&quot; data-filename=&quot;10번.jpeg&quot; data-origin-width=&quot;1545&quot; data-origin-height=&quot;577&quot;/&gt;&lt;/span&gt;&lt;/figure&gt;
&lt;/div&gt;
&lt;/div&gt;
&lt;p data-ke-size=&quot;size16&quot;&gt;&amp;nbsp;&lt;/p&gt;</description>
      <category>수학1- 문제풀이/삼각함수</category>
      <author>수악중독</author>
      <guid isPermaLink="true">https://mathjk.tistory.com/6757</guid>
      <comments>https://mathjk.tistory.com/6757#entry6757comment</comments>
      <pubDate>Sun, 19 Oct 2025 00:40:39 +0900</pubDate>
    </item>
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